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Agnaa

Agnaa

VS Battles Super Moderator Administrator Calculation Group Translation Helper Human Resources Gold Supporter
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  • Currently in a nadir of interest. Not reading my profile or notifications. If there's anything important, DM me. 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==================================================================================================================================================================== Currently in a nadir of interest. Not reading my profile or notifications. If there's anything important, DM me.
    FantaRin_The_First
    Hey, hey, fanta here. I am 'bout to show ya something, it is a picture of a hole. I need your opinion about its shape. A good friend of mind told me to use rectangular volume for it -
    and I can do that, I have another frame of the same shot that shows a person passing through the hole to pixel scale from, and the picture you see now is something I picked out in order to help you judge the best shape, thus, I wanna hear your opinion about this. Also, to say it now, this is about the last calc-related thing you should hear from me for awhile, don't want to bother you more than I already have about calc stuff.

    View previous comments…
    Agnaa
    Agnaa
    Wait, is the hole you're calculating just the one in the door, or is it including everything behind it?
    FantaRin_The_First
    FantaRin_The_First
    Just the one in the door.
    Agnaa
    Agnaa
    V. Frag, imo. But you can just list multiple ends and whoever evaluates it will pick one.
    DaReaperMan
    About Acausality 5 having nobody who qualifies...

    Warhammer Acausality 5 is probably still fine, they've got feats of being unaffected by even Irregular flows of Causality and the only things that interact with anything from the warp in either 40K, AoS, or Fantasy, are magical/enchanted weapons or straight magic. Kinda like a NEP 2 being socking another NEP 2 being, it's using the exact same stuff they're made of in the first place on them
    Agnaa
    Agnaa
    idk, you can bring that up in the thread tho.
    ImmortalDread
    I agree with your reasoning and disagreement on that topic. It seems rather punishing person where there the rule itself allowed him.
    I struggled to debate on it because it seems for me incon (with old rules).
    ImmortalDread
    ImmortalDread
    Don't you see the reasoning behind the topic ban is unfair itself? The staff is still debating on who will win.
    The Vs. thread itself is not against wiki rules. I won't talk anymore there. But I simply want to know which rule he violated.
    This is all, and I believe transparency in judgment is best. Involving his old past violations (he mentioned he only did this one, and the old previous are 2 years old) is a bad argument to begin with because those old violations are already dealt with.
    Agnaa
    Agnaa
    Agnaa said:
    If you don't know all the reasons that Goku vs Saul would be unworkable (Goku being able to nuke Saul from 4km away as soon as the match starts, dearth of information on Goku's motivations and no way to stall for time to discover them, Goku being able to power up and speed blitz, Saul's convincing taking time that he doesn't have, Saul's convincing having worked in limited situations and still resulted in bodily harm coming to the people involved to the extent of probably being ruled an incap loss, Saul's convincing having numerous anti-feats), despite knowing one of the verses involved well, then you can't really be trusted to make reasonable matches involving that verse.
    Click to expand...
    ImmortalDread
    ImmortalDread
    Understandable. I won't comment anymore.
    KobsterHope07
    Hello, hello.

    I saw the notifications on two of my calc blogs. Thanks for the notifs, but is the other method in those blogs okay
    Agnaa
    Agnaa
    It's much closer, but not quite. The main substantive thing, is that I'd use the density of flame (0.3 kg/m^3) instead of the density of air. And I use veeery slightly different values for temperature change and heat capacity, but those would barely change the results at all. You can see this calc for an example.
    FantaRin_The_First
    Hey, hey, fanta here, and I require your help... not input on my calcs, but I need your knowledge (again).



    Do you know the possible correct shape for this? I can't make heads or tails of it.
    Mr_Sugabz
    Agnaa
    Agnaa
    What do you need the middle value for?

    But it would be 0.13 + ((0.2-0.13)/2), or 0.165
    Mr_Sugabz
    Mr_Sugabz
    hmm I'm arguing with my friend actually. And, is this different from the average formula in mathematics?
    Example: (0.2+0.3+0.4 ........ 0.11+0.12+0.13) Then divided by how many data there are?
    Agnaa
    Agnaa
    The conventional average formula doesn't really work for infinite sets; there's an infinite amount of values between 0.2 and 0.13

    But there's many ways to reach the answer I described. (0.2+0.13)/2 also reaches the same answer for all endpoints.

    And intuitively, you could imagine it working the same way as the ordinary average formula. If you add each of the numbers on either side of the extreme, the average of that pair would cancel out to the midpoint. That gets done for every single number in the infinite set.
    FantaRin_The_First
    Hey, hey, fanta here. Small question... How do you find the cubic meter (m^3) value to find the volume for humanoid-shaped things? Genuinely curious, and wonder if you know or is just really simple - like I just need to find a meter to cubic meter converter online or smth.
    View previous comments…
    FantaRin_The_First
    FantaRin_The_First
    Hey, hey, it's Fanta again, and I wish to inform you of what I did with the information you gave me, well... It's dumb, but, basically, I used the height of a giant mecha (6.94m) and ^3 times it in order to get a volume of 334.3m - afterwards, I used the fact that the mecha was composed out of tungsten and multiplied the volume value I got by the V.Frag Value of Tungsten [1412.5 J/cc].

    ... To make it more quicker to understand, here's the formula I used.

    334.3 m^3 * 1412.5 J/cc = 472198750000 joules, or 112.86 Tons.

    Is there anything wrong with this formula itself, and if so, could you tell me?
    Agnaa
    Agnaa
    Main concern I could have is that giant mechas wouldn't usually be completely solid, like the human body is, so you'd need to reduce that number based on how hollow the mech seems.

    If it seems to be 20% air, you'd multiply it by 0.8, if it seems to be 50% air, multiply by 0.5, etc.

    Also, could be a bit strange to assume tungsten for literally the entire thing, including cables and all of that. V. Frag may or may not be accurate. Etc.
    FantaRin_The_First
    FantaRin_The_First
    True, true. Hm... There is a cockpit area, so maybe 0.8 to 0.5 might be fine. Idk. Never done something like this before.

    And I know, but tungsten is the only confirmed material, so can't really guess. And I am assuming V.Frag cuz it explicitly shows very small shards of metal flying onwards after they explode, could settle for Frag, tho.
    FantaRin_The_First
    Hey, hey, fanta here!

    Agnaa, could you check if I do the numbers right in this calc? It is the thing that I asked for your help for, y'know, the big hole. I literally just want to know if I did the math right, and didn't screw up somewhere.
    View previous comments…
    Agnaa
    Agnaa
    I ran the numbers for one of the triangles, and you applied it perfectly.
    FantaRin_The_First
    FantaRin_The_First
    Thanks, mate! From here on, won't be bothering ya about this calc. Got everything I wanted answered, answered! And now I wait for other CGM to check out my calc and get their two cents 'bout it.
    Agnaa
    Agnaa
    No problem buddy.
    azontr
    View previous comments…
    azontr
    azontr
    Alright, thanks!
    Drite77
    Drite77
    Heeeey, sorry for bringing this up here since Fandom is a bitch and won't notify us

    The reason why I don't think I should double the result is because they have 2 arms. When one arm punches, the other is in standby, and when they retrieve their arm, the other punches at the same time.

    They weren't punching with one hand or don't have 2 arms
    Agnaa
    Agnaa
    idk if that really matters. Their total movement is 398-400 arm lengths, even if it was done with two limbs.

    You can ask another calc group member, but I think doubling would be ideal. If they say otherwise, then I'll fold. I am relatively new to this, after all.
    FantaRin_The_First
    Hey, hey, I got a question to ask.

    Would it be okay for me to make a user blog that features 3 different calcs from the same show in one user blog? Kinda wanted to make three different user blogs but figured that would be too troublesome and tiresome for CGMs.
    View previous comments…
    Agnaa
    Agnaa
    I'm not sure what destruction values we give for asphalt.

    Using the shapes I drew, I'd do area of a triangle (green triangle 1) + area of a triangle (green triangle 2) + area of an ellipsis (green circle) - area of an ellipsis (yellow circle), and then multiply all of that by the depth. If the crater has an uneven depth, it would be really difficult to account for because of the weird doughnut + triangular indent it's got going on.

    I'd say just a depth of 5.7m for seeming taller than the robots. I wouldn't bother pixel-scaling.
    FantaRin_The_First
    FantaRin_The_First
    I'll figure out the destruction values for asphalt later... Probably settle for just cement or just rocks to make it simpler.

    Thank you for your help. See you later, I suppose.
    FantaRin_The_First
    FantaRin_The_First
    Hey, hey, I am in the finishing touches of my calc - and am going to actually put it in a user blog soon, but want to get something clear first.

    When you said do the area of the shapes and multipy them by the depth do you mean smth like this - example: 7m (base of a triangle times 4m (height of a triangle) times 5.7m (the depth of 5.7m that you mentioned I should use) to get their cubic centimeter / cubic meter?

    Also, once I get all of the cubic centimeter / cubic meter for all of the shapes, do I add them up altogether and then multiply them by the pulverization value of concrete and/or rock?

    Just making sure since I haven't done a calc like this before.
    Eseseso
    Could you open up the Doctor Doom page for just a sec?

    I just want to remove the justification of Doom "destroying Doombots almost comparable to him", since that statement means nothing in scaling and just seems so weird.
    Agnaa
    Agnaa
    Doctor Doom's getting changed real soon, iirc. You should ask in this thread about it.
    Eseseso
    Eseseso
    The thread already did their change and relocked the page, but I'll re ask
    Omnificence
    @Agnaa Do you know if this is a galaxy or universe, or some shiz like that?
    Agnaa
    Agnaa
    The terrible quality makes it too hard to tell.

    Pinging me does nothing btw. Only staff members give notifications by pinging, and I already get notifications for posts on my wall.
    Omnificence
    Omnificence
    I don't suppose you can calculate it, can you?
    Agnaa
    Agnaa
    Nope.

    If you still want me to eyeball from that video, it looks more like a protostar/proto-solar system. Maybe less because of the relative sizes of the characters/spaceships.

    But I could be missing some details that indicate it's a galaxy/universe in the low quality.
    RoTt35
    Hello, I would appreciate if you could evaluate this calc. Thanks in advance
    Agnaa
    Agnaa
    I will not be evaluating that calc.
    RoTt35
    RoTt35
    Np, thanks anyways
    Rikimarox2
    Ello, simple question if you don't mind, but if we have a statement about a character shaking an entire forest, but the forest size wasn't mentioned, what can I do to calc it? Or is it just unquantifiable?
    Jamesthetaker
    Hi there, may I ask a question about lifting strength?

    If there were characters A and B with comparable AP but B had superior lifting strength, then would B be able to crush A with LS with ease?
    Drite77
    Suuuuuup, I don't know if you didn't get a notification (Because I didn't) of the evaluation here but:
    He gave the scan for the 3/4s of a month and it checks out.
    The ship doesn't really have any description itself. Prob could change the speed to a 1800s ship instead of a modern day one if needed
    View previous comments…
    Agnaa
    Agnaa
    I left the question in the calc's comments, but I'll repost here.

    Can you post where you got that formula from? I don't recognize it. And using another formula I've seen accepted in other calcs, I got a result about 3.53x lower. So either you're using the formula incorrectly, or one of these calcs needs to be updated.
    Click to expand...
    Drite77
    Drite77
    Agnaa
    Agnaa
    Oh, airburst vs ground, doh. Yeah that's fine.
    Arnoldstone18
    Agnaa
    Agnaa
    I'm glad that I don't have to because I won't :3
    Arnoldstone18
    Arnoldstone18
    41ee9620-7454-49a5-a080-e7467b8efad0.png


    Understandable 🫠
    Arkenis
    Hey, got a calc you could do for me if u can. I'm struggling to figure out what to use and how to calc it really given the type of reaction speed.
    0091-013.png

    0091-014.png


    The projectiles are all moving at mach 3 and the guy reacting is 6ft. and the sword is is moving, he's not swinging it to react to them, that sword just fast.
    Agnaa
    Agnaa
    I don't understand what the hell's going on here. How do know the projectiles are moving at mach 3?
    Arkenis
    Arkenis
    They're stated to in previous chapter.
    Agnaa
    Agnaa
    It would be best to link that statement as well when asking for the calc to be made, but idk how to calc that, sorry.
    FantaRin_The_First
    Hey, hey, would it be possible for you to look this calc? ... The first one, to be exact. It is simply a calc that calc a giant's size and GPE to get its AP - it (and the lesser calc) serves as the foundation for an entire verse, but I really just need somebody to see if I fudge smth up with the giant calc.
    Agnaa
    Agnaa
    I'm putting calc evals off for a minute. I might get to it eventually, but you should prolly ask someone else.
    FantaRin_The_First
    FantaRin_The_First
    Thank you for taking the time to reply, Agn. Will do what you said.
    Propellus
    Hey Agnaa, I'm not sure if you're knowledgable in Pythagoras theorem, but this calc could really use some corrections using that formula.
    Agnaa
    Agnaa
    The length of the side opposite the right angle of a right-angled triangle is equal to the square of the other two sides.
    XitSign
    Hello, and terribly sorry for the both on this, going around to try to get some input.

    I have a fairly important CRT for the verse Puzzle and Dragons, however due to its niche nature it can be really hard to get input on these.

    If you can give your thoughts, it would be greatly apricated, but if not I 100% understand. Either way, thank you so much.
    Agnaa
    Agnaa
    I cannot, sorry m8.
    XitSign
    XitSign
    Totally understandable, thank you for getting back to me!
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