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Well this is fiction after all. And this is a metal we have no idea about and is even stated that it's not from Earth
 
the earth's mantle is solid but due to various factors such as the temperature difference between the Earth's surface and outer core , it behaves like a liquid
It behaving like a liquid doesn't change that Stoke's law is about solid substances interacting with fluids of a different particle amount in a uniform body of material. The fest occurs over multiple layers of the Earth with uneven material, the particles do interact with each other, and it's going through a solid most of the time rather than a liquid.


yes, in real life the earth would have been destroyed but this is fiction and does not follow this logic
Fiction doesn't follow logic but our calcs do. You cannot calculate a feat that involves an object exerting friction on the planet that's nearly ten billion times higher than the Earth's GBE.

1) exactly how the boros ship is able to withstand the impact of saitama
Because it's alien super metal, not something we have a tangible idea of how it works

ignoring the force of friction is not a viable option
We're not ignoring it, it's just the basis of your calc is flawed
 
even if my calculation is wrong
if you take into account the friction force the feat will surpass the energy required to destroy the earth

there is also the enormous pressure of the earth's mantle to consider
 
Wouldn't the pressure of the Earth's mantle be completely overwhelmed by the kind of power needed to perform the feat in the first place?
 
orochi's feat
i don't know how to post the calculation so i leave it here
1) I use the parameters used in the original calculation
2) the result exceeds the energy needed to destroy the earth, but this is NOT a problem because the object is not an explosion but is more like a bullet and is absorbed before leaving the earth's crust (considering its energy, had it not been absorbed it probably would have traveled into space for quite a while)

A) we need to find the formula to calculate the viscous friction
based on wikipedia https://en.wikipedia.org/wiki/Stokes'_law
- (sphere)
Re (reynolds' s number) = (2 * radius * speed * fluid density) / fluid viscosity
if Re <1 we can use the following formula to calculate the friction:
F (viscous friction force) = -6 * pi * viscosity * radius * speed
the viscosity of the upper terrestrial mantle varies from 10e + 19 to 10e + 24 (source wikipedia) and the lower mantle is denser than the upper one so for simplification I will use a lower average (10e + 22) even if it should be closer to 10e +24
I use the density of the earth because I could not find the specific one of the earth's mantle (there shouldn't be big differences) d = 5515 kg / m ^ 3
since the object starts from standstill and accelerates
to find the work we have to calculate the friction at the start and the friction at the end and then do the integral using the distance
then Re1 (stopped -> speed (v = 0)) = 2 * r * 0 * density / Viscosity = 0 (Re <1)
F1 = 0 (since it is a multiplication by 0)

Re2 = (2 * 366717.0236 * 3177965/20 * 5515) / 10e + 22 = 6e-8
Re <1 then we can use the above formula

but to calculate the integral:
speed (v) = space (d) / time
(F = -6pi * viscosity * radius * distance / time)

the object starts from d1 = 0 (starting space)
and arrives at d2 = 3177965 m (distance traveled / point of arrival)

work (joule) = force (= friction in this case in newtons) * displacement (m)
since the friction force changes according to the speed to find the work we have to calculate the following integral

integral from d1 to d2 of (F sd) = integral from 0 to d2 of -6pi * viscosity * radius * (d / t) ds
= Integral from d1 = 0 to d2 = 3177965 of -6pi * 10e + 22 * 366717.0236 * (d / 20)
using https://www.integral-calculator.com/
the result W (work) = -
+174441643610431532107500000000000000000000 joules
or 1.74e + 41 j
I hope I have not made some casting mistake in doing so
****
 
So even the original Low 5-B calc is unusable
It's unusable if we go with the idea that he absorbed thermal energy rather than a chunk of the inner core, since the fear is only as high as it is due to Kinetic Energy.
 
CmtikkM.png


Does anyone have the original kanji for this? I'd like to see a translated raw.
 
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I rechecked and you're right.


We don't see any major damage so I don't think we should assume higher. 5 to 6 does make sense. To anything in the tier 5 range feels kind of a reach.
We do see major damage, room-sized chunks of building are falling off and high rise buildings are falling over by the surface team. That's 8 at a minimum
 
At the very least the earthquake Orochi caused is magnitude 6, as Captain Mizuki says the quake was bigger than the previous one.
 
It was rejected before by assuming Fuhrer Ugly wasn't going all out against him

I don't agree with that, btw
Fuhrer Ugly's Low 7-B rating comes from him being vastly above high demon lvl monster, which are also Low 7-B. Why wouldn't Fuhrer be casually above demon levels when hes a Dragon lvl himself?
 
Fuhrer Ugly's Low 7-B rating comes from him being vastly above high demon lvl monster, which are also Low 7-B. Why wouldn't Fuhrer be casually above demon levels when hes a Dragon lvl himself?
I don't agree with the "not going all out" part, I agree with you, he should scale
 
Okay so here's a possible recalc I can do
Estimates of the total heat flow from Earth's interior to surface span a range of 43 to 49 terawatts (TW) (a terawatt is 10^12 watts).[10] One recent estimate is 47 TW,[1] equivalent to an average heat flux of 91.6 mW/m^2, and is based on more than 38,000 measurements. The respective mean heat flows of continental and oceanic crust are 70.9 and 105.4 mW/m2.[1]
Heat flux or thermal flux, sometimes also referred to as heat flux density[1], heat-flow density or heat flow rate intensity is a flow of energy per unit of area per unit of time.
So using my Orochi Calc
SA = 4πr^2

SA = 4 * π * (366,717.0236)^2

SA = 1,689,942,800,000 m^2

1,689,942,800,000 m^2 * 91.6 Megawatts/m^2 = 154,798,760,480,000 Megawatts or 1.5479876047999998e+20 Watts

Watts = Joules per second


1.5479876047999998e+20 Watts = 1.5479876047999998e+20 Joules per second (6-C)
So we add this to the Earthquake stuff and Orochi is downgraded to High 6-C or 6-A depending on which earthquake method we want to use.
 
Are we only using the earthquake feat and removing the magma pull?
The above is under the assumption Orochi absorbed the thermal energy rather than physically pulled a chunk of the inner core up
 
Finally home, I can scan some pages of the databook if you guys want. We have plenty of Spanish translators here. Any particular pages?

 
The lines would appear upwards first, I'm pretty sure, as it'd displace mass above. However, I doubt they'd be smeared and triangular, as if they'd been dragged separately.
 
It's in the process of being dragged out. I really don't get your point.
 
I'm not saying you're wrong about it being the tail, I'm just saying what you've given is hardly substantial.

Also, I was saying I don't get how it being displaced before the core is fully out proves anything. The sphere was already half-way out of the core.
 
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