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DEATH BATTLE! Discussion Thread (2024–2025) (All-time Death Battle Spoilers Alert)

The_Unknown_Warrior1 said:
Honestly? I think that even Sonic is a victim of this sort of mentality, but I feel like it's in reverse as some people think that Sonic is meant to be some purely strong character without any sort of nuance or complexity to him. And as a Sonic fan, it sucks to see because like Goku, there's a lot of depth to him that has made him one of my favorite characters of all time.

I'm not the best when it comes to articulating my thoughts and feelings, but what I love about Sonic the Hedgehog is that he is a character that personifies the concept of freedom and is willing to oppose any sort of attempt of someone trying to enforce control or remove said freedom from others. My favorite example of this mentality is in Sonic and the Black Knight, where the villain's goal of that game is to create an eternal world where everyone in it is part of an endless cycle of rebirth and destruction due to the villain's fear of the inevitability of the end. But despite knowing that his actions would doom said world to one day coming to an end, Sonic puts a stop to their plans due to his love for freedom and imparts a message of living life to the fullest and as freely as possible while not being afraid of death.

There's plenty of other examples of that in the games and other pieces of media, especially in the IDW comics, but I absolutely love that Sonic is a character who is so dedicated to his ideals and beliefs that he's more than willing to be a bad guy if one's actions directly harm the freedom and happiness of others. It's why he's such a great character when written well, and it bugs the piss out of me that there's a vocal group of people who only talk about him because he "beats" Goku or whatever.
Click to expand...
Tbf, this happens more with fake Archie Sonic fans who never read an issue but overhype Archie Sonic to be the strongest character in fiction than Game Sonic.
 
AcidSilver said:
Bardock doesn’t survive his home planet exploding while Omni-Man does. He is clearly stronger than Fraudock.
Click to expand...
Yeah, and Bardock got killed easily by a galactic tyrant, while... uh... Despite his effort(Dragon Magic), Bardock only has one living son, while... uh... Viltrumites can generally invade a planet on their own, while... uh...
 
The_Unknown_Warrior1 said:
Honestly? I think that even Sonic is a victim of this sort of mentality, but I feel like it's in reverse as some people think that Sonic is meant to be some purely strong character without any sort of nuance or complexity to him. And as a Sonic fan, it sucks to see because like Goku, there's a lot of depth to him that has made him one of my favorite characters of all time.

I'm not the best when it comes to articulating my thoughts and feelings, but what I love about Sonic the Hedgehog is that he is a character that personifies the concept of freedom and is willing to oppose any sort of attempt of someone trying to enforce control or remove said freedom from others. My favorite example of this mentality is in Sonic and the Black Knight, where the villain's goal of that game is to create an eternal world where everyone in it is part of an endless cycle of rebirth and destruction due to the villain's fear of the inevitability of the end. But despite knowing that his actions would doom said world to one day coming to an end, Sonic puts a stop to their plans due to his love for freedom and imparts a message of living life to the fullest and as freely as possible while not being afraid of death.

There's plenty of other examples of that in the games and other pieces of media, especially in the IDW comics, but I absolutely love that Sonic is a character who is so dedicated to his ideals and beliefs that he's more than willing to be a bad guy if one's actions directly harm the freedom and happiness of others. It's why he's such a great character when written well, and it bugs the piss out of me that there's a vocal group of people who only talk about him because he "beats" Goku or whatever.
Click to expand...
Sonic got stuck with a fandom where Chris Chan is a member of it, RIP
 
Theuser789 said:
Tbf, this happens more with fake Archie Sonic fans who never read an issue but overhype Archie Sonic to be the strongest character in fiction than Game Sonic.
Click to expand...
True, but I think that Sonic Frontiers unearthed some people who only care about Sonic's strength because Frontiers embraced a more Shonen style to its story and gameplay.

XXBenShapiroXx said:
Sonic got stuck with a fandom where Chris Chan is a member of it, RIP
Click to expand...
No cap: as someone who has autism and wants to try a hand at streaming on Twitch and or YouTube...one of the things that keeps me away from doing that is becoming the next Chris Chan. It genuinely terrifies me, like looking into the abyss and having it blink back at you.
 
Joycap said:
I think he said in his Jin vs Ryu review (?) that he doesn't care too much who wins. My guess is he thinks result and research are mutually exclusive.
Click to expand...
Then why the hell do people watch him? His entire schtick is that he double checks the works. If you want DB worship, go to the subreddit.
 
The_Unknown_Warrior1 said:
No cap: as someone who has autism and wants to try a hand at streaming on Twitch and or YouTube...one of the things that keeps me away from doing that is becoming the next Chris Chan. It genuinely terrifies me, like looking into the abyss and having it blink back at you
Click to expand...
I can really relate to that, I'm the same way (autistic, I mean). Worrying about how you'll be perceived makes it really hard to put yourself out there, even when you're just trying to make a friend, let alone build an audience online.

If you do eventually start streaming, I sincerely wish you the best of luck 👏
 
BlackDarkness679 said:
I wonder if some of the researchers are even remotely looking at context for some feats or claims
Click to expand...
Personally they had to or they thought they could bullshit without folks checking which did not pass the sniff test
LegendariumOfLies said:
That is the biggest anti-feat in Invincible. Isn't surviving the surface of the sun a City-Block Level feat?
Click to expand...
Prob if ya go by calcs and shit
Its usual case of author thinking Sun>all but in case of invincible practically hard caps the verse
 
Tipper17 said:
Already mentioned
Honestly just bring up Thragg and Mark getting rekt by the sun's surface and that's all you need
Click to expand...
LegendariumOfLies said:
That is the biggest anti-feat in Invincible. Isn't surviving the surface of the sun a City-Block Level feat?
Click to expand...
Say it with me now, heat resistance

Like I'm not trying to defend the whole sun disk stuff, but come on, the surface of a yellow star is like, what, 5000 kelvin?
 
AnAverageUsername said:
Say it with me now, heat resistance

Like I'm not trying to defend the whole sun disk stuff, but come on, the surface of a yellow star is like, what, 5000 kelvin?
Click to expand...
Like yeah, why we acting like that stops a character from being above a tier, you could be almost any tier yet die by lack of oxygen or not resisting stuff like freezing to death
 
BlackDarkness679 said:
Thats hax and not AP, as heat is a weakness of viltrumites
Click to expand...
If they can go through the core of Viltrum that got hit by the infinity ray the heat weakness shit not selling me especially when kirkman probably never took it into account for the final fight

But let's say I agree ya got the issues with the Viltrum feat and the fact the infinity ray Pierce thru them like hot butter
 
The_Unknown_Warrior1 said:
No cap: as someone who has autism and wants to try a hand at streaming on Twitch and or YouTube...one of the things that keeps me away from doing that is becoming the next Chris Chan. It genuinely terrifies me, like looking into the abyss and having it blink back at you.
Click to expand...
Don't let your autism stop you, plenty of mentally ill people are successful at streaming. Also, plenty of people who do stupid things like crimes or morally wrong things still have a career.

Like, Chris Chan is a very unique case, he can't take criticism, he gets angry easy, he made videos raging at his haters, he made comics as a power fantasy where he killed and tortured all the people he disliked, and he ****** his own mother. Just don't commit crimes, do morally reprehensible stuff, **** your own mother or make comics where you kill and torture people you dislike and you'll be fine. I 100% believe you can become a successful streamer.
 
So I decided to make the calc according to VBW's rules on the Sun Disc's feat, as I said above.

I'll be using two methods:
  1. Lagrange Points
  2. Umbra size
Time to get this shitshow:

2O11iOB.png

  • Planet: 492 px
  • Sun Disc: 79 px
  • Star: 47 px
  • Panel's height: 285 px
  • Petal: 7.21 px
ui85iaE.png

  • Petal's height (imma call them like that): 87.05 px
  • Petal's thickness: 9.9 px
Now... the distance between the star and panel is easy to get, as the default assumption is our Sun unless specified otherwise.
  • (1391400 * 285) / [47 * 2tan(70/2 deg)] = 6024794.3 km
Huh... a lot.

The planet on the other hand is gonna be trickier. I'll use 3 assumptions: Our Earth, Viltrum (again, as VBW currently accepts it) and, as a generous high end, the densest planet ever according to Wikipedia.

I'll also use this very nice rule about scaling the actual diameter of the planet if it's too close to the POV.

Last, but not least, I'll use this calculator to get the distance between the planet and Solar Disc (which will be between M2 and L1).

Imma use steel here for the material, as it's pretty common for this space stuff, and the ends for destruction are fragmentation (208 j/cm3) and pulverization (1000 j/cm3).

Earth end

Part 1:
  • Actual planet's diameter = sqrt(1-(tan(35)x(492/285))^2/((tan(35)x(492/285))^2+1))x12742 = 9862.86584 km
  • Distance between POV and planet = (9862.86584 * 285) / [492 * 2tan(70/2 deg)] = 4079.68006 km
  • Distance between star and planet = 6024794.3 - 4079.68006 = 6020714.62 km, which is 0.0402459914 AU
  • The calculator tells me that the distance between Sun Disc and Planet = 60229.1 km
  • The angle for the Sun Disc = 2atan(tan(35deg)*(79/285)) = 0.383417968 Rad = 21.968231 Deg
  • Size = 23380 km
Part 2 (IMAGE 1):
  • Sun Disc: 79 px = 23380 km
  • 1 px = 295.9493671 km
  • Petal's height = 7.21 px = 2133.794937 km
Part 2 (IMAGE 2):
  • Petal's height = 87.05 px = 2133.794937 km
  • 1 px = 24.51229106 km
  • Petal's thickness (will use as a low end for the whole thickness) = 9.9 px = 242.6716815 km
Part 3:
  • Sun Disc's volume = pi * ((23380/2)^2) * 242.6716815 = 1.04183272e11 km^3 =1.04183272e26 cm^3
  • Sun Disc's mass = 1.04183272e26 * ((7.5+8)/2) = 8.07420358e26 g = 8.07420358e23 kg
  • Fragmentation = 208 * 1.04183272e26 = 2.167012058e28 Joules or 5.18 Exatons (Multi-Continent)
  • Pulverization = 1000 * 1.04183272e26 = 1.04183272e29 Joules or 24.9 Exatons (Multi-Continent+)
  • Assuming KE under 1 second because it's fun = 0.5 * 8.07420358e23 * (23380000/2)^2 = 5.51694586e37 Joules or 13.19 Ronnatons (Large Planet+)
Viltrum end

Part 1:
  • Actual planet's diameter = sqrt(1-(tan(35)x(492/285))^2/((tan(35)x(492/285))^2+1))x12742 = 9862.86584 km
  • Distance between POV and planet = (9862.86584 * 285) / [492 * 2tan(70/2 deg)] = 4079.68006 km
  • Distance between star and planet = 6024794.3 - 4079.68006 = 6020714.62 km, which is 0.0402459914 AU
  • The calculator tells me that the distance between Sun Disc and Planet = 64882.7 km (remember that VBW's mass for Viltrum is 7.4661961e+24 kg if you check the linked blog above)
  • The angle for the Sun Disc = 2atan(tan(35deg)*(79/285)) = 0.383417968 Rad = 21.968231 Deg
  • Size = 25187 km
Part 2 (IMAGE 1):
  • Sun Disc: 79 px = 25187 km
  • 1 px = 318.8227848 km
  • Petal's height = 7.21 px = 2298.712278 km
Part 2 (IMAGE 2):
  • Petal's height = 87.05 px = 2298.712278 km
  • 1 px = 26.40680388 km
  • Petal's thickness (will use as a low end for the whole thickness) = 9.9 px = 261.4273584 km
Part 3:
  • Sun Disc's volume = pi * ((25187/2)^2) * 261.4273584 = 1.30254819e11 km^3 = 1.30254819e26 cm^3
  • Sun Disc's mass = 1.30254819e26 * ((7.5+8)/2) = 1.009474847e27 g = 1.009474847e24 kg
  • Fragmentation = 208 * 1.30254819e26 = 2.709300235e28 Joules or 6.47 Exatons (Multi-Continent)
  • Pulverization = 1000 * 1.30254819e26 = 1.30254819e29 Joules or 31.13 Exatons (Moon)
  • Assuming KE under 1 second because it's fun = 0.5 * 1.009474847e24 * (25187000/2)^2 = 8.00494587e37 Joules or 19.13 Ronnatons (Brown Dwarf)
Densest planet end

Part 0 (to understand the size and mass of the thing):
  • The radius is 0.4 Jupiter's, which means that the diameter is 2 * 0.4 * 71492 = 57193.6 km
  • Mass is 330 Earths, or 330 * 5.9722e24 = 1.970826e27 kg
Part 1:
  • Actual planet's diameter = sqrt(1-(tan(35)x(492/285))^2/((tan(35)x(492/285))^2+1))x57193.6 = 44270.3503 km
  • Distance between POV and planet = (44270.3503 * 285) / [492 * 2tan(70/2 deg)] = 18312.0067 km
  • Distance between star and planet = 6024794.3 - 18312.0067 = 6006482.293 km, which is 0.0401508542 AU
  • The calculator tells me that the distance between Sun Disc and Planet = 415225 km
  • The angle for the Sun Disc = 2atan(tan(35deg)*(79/285)) = 0.383417968 Rad = 21.968231 Deg
  • Size = 161180 km
Part 2 (IMAGE 1):
  • Sun Disc: 79 px = 161180 km
  • 1 px = 2040.253165 km
  • Petal's height = 7.21 px = 14710.22532 km
Part 2 (IMAGE 2):
  • Petal's height = 87.05 px = 14710.22532 km
  • 1 px = 168.9859313 km
  • Petal's thickness (will use as a low end for the whole thickness) = 9.9 px = 1672.96072 km
Part 3:
  • Sun Disc's volume = pi * ((161180/2)^2) * 1672.96072 = 3.41348445e13 km^3 = 3.41348445e28 cm^3
  • Sun Disc's mass = 3.41348445e28 * ((7.5+8)/2) = 2.645450449e29 g = 2.645450449e26 kg
  • Fragmentation = 208 * 3.41348445e28 = 7.100047656e30 Joules or 1.7 Zettatons (Small Planet)
  • Pulverization = 1000 * 3.41348445e28 = 3.41348445e31 Joules or 8.16 Zettatons (Small Planet)
  • Assuming KE under 1 second because it's fun = 0.5 * 2.645450449e26 * (161180000/2)^2 = 8.59076714e41 Joules or 205.32 Quettatons (Star)

I think this other one is more accurate as it takes in account the fact that the Solar Disc has completely covered the planet from the star, causing its temperature to massively drop. It won't use any pixel scaling here, outside to get the thickness of the disc.

Thanks to this, we know that (assuming Moon = Disc):
  • Radius of Umbra = RadiusMoon - ((Distance Moon-Earth - RadiusEarth)/(Distance Sun-Earth - Distance Moon-Earth))*(RadiusSun - RadiusMoon)
If you don't know, the Umbra is the part that's completely covered in darkness during an eclypse, and what gets their temperature to decrease.

The distance between Sun and Planet is the easiest to take here. Minimal AU to be habitable is 0.9 (and I'll use it as the ice trapping these aliens was melting super fast), which will be 149597870700 m * 0.9 = 134638083630 m, or 134638083.63 km.

The 2nd thing that's unknown here is the distance between Disc and Planet, which will be using the formula from here. The density for the Disc will be stainless steel, which is (7500 + 8000)/2 or 7750 kg/m3.

The rest will be taken care off in the 3 ends, which are the same of the 1st method: Our Earth, Viltrum (again, as VBW currently accepts it) and, as a generous high end, the densest planet ever according to Wikipedia.

For the Thickness, instead...
2O11iOB.png

  • Sun Disc: 79 px
  • Petal: 7.21 px
  • Ratio: 10.95700416
ui85iaE.png

  • Petal: 87.05 px
  • Thickness: 9.9 px
  • Ratio: 8.792929293
Meaning that the diameter of the Disc is 96.34416284 times higher than its thickness.

Earth end

To find the distance between planet and disc (Earth's density is 5513 kg/m3):
  • 2.4 * 6371 * ((5513/7750)^(1/3)) = 13649.4225 km
To find the Radius of the Disc, we know that, assuming that X is the radius of the Disc:
  • 6371 = X - ((13649.4225 - 6371)/(134638083.63 - 13649.4225))*(696340 - X)
  • Putting it in Microsoft Calculator gives me 6408.300913699 km
  • Thickness = 6408.300913699 / 96.34416284 = 66.51467743 km
Now time to get the AP:
  • Sun Disc's volume = pi * (6408.300913699^2) * 66.51467743 = 8.58130139e9 km^3 = 8.58130139e24 cm^3
  • Sun Disc's mass = 8.58130139e24 * 7.75 = 6.650508577e25 g = 6.650508577e22 kg
  • Fragmentation = 208 * 8.58130139e24 = 1.784910689e27 Joules or 426.6 Petatons (Multi-Continent)
  • Pulverization = 1000 * 8.58130139e24 = 8.58130139e27 Joules or 2.05 Exatons (Multi-Continent)
  • Assuming KE under 1 second because it's fun = 0.5 * 6.650508577e22 * (6408300.913699)^2 = 1.365559589e36 Joules or 326.38 Yottatons (Large Planet)
Viltrum end

To find the distance between planet and disc (Viltrum's density is 5513 * 1.25 = 6891.25 kg/m^3):
  • 2.4 * 6371 * ((6891.25/7750)^(1/3)) = 14703.3947 km
To find the Radius of the Disc, we know that, assuming that X is the radius of the Disc:
  • 6371 = X - ((14703.3947 - 6371)/(134638083.63 - 14703.3947))*(696340 - X)
  • Putting it in Microsoft Calculator gives me 6413.702376182 km
  • Thickness = 6413.702376182 / 96.34416284 = 66.57074167 km
Now time to get the AP:
  • Sun Disc's volume = pi * (6413.702376182^2) * 66.57074167 = 8.60301884e9 km^3 = 8.60301884e24 cm^3
  • Sun Disc's mass = 8.60301884e24 * 7.75 = 6.667339601e25 g = 6.667339601e22 kg
  • Fragmentation = 208 * 8.60301884e24 = 1.789427919e27 Joules or 427.68 Petatons (Multi-Continent)
  • Pulverization = 1000 * 8.60301884e24 = 8.60301884e27 Joules or 2.06 Exatons (Multi-Continent)
  • Assuming KE under 1 second because it's fun = 0.5 * 6.650508577e22 * (6408300.913699)^2 = 1.36555959e36 Joules or 326.38 Yottatons (Large Planet) (lol)
Densest Planet end

To find the distance between planet and disc (density is 23 g/cm3, or 23000 Kg/cm3):
  • The radius is 0.4 Jupiter's, which means that the radius 0.4 * 71492 = 28596.8 km
  • 2.4 * 28596.8 * ((23000/7750)^(1/3)) = 98628.87 km
To find the Radius of the Disc, we know that, assuming that X is the radius of the Disc:
  • 28596.8 = X - ((98628.87 - 28596.8)/(134638083.63 - 98628.87))*(696340 - X)
  • Putting it in Microsoft Calculator gives me 28944.200763688
  • Thickness = 28944.200763688 / 96.34416284 = 300.4250586 km
Now time to get the AP:
  • Sun Disc's volume = pi * (28944.200763688^2) * 300.4250586 = 7.90695289e11 km^3 = 7.90695289e26 cm^3
  • Sun Disc's mass = 7.90695289e26 * 7.75 = 6.12788849e27 g = 6.12788849e24 kg
  • Fragmentation = 208 * 7.90695289e26 = 1.644646201e29 Joules or 39.31 Exatons (Moon)
  • Pulverization = 1000 * 7.90695289e26 = 7.90695289e29 Joules or 188.98 Exatons (Moon)
  • Assuming KE under 1 second because it's fun = 0.5 * 6.12788849e24 * (28944200.763688)^2 = 2.56687064e39 Joules or 613.5 Ronnatons (Brown Dwarf)

TLDR coz numbers are beeg:
  • Lagrange method:
    • Earth:
      • Fragmentation = 5.18 Exatons (Multi-Continent)
      • Pulverization = 24.9 Exatons (Multi-Continent+)
      • KE for fun = 13.19 Ronnatons (Large Planet+)
    • Viltrum:
      • Fragmentation = 6.47 Exatons (Multi-Continent)
      • Pulverization = 31.13 Exatons (Moon)
      • KE for fun = 19.13 Ronnatons (Brown Dwarf)
    • Densest Planet in the universe:
      • Fragmentation = 1.7 Zettatons (Small Planet)
      • Pulverization = 8.16 Zettatons (Small Planet)
      • KE for fun = 205.32 Quettatons (Star)

  • Umbra method (more accurate imo):
    • Earth:
      • Fragmentation = 426.6 Petatons (Multi-Continent)
      • Pulverization = 2.05 Exatons (Multi-Continent)
      • KE for fun = 326.38 Yottatons (Large Planet)
    • Viltrum
      • Fragmentation = 427.68 Petatons (Multi-Continent)
      • Pulverization = 2.06 Exatons (Multi-Continent)
      • KE for fun = 326.38 Yottatons (Large Planet) (lol)
    • Densest Planet in the universe:
      • Fragmentation = 39.31 Exatons (Moon)
      • Pulverization = 188.98 Exatons (Moon)
      • KE for fun = 613.5 Ronnatons (Brown Dwarf)
I'd take fragmentation of the Viltrum end in the Umbra method tbh, as the Black hole shit was cartoon only, and we barely see any destruction of the disc.
 
Last edited:
StrymULTRA said:
So I decided to make the calc according to VBW's rules on the Sun Disc's feat, as I said above.

I'll be using two methods:
  1. Lagrange Points
  2. Umbra size
Time to get this shitshow:

2O11iOB.png

  • Planet: 492 px
  • Sun Disc: 79 px
  • Star: 47 px
  • Panel's height: 285 px
  • Petal: 7.21 px
ui85iaE.png

  • Petal's height (imma call them like that): 87.05 px
  • Petal's thickness: 9.9 px
Now... the distance between the star and panel is easy to get, as the default assumption is our Sun unless specified otherwise.
  • (1391400 * 285) / [47 * 2tan(70/2 deg)] = 6024794.3 km
Huh... a lot.

The planet on the other hand is gonna be trickier. I'll use 3 assumptions: Our Earth, Viltrum (again, as VBW currently accepts it) and, as a generous high end, the densest planet ever according to Wikipedia.

I'll also use this very nice rule about scaling the actual diameter of the planet if it's too close to the POV.

Last, but not least, I'll use this calculator to get the distance between the planet and Solar Disc (which will be between M2 and L1).

Imma use steel here for the material, as it's pretty common for this space stuff, and the ends for destruction are fragmentation (208 j/cm3) and pulverization (1000 j/cm3).

Earth end

Part 1:
  • Actual planet's diameter = sqrt(1-(tan(35)x(492/285))^2/((tan(35)x(492/285))^2+1))x12742 = 9862.86584 km
  • Distance between POV and planet = (9862.86584 * 285) / [492 * 2tan(70/2 deg)] = 4079.68006 km
  • Distance between star and planet = 6024794.3 - 4079.68006 = 6020714.62 km, which is 0.0402459914 AU
  • The calculator tells me that the distance between Sun Disc and Planet = 60229.1 km
  • The angle for the Sun Disc = 2atan(tan(35deg)*(79/285)) = 0.383417968 Rad = 21.968231 Deg
  • Size = 23380 km
Part 2 (IMAGE 1):
  • Sun Disc: 79 px = 23380 km
  • 1 px = 295.9493671 km
  • Petal's height = 7.21 px = 2133.794937 km
Part 2 (IMAGE 2):
  • Petal's height = 87.05 px = 2133.794937 km
  • 1 px = 24.51229106 km
  • Petal's thickness (will use as a low end for the whole thickness) = 9.9 px = 242.6716815 km
Part 3:
  • Sun Disc's volume = pi * ((23380/2)^2) * 242.6716815 = 1.04183272e11 km^3 =1.04183272e26 cm^3
  • Sun Disc's mass = 1.04183272e26 * ((7.5+8)/2) = 8.07420358e26 g = 8.07420358e23 kg
  • Fragmentation = 208 * 1.04183272e26 = 2.167012058e28 Joules or 5.18 Exatons (Multi-Continent)
  • Pulverization = 1000 * 1.04183272e26 = 1.04183272e29 Joules or 24.9 Exatons (Multi-Continent+)
  • Assuming KE under 1 second because it's fun = 0.5 * 8.07420358e23 * (23380000/2)^2 = 5.51694586e37 Joules or 13.19 Ronnatons (Large Planet+)
Viltrum end

Part 1:
  • Actual planet's diameter = sqrt(1-(tan(35)x(492/285))^2/((tan(35)x(492/285))^2+1))x12742 = 9862.86584 km
  • Distance between POV and planet = (9862.86584 * 285) / [492 * 2tan(70/2 deg)] = 4079.68006 km
  • Distance between star and planet = 6024794.3 - 4079.68006 = 6020714.62 km, which is 0.0402459914 AU
  • The calculator tells me that the distance between Sun Disc and Planet = 64882.7 km (remember that VBW's mass for Viltrum is 7.4661961e+24 kg if you check the linked blog above)
  • The angle for the Sun Disc = 2atan(tan(35deg)*(79/285)) = 0.383417968 Rad = 21.968231 Deg
  • Size = 25187 km
Part 2 (IMAGE 1):
  • Sun Disc: 79 px = 25187 km
  • 1 px = 318.8227848 km
  • Petal's height = 7.21 px = 2298.712278 km
Part 2 (IMAGE 2):
  • Petal's height = 87.05 px = 2298.712278 km
  • 1 px = 26.40680388 km
  • Petal's thickness (will use as a low end for the whole thickness) = 9.9 px = 261.4273584 km
Part 3:
  • Sun Disc's volume = pi * ((25187/2)^2) * 261.4273584 = 1.30254819e11 km^3 = 1.30254819e26 cm^3
  • Sun Disc's mass = 1.30254819e26 * ((7.5+8)/2) = 1.009474847e27 g = 1.009474847e24 kg
  • Fragmentation = 208 * 1.30254819e26 = 2.709300235e28 Joules or 6.47 Exatons (Multi-Continent)
  • Pulverization = 1000 * 1.30254819e26 = 1.30254819e29 Joules or 31.13 Exatons (Moon)
  • Assuming KE under 1 second because it's fun = 0.5 * 1.009474847e24 * (25187000/2)^2 = 8.00494587e37 Joules or 19.13 Ronnatons (Brown Dwarf)
Densest planet end

Part 0 (to understand the size and mass of the thing):
  • The radius is 0.4 Jupiter's, which means that the diameter is 2 * 0.4 * 71492 = 57193.6 km
  • Mass is 330 Earths, or 330 * 5.9722e24 = 1.970826e27 kg
Part 1:
  • Actual planet's diameter = sqrt(1-(tan(35)x(492/285))^2/((tan(35)x(492/285))^2+1))x57193.6 = 44270.3503 km
  • Distance between POV and planet = (44270.3503 * 285) / [492 * 2tan(70/2 deg)] = 18312.0067 km
  • Distance between star and planet = 6024794.3 - 18312.0067 = 6006482.293 km, which is 0.0401508542 AU
  • The calculator tells me that the distance between Sun Disc and Planet = 415225 km
  • The angle for the Sun Disc = 2atan(tan(35deg)*(79/285)) = 0.383417968 Rad = 21.968231 Deg
  • Size = 161180 km
Part 2 (IMAGE 1):
  • Sun Disc: 79 px = 161180 km
  • 1 px = 2040.253165 km
  • Petal's height = 7.21 px = 14710.22532 km
Part 2 (IMAGE 2):
  • Petal's height = 87.05 px = 14710.22532 km
  • 1 px = 168.9859313 km
  • Petal's thickness (will use as a low end for the whole thickness) = 9.9 px = 1672.96072 km
Part 3:
  • Sun Disc's volume = pi * ((161180/2)^2) * 1672.96072 = 3.41348445e13 km^3 = 3.41348445e28 cm^3
  • Sun Disc's mass = 3.41348445e28 * ((7.5+8)/2) = 2.645450449e29 g = 2.645450449e26 kg
  • Fragmentation = 208 * 3.41348445e28 = 7.100047656e30 Joules or 1.7 Zettatons (Small Planet)
  • Pulverization = 1000 * 3.41348445e28 = 3.41348445e31 Joules or 8.16 Zettatons (Small Planet)
  • Assuming KE under 1 second because it's fun = 0.5 * 2.645450449e26 * (161180000/2)^2 = 8.59076714e41 Joules or 205.32 Quettatons (Star)

I think this other one is more accurate as it takes in account the fact that the Solar Disc has completely covered the planet from the star, causing its temperature to massively drop. It won't use any pixel scaling here, outside to get the thickness of the disc.

Thanks to this, we know that (assuming Moon = Disc):
  • Radius of Umbra = RadiusMoon - ((Distance Moon-Earth - RadiusEarth)/(Distance Sun-Earth - Distance Moon-Earth))*(RadiusSun - RadiusMoon)
If you don't know, the Umbra is the part that's completely covered in darkness during an eclypse, and what gets their temperature to decrease.

The distance between Sun and Planet is the easiest to take here. Minimal AU to be habitable is 0.9 (and I'll use it as the ice trapping these aliens was melting super fast), which will be 149597870700 m * 0.9 = 134638083630 m, or 134638083.63 km.

The 2nd thing that's unknown here is the distance between Disc and Planet, which will be using the formula from here. The density for the Disc will be stainless steel, which is (7500 + 8000)/2 or 7750 kg/m3.

The rest will be taken care off in the 3 ends, which are the same of the 1st method: Our Earth, Viltrum (again, as VBW currently accepts it) and, as a generous high end, the densest planet ever according to Wikipedia.

For the Thickness, instead...
2O11iOB.png

  • Sun Disc: 79 px
  • Petal: 787-.21 px
  • Ratio: 10.95700416
ui85iaE.png

  • Petal: 87.05 px
  • Thickness: 9.9 px
  • Ratio: 8.792929293
Meaning that the diameter of the Disc is 96.34416284 times higher than its thickness.

Earth end

To find the distance between planet and disc (Earth's density is 5513 kg/m3):
  • 2.4 * 6371 * ((5513/7750)^(1/3)) = 13649.4225 km
To find the Radius of the Disc, we know that, assuming that X is the radius of the Disc:
  • 6371 = X - ((13649.4225 - 6371)/(134638083.63 - 13649.4225))*(696340 - X)
  • Putting it in Microsoft Calculator gives me 6408.300913699 km
  • Thickness = 6408.300913699 / 96.34416284 = 66.51467743 km
Now time to get the AP:
  • Sun Disc's volume = pi * (6408.300913699^2) * 66.51467743 = 8.58130139e9 km^3 = 8.58130139e24 cm^3
  • Sun Disc's mass = 8.58130139e24 * 7.75 = 6.650508577e25 g = 6.650508577e22 kg
  • Fragmentation = 208 * 8.58130139e24 = 1.784910689e27 Joules or 426.6 Petatons (Multi-Continent)
  • Pulverization = 1000 * 8.58130139e24 = 8.58130139e27 Joules or 2.05 Exatons (Multi-Continent)
  • Assuming KE under 1 second because it's fun = 0.5 * 6.650508577e22 * (6408300.913699)^2 = 1.365559589e36 Joules or 326.38 Yottatons (Large Planet)
Viltrum end

To find the distance between planet and disc (Viltrum's density is 5513 * 1.25 = 6891.25 kg/m^3):
  • 2.4 * 6371 * ((6891.25/7750)^(1/3)) = 14703.3947 km
To find the Radius of the Disc, we know that, assuming that X is the radius of the Disc:
  • 6371 = X - ((14703.3947 - 6371)/(134638083.63 - 14703.3947))*(696340 - X)
  • Putting it in Microsoft Calculator gives me 6413.702376182 km
  • Thickness = 6413.702376182 / 96.34416284 = 66.57074167 km
Now time to get the AP:
  • Sun Disc's volume = pi * (6413.702376182^2) * 66.57074167 = 8.60301884e9 km^3 = 8.60301884e24 cm^3
  • Sun Disc's mass = 8.60301884e24 * 7.75 = 6.667339601e25 g = 6.667339601e22 kg
  • Fragmentation = 208 * 8.60301884e24 = 1.789427919e27 Joules or 427.68 Petatons (Multi-Continent)
  • Pulverization = 1000 * 8.60301884e24 = 8.60301884e27 Joules or 2.06 Exatons (Multi-Continent)
  • Assuming KE under 1 second because it's fun = 0.5 * 6.650508577e22 * (6408300.913699)^2 = 1.36555959e36 Joules or 326.38 Yottatons (Large Planet) (lol)
Densest Planet end

To find the distance between planet and disc (density is 23 g/cm3, or 23000 g/cm3):
  • The radius is 0.4 Jupiter's, which means that the radius 0.4 * 71492 = 28596.8 km
  • 2.4 * 28596.8 * ((6891.25/7750)^(1/3)) = 65997.4943 km
To find the Radius of the Disc, we know that, assuming that X is the radius of the Disc:
  • 28596.8 = X - ((65997.4943 - 28596.8)/(134638083.63 - 65997.4943))*(696340 - X)
  • Putting it in Microsoft Calculator gives me 28782.329711778 km
  • Thickness = 28782.329711778 / 96.34416284 = 298.7449251 km
Now time to get the AP:
  • Sun Disc's volume = pi * (28782.329711778^2) * 298.7449251 = 7.775034e11 km^3 = 7.775034e26 cm^3
  • Sun Disc's mass = 7.775034e26 * 7.75 = 6.02565135e27 g = 6.02565135e24 kg
  • Fragmentation = 208 * 7.775034e26 = 1.617207072e29 Joules or 38.65 Exatons (Moon)
  • Pulverization = 1000 * 7.775034e26 = 7.775034e29 Joules or 185.83 Exatons (Moon)
  • Assuming KE under 1 second because it's fun = 0.5 * 6.02565135e24 * (6408300.913699)^2 = 1.23725665e38 Joules or 29.57 Ronnatona (Brown Dwarf)

TLDR coz numbers are beeg:
  • Lagrange method:
    • Earth:
      • Fragmentation = 5.18 Exatons (Multi-Continent)
      • Pulverization = 24.9 Exatons (Multi-Continent+)
      • KE for fun = 13.19 Ronnatons (Large Planet+)
    • Viltrum:
      • Fragmentation = 6.47 Exatons (Multi-Continent)
      • Pulverization = 31.13 Exatons (Moon)
      • KE for fun = 19.13 Ronnatons (Brown Dwarf)
    • Densest Planet in the universe:
      • Fragmentation = 1.7 Zettatons (Small Planet)
      • Pulverization = 8.16 Zettatons (Small Planet)
      • KE for fun = 205.32 Quettatons (Star)

  • Umbra method (more accurate imo):
    • Earth:
      • Fragmentation = 426.6 Petatons (Multi-Continent)
      • Pulverization = 2.05 Exatons (Multi-Continent)
      • KE for fun = 326.38 Yottatons (Large Planet)
    • Viltrum
      • Fragmentation = 427.68 Petatons (Multi-Continent)
      • Pulverization = 2.06 Exatons (Multi-Continent)
      • KE for fun = 326.38 Yottatons (Large Planet) (lol)
    • Densest Planet in the universe:
      • Fragmentation = 38.65 Exatons (Moon)
      • Pulverization = 185.83 Exatons (Moon)
      • KE for fun = 29.57 Ronnatona (Brown Dwarf)
I'd take fragmentation of the Viltrum end in the Umbra method tbh, as the Black hole shit was cartoon only, and we barely see any destruction of the disc.
Click to expand...
So it's weaker than the Viltrum planet bust, right?
 
Tipper17 said:
If they can go through the core of Viltrum that got hit by the infinity ray the heat weakness shit not selling me especially when kirkman probably never took it into account for the final fight
Click to expand...
Pretty sure a sun is hotter then a planet core, especially with spending a lot of time in a star without getting out
AcidSilver said:
Nuh-Uh. Checkmate.
Click to expand...
Dont pull a DBC now
 
SlendVeny said:
Ok, but that's heat resistance, Bardock would get melted in the sun too.
Click to expand...
Thing is nobody thinks Bardock is star level even if ya factor this sites ratings

This was the strongest viltrutmites getting his ass cooked shit if anything that's supports the idea there nowhere near star level and I mentioned the infinity ray and again Viltrum shit
If kirkman wanted star level invincible he would've done so without the infinity ray
StrymULTRA said:
So I decided to make the calc according to VBW's rules on the Sun Disc's feat, as I said above.

I'll be using two methods:
  1. Lagrange Points
  2. Umbra size
Time to get this shitshow:

2O11iOB.png

  • Planet: 492 px
  • Sun Disc: 79 px
  • Star: 47 px
  • Panel's height: 285 px
  • Petal: 7.21 px
ui85iaE.png

  • Petal's height (imma call them like that): 87.05 px
  • Petal's thickness: 9.9 px
Now... the distance between the star and panel is easy to get, as the default assumption is our Sun unless specified otherwise.
  • (1391400 * 285) / [47 * 2tan(70/2 deg)] = 6024794.3 km
Huh... a lot.

The planet on the other hand is gonna be trickier. I'll use 3 assumptions: Our Earth, Viltrum (again, as VBW currently accepts it) and, as a generous high end, the densest planet ever according to Wikipedia.

I'll also use this very nice rule about scaling the actual diameter of the planet if it's too close to the POV.

Last, but not least, I'll use this calculator to get the distance between the planet and Solar Disc (which will be between M2 and L1).

Imma use steel here for the material, as it's pretty common for this space stuff, and the ends for destruction are fragmentation (208 j/cm3) and pulverization (1000 j/cm3).

Earth end

Part 1:
  • Actual planet's diameter = sqrt(1-(tan(35)x(492/285))^2/((tan(35)x(492/285))^2+1))x12742 = 9862.86584 km
  • Distance between POV and planet = (9862.86584 * 285) / [492 * 2tan(70/2 deg)] = 4079.68006 km
  • Distance between star and planet = 6024794.3 - 4079.68006 = 6020714.62 km, which is 0.0402459914 AU
  • The calculator tells me that the distance between Sun Disc and Planet = 60229.1 km
  • The angle for the Sun Disc = 2atan(tan(35deg)*(79/285)) = 0.383417968 Rad = 21.968231 Deg
  • Size = 23380 km
Part 2 (IMAGE 1):
  • Sun Disc: 79 px = 23380 km
  • 1 px = 295.9493671 km
  • Petal's height = 7.21 px = 2133.794937 km
Part 2 (IMAGE 2):
  • Petal's height = 87.05 px = 2133.794937 km
  • 1 px = 24.51229106 km
  • Petal's thickness (will use as a low end for the whole thickness) = 9.9 px = 242.6716815 km
Part 3:
  • Sun Disc's volume = pi * ((23380/2)^2) * 242.6716815 = 1.04183272e11 km^3 =1.04183272e26 cm^3
  • Sun Disc's mass = 1.04183272e26 * ((7.5+8)/2) = 8.07420358e26 g = 8.07420358e23 kg
  • Fragmentation = 208 * 1.04183272e26 = 2.167012058e28 Joules or 5.18 Exatons (Multi-Continent)
  • Pulverization = 1000 * 1.04183272e26 = 1.04183272e29 Joules or 24.9 Exatons (Multi-Continent+)
  • Assuming KE under 1 second because it's fun = 0.5 * 8.07420358e23 * (23380000/2)^2 = 5.51694586e37 Joules or 13.19 Ronnatons (Large Planet+)
Viltrum end

Part 1:
  • Actual planet's diameter = sqrt(1-(tan(35)x(492/285))^2/((tan(35)x(492/285))^2+1))x12742 = 9862.86584 km
  • Distance between POV and planet = (9862.86584 * 285) / [492 * 2tan(70/2 deg)] = 4079.68006 km
  • Distance between star and planet = 6024794.3 - 4079.68006 = 6020714.62 km, which is 0.0402459914 AU
  • The calculator tells me that the distance between Sun Disc and Planet = 64882.7 km (remember that VBW's mass for Viltrum is 7.4661961e+24 kg if you check the linked blog above)
  • The angle for the Sun Disc = 2atan(tan(35deg)*(79/285)) = 0.383417968 Rad = 21.968231 Deg
  • Size = 25187 km
Part 2 (IMAGE 1):
  • Sun Disc: 79 px = 25187 km
  • 1 px = 318.8227848 km
  • Petal's height = 7.21 px = 2298.712278 km
Part 2 (IMAGE 2):
  • Petal's height = 87.05 px = 2298.712278 km
  • 1 px = 26.40680388 km
  • Petal's thickness (will use as a low end for the whole thickness) = 9.9 px = 261.4273584 km
Part 3:
  • Sun Disc's volume = pi * ((25187/2)^2) * 261.4273584 = 1.30254819e11 km^3 = 1.30254819e26 cm^3
  • Sun Disc's mass = 1.30254819e26 * ((7.5+8)/2) = 1.009474847e27 g = 1.009474847e24 kg
  • Fragmentation = 208 * 1.30254819e26 = 2.709300235e28 Joules or 6.47 Exatons (Multi-Continent)
  • Pulverization = 1000 * 1.30254819e26 = 1.30254819e29 Joules or 31.13 Exatons (Moon)
  • Assuming KE under 1 second because it's fun = 0.5 * 1.009474847e24 * (25187000/2)^2 = 8.00494587e37 Joules or 19.13 Ronnatons (Brown Dwarf)
Densest planet end

Part 0 (to understand the size and mass of the thing):
  • The radius is 0.4 Jupiter's, which means that the diameter is 2 * 0.4 * 71492 = 57193.6 km
  • Mass is 330 Earths, or 330 * 5.9722e24 = 1.970826e27 kg
Part 1:
  • Actual planet's diameter = sqrt(1-(tan(35)x(492/285))^2/((tan(35)x(492/285))^2+1))x57193.6 = 44270.3503 km
  • Distance between POV and planet = (44270.3503 * 285) / [492 * 2tan(70/2 deg)] = 18312.0067 km
  • Distance between star and planet = 6024794.3 - 18312.0067 = 6006482.293 km, which is 0.0401508542 AU
  • The calculator tells me that the distance between Sun Disc and Planet = 415225 km
  • The angle for the Sun Disc = 2atan(tan(35deg)*(79/285)) = 0.383417968 Rad = 21.968231 Deg
  • Size = 161180 km
Part 2 (IMAGE 1):
  • Sun Disc: 79 px = 161180 km
  • 1 px = 2040.253165 km
  • Petal's height = 7.21 px = 14710.22532 km
Part 2 (IMAGE 2):
  • Petal's height = 87.05 px = 14710.22532 km
  • 1 px = 168.9859313 km
  • Petal's thickness (will use as a low end for the whole thickness) = 9.9 px = 1672.96072 km
Part 3:
  • Sun Disc's volume = pi * ((161180/2)^2) * 1672.96072 = 3.41348445e13 km^3 = 3.41348445e28 cm^3
  • Sun Disc's mass = 3.41348445e28 * ((7.5+8)/2) = 2.645450449e29 g = 2.645450449e26 kg
  • Fragmentation = 208 * 3.41348445e28 = 7.100047656e30 Joules or 1.7 Zettatons (Small Planet)
  • Pulverization = 1000 * 3.41348445e28 = 3.41348445e31 Joules or 8.16 Zettatons (Small Planet)
  • Assuming KE under 1 second because it's fun = 0.5 * 2.645450449e26 * (161180000/2)^2 = 8.59076714e41 Joules or 205.32 Quettatons (Star)

I think this other one is more accurate as it takes in account the fact that the Solar Disc has completely covered the planet from the star, causing its temperature to massively drop. It won't use any pixel scaling here, outside to get the thickness of the disc.

Thanks to this, we know that (assuming Moon = Disc):
  • Radius of Umbra = RadiusMoon - ((Distance Moon-Earth - RadiusEarth)/(Distance Sun-Earth - Distance Moon-Earth))*(RadiusSun - RadiusMoon)
If you don't know, the Umbra is the part that's completely covered in darkness during an eclypse, and what gets their temperature to decrease.

The distance between Sun and Planet is the easiest to take here. Minimal AU to be habitable is 0.9 (and I'll use it as the ice trapping these aliens was melting super fast), which will be 149597870700 m * 0.9 = 134638083630 m, or 134638083.63 km.

The 2nd thing that's unknown here is the distance between Disc and Planet, which will be using the formula from here. The density for the Disc will be stainless steel, which is (7500 + 8000)/2 or 7750 kg/m3.

The rest will be taken care off in the 3 ends, which are the same of the 1st method: Our Earth, Viltrum (again, as VBW currently accepts it) and, as a generous high end, the densest planet ever according to Wikipedia.

For the Thickness, instead...
2O11iOB.png

  • Sun Disc: 79 px
  • Petal: 787-.21 px
  • Ratio: 10.95700416
ui85iaE.png

  • Petal: 87.05 px
  • Thickness: 9.9 px
  • Ratio: 8.792929293
Meaning that the diameter of the Disc is 96.34416284 times higher than its thickness.

Earth end

To find the distance between planet and disc (Earth's density is 5513 kg/m3):
  • 2.4 * 6371 * ((5513/7750)^(1/3)) = 13649.4225 km
To find the Radius of the Disc, we know that, assuming that X is the radius of the Disc:
  • 6371 = X - ((13649.4225 - 6371)/(134638083.63 - 13649.4225))*(696340 - X)
  • Putting it in Microsoft Calculator gives me 6408.300913699 km
  • Thickness = 6408.300913699 / 96.34416284 = 66.51467743 km
Now time to get the AP:
  • Sun Disc's volume = pi * (6408.300913699^2) * 66.51467743 = 8.58130139e9 km^3 = 8.58130139e24 cm^3
  • Sun Disc's mass = 8.58130139e24 * 7.75 = 6.650508577e25 g = 6.650508577e22 kg
  • Fragmentation = 208 * 8.58130139e24 = 1.784910689e27 Joules or 426.6 Petatons (Multi-Continent)
  • Pulverization = 1000 * 8.58130139e24 = 8.58130139e27 Joules or 2.05 Exatons (Multi-Continent)
  • Assuming KE under 1 second because it's fun = 0.5 * 6.650508577e22 * (6408300.913699)^2 = 1.365559589e36 Joules or 326.38 Yottatons (Large Planet)
Viltrum end

To find the distance between planet and disc (Viltrum's density is 5513 * 1.25 = 6891.25 kg/m^3):
  • 2.4 * 6371 * ((6891.25/7750)^(1/3)) = 14703.3947 km
To find the Radius of the Disc, we know that, assuming that X is the radius of the Disc:
  • 6371 = X - ((14703.3947 - 6371)/(134638083.63 - 14703.3947))*(696340 - X)
  • Putting it in Microsoft Calculator gives me 6413.702376182 km
  • Thickness = 6413.702376182 / 96.34416284 = 66.57074167 km
Now time to get the AP:
  • Sun Disc's volume = pi * (6413.702376182^2) * 66.57074167 = 8.60301884e9 km^3 = 8.60301884e24 cm^3
  • Sun Disc's mass = 8.60301884e24 * 7.75 = 6.667339601e25 g = 6.667339601e22 kg
  • Fragmentation = 208 * 8.60301884e24 = 1.789427919e27 Joules or 427.68 Petatons (Multi-Continent)
  • Pulverization = 1000 * 8.60301884e24 = 8.60301884e27 Joules or 2.06 Exatons (Multi-Continent)
  • Assuming KE under 1 second because it's fun = 0.5 * 6.650508577e22 * (6408300.913699)^2 = 1.36555959e36 Joules or 326.38 Yottatons (Large Planet) (lol)
Densest Planet end

To find the distance between planet and disc (density is 23 g/cm3, or 23000 g/cm3):
  • The radius is 0.4 Jupiter's, which means that the radius 0.4 * 71492 = 28596.8 km
  • 2.4 * 28596.8 * ((6891.25/7750)^(1/3)) = 65997.4943 km
To find the Radius of the Disc, we know that, assuming that X is the radius of the Disc:
  • 28596.8 = X - ((65997.4943 - 28596.8)/(134638083.63 - 65997.4943))*(696340 - X)
  • Putting it in Microsoft Calculator gives me 28782.329711778 km
  • Thickness = 28782.329711778 / 96.34416284 = 298.7449251 km
Now time to get the AP:
  • Sun Disc's volume = pi * (28782.329711778^2) * 298.7449251 = 7.775034e11 km^3 = 7.775034e26 cm^3
  • Sun Disc's mass = 7.775034e26 * 7.75 = 6.02565135e27 g = 6.02565135e24 kg
  • Fragmentation = 208 * 7.775034e26 = 1.617207072e29 Joules or 38.65 Exatons (Moon)
  • Pulverization = 1000 * 7.775034e26 = 7.775034e29 Joules or 185.83 Exatons (Moon)
  • Assuming KE under 1 second because it's fun = 0.5 * 6.02565135e24 * (6408300.913699)^2 = 1.23725665e38 Joules or 29.57 Ronnatona (Brown Dwarf)

TLDR coz numbers are beeg:
  • Lagrange method:
    • Earth:
      • Fragmentation = 5.18 Exatons (Multi-Continent)
      • Pulverization = 24.9 Exatons (Multi-Continent+)
      • KE for fun = 13.19 Ronnatons (Large Planet+)
    • Viltrum:
      • Fragmentation = 6.47 Exatons (Multi-Continent)
      • Pulverization = 31.13 Exatons (Moon)
      • KE for fun = 19.13 Ronnatons (Brown Dwarf)
    • Densest Planet in the universe:
      • Fragmentation = 1.7 Zettatons (Small Planet)
      • Pulverization = 8.16 Zettatons (Small Planet)
      • KE for fun = 205.32 Quettatons (Star)

  • Umbra method (more accurate imo):
    • Earth:
      • Fragmentation = 426.6 Petatons (Multi-Continent)
      • Pulverization = 2.05 Exatons (Multi-Continent)
      • KE for fun = 326.38 Yottatons (Large Planet)
    • Viltrum
      • Fragmentation = 427.68 Petatons (Multi-Continent)
      • Pulverization = 2.06 Exatons (Multi-Continent)
      • KE for fun = 326.38 Yottatons (Large Planet) (lol)
    • Densest Planet in the universe:
      • Fragmentation = 38.65 Exatons (Moon)
      • Pulverization = 185.83 Exatons (Moon)
      • KE for fun = 29.57 Ronnatona (Brown Dwarf)
I'd take fragmentation of the Viltrum end in the Umbra method tbh, as the Black hole shit was cartoon only, and we barely see any destruction of the disc.
Click to expand...
So frankly even if you calc it doesn't get anywhere as high db got it too
 
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Jasonsith
Death Battle Season Seven Discussion Thread (5) (Death Battle Spoilers Alert)
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EnnardTrap1987
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