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A references for common feats page continuation

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That would depend on the size of the door, so I think the more important statistics to get to those numbers are the common materials made for them.
 
Just get the mass of the vault door and divide its mass with the density of the metals used to make the door to get the volume and use said metal's frag, v. frag and pulverization depending on how it's destroyed (This is in case the feat is done off-screen or is used as a general feat).

But if the door is shown, then you can use good-old pixel-scaling.

Today's vault doors are made of cast iro, which has a density of 6800-7800 kg/m^3 starting shear strength of 276 MPa and a tensile strength of 414 MPa (We use shear strength for normal frag, tensile strength for v. frag and ultimate tensile strength for pulverization)
 
I've been meaning to ask, where's the page that states the frag, v.frag, etc numbers?
 
Subatomic Destruction: Value is 5.403E13 (j/cc).

Does that mean 5.403x10^13 or 5.403^13?
 
the former
 
That should probably be corrected in case of confusion

I mean I could've assumed it was the former, but you know, I like to be sure.
 
Dark-Carioca said:
That should probably be corrected in case of confusion

I mean I could've assumed it was the former, but you know, I like to be sure.
Click to expand...
It's not necessary, that's how every site and scientific article uses E#.
 
Haven't done all possible ways to destroy a vault door but (from what I've calced so far in my blog) for the smallest and biggest it doesn't vary much from Small Building level, to Building level, to City Block level and finally Island level or Large Island level
 
From this, we have:

  1. Energy to melt 1 cc iron = 7.874/55.845 * (25.1 * (1538 - 25) + 13810) = 7301.733838 J/cc
  2. Energy to vaporise 1 cc iron = 7.874/55.845 * (25.1 * (1538 - 25) + 13810 + 25.1 * (2862 - 1538) + 340000) = 59926.53315 J/cc
Try to plug it into your equation.

(And by the way we have melting and vaporisation value for 1 cc iron.)
 
How do you calculate ripping human arms/legs off? Or ripping the human body in half with bare hands?

I was always curious about it. But I could never find a way to calculate it no matter how many times I searched for it.
 
I think there is a calc for it based on numbers that have been given across history.

After all, tearing people's limbs off was a method of torture back in the old days.
 
Quentin Pimienta said:
How do you calculate ripping human arms/legs off? Or ripping the human body in half with bare hands?

I was always curious about it. But I could never find a way to calculate it no matter how many times I searched for it.
Click to expand...
Ripping a human head (with some backbones) off a human body with bare hands requires Leung Chun Ying <= 689,000 J AP with 1,000,000 N lifting strength to do so.

Dunno how this compares to ripping limbs or torsos off.


Also needs the human anatomy knowledge on vertically cutting a human in half. (I have done one horizontally cutting a human in half though)

And an ad on a draft for fire-based attack potency calculations by Spino
 
Also do we have a calc for covering the world in storm clouds? I know that was High 6-A before CAPE shenanigans
 
Is it possible to calc fire turning a human's entire body (bones and everything included) into ash nigh-instantly? Or bursting the inside of a building into flames that fire leaks out the windows?
 
Are there calculations for various natural disasters (hurricanes, tornados, earthquakes, tsunamis, etc.)?
 
Speed for running so fast that you leave behind a fire trail
 
I'm not sure if there is a reasonable speed that would leave behind a fire trail.

Considering that that usually happens in visual media, you should try just calcing the speed they ran on-screen.
 
Just a note, that mostly applies to running or punching near ground level. There are times where people appear to catch on fire despite falling as only Subsonic speeds; as most human reentry feats are simply Subsonic falling speeds getting Wall level results.
 
Ugarik said:
By the way we can not calculate the energy to destroy a particulas object from its volume like we do on this wiki. Only pulverization feats are correct
Click to expand...
I want to inform you that I still haven't changed my position about this and I'm going to create a revision thread sometimes soon regarding the problem.

I need to remind you that it will require to revise several thousands of profiles and verses if it gets accepted so I want to make sure if we not went to far usimg the wrong method and it's not too late to create such threads
 
Ugarik said:
Ugarik said:
By the way we can not calculate the energy to destroy a particulas object from its volume like we do on this wiki. Only pulverization feats are correct
Click to expand...
I want to inform you that I still haven't changed my position about this and I'm going to create a revision thread sometimes soon regarding the problem.

I need to remind you that it will require to revise several thousands of profiles and verses if it gets accepted so I want to make sure if we not went to far usimg the wrong method and it's not too late to create such threads
Click to expand...
Both DMUA and Bambu have already talked about this and it's pretty much the best we can do.
 
Ugarik is right that fragmentation values aren't 100% accurate because there are like many different levels of fragmentation severity; such as splitting in half vs shattering it into tiny pebbles. Plus, there's also the shape of the object to consider; a flat plate is easier to destroy than a solid sphere for instance.
 
I know but I can assure you that the method I'm going to present is way more accurate
 
Ok then, what is the method exactly and what units are going to be used with it? And what do you mean by tension of the material? Are you referring to its tensile strength?
 
Mind giving an example of how a calc would look with that?
 
There is a difference between hardness and toughness; like comparing a Diamond to Jade. Diamonds aren't as durable as people realize where as Jade is.
 
KLOL506 said:
Mind giving an example of how a calc would look with that?
Click to expand...
Same as before but the actual values are going to be very different (exept for metals)
 
So metals are unaffected by this revision then? This only applies to brittle objects like rock and the like, correct?
 
Also say there's a big cuboid rock pillar 5m tall, 3 m wide all over all over and it gets broken into multiple pieces. How do we calculate the energy needed to destroy it?
 
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