DC Comics - 8-C Batman

[Chariot190]

I never said it'd be worse tho, I just said it'd be complicated
I just think it'd be low because he was very far.

 

[Transcending]

I never said it'd be worse tho, I just said it'd be complicated
I just think it'd be low because he was very far.

Aren't nukes extremely powerful? Even with the distance it could still help.

 

[KLOL506]

I never said it'd be worse tho, I just said it'd be complicated

Turns out, it isn't, you'd just use the surface burst LOL, you learn something new every day I guess

I just think it'd be low because he was very far.

But didn't we already calc Batman's distance from the bomb in the Sub? Like an Arm's length away by the visuals alone? Or are you talking about something else?

I think basically we'd need to use more usable metrics for measuring the boom diameter because the Submarine is at an angle, its top section however, should be at a more reliable angle to use.

 

[KLOL506]

Aren't nukes extremely powerful? Even with the distance it could still help.

Depends on whether we know where the nukes are or what type they are. If they are there to begin with.

 

[Chariot190]

Turns out, it isn't, you'd just use the surface burst LOL, you learn something new every day I guess


But didn't we already calc Batman's distance from the bomb in the Sub? Like an Arm's length away by the visuals alone? Or are you talking about something else?

I think basically we'd need to use more usable metrics for measuring the boom diameter because the Submarine is at an angle, its top section however, should be at a more reliable angle to use.

Aren't we talking about Red Hood being near that sub exploding?

 

[Transcending]

Turns out, it isn't, you'd just use the surface burst LOL, you learn something new every day I guess

Would you change the pressure value?

I think basically we'd need to use more usable metrics for measuring the boom diameter because the Submarine is at an angle, its top section however, should be at a more reliable angle to use

I had a few questions for you about that I asked in the blog, can you answer?

 

[Transcending]

Depends on whether we know where the nukes are or what type they are. If they are there to begin with.

The nuke was in the Submarine I believe. I don't remember the type.

 

[KLOL506]

Would you change the pressure value?

Prolly not, since we at the moment don't have a way to account for that massive pressure increase so the surface burst may as well be a low-ball at this rate.

I had a few questions for you about that I asked in the blog, can you answer?

I did.

Basically, we need a submarine that has a round front, front wings, x-stern with the propellor, side windows, and a top tower with the antennae.

 

[KLOL506]

The nuke was in the Submarine I believe. I don't remember the type.

'Kay so the torpedoes were apparently perfectly fine and they got launched after the sub blew up it seems, in Issue 12. Batman checks them up and watches them launch up close without warning.

 

[Transcending]

Prolly not, since we at the moment don't have a way to account for that massive pressure increase so the surface burst may as well be a low-ball at this rate.

Is there an average value or something similar we can use?

Basically, we need a submarine that has a round front, front wings, x-stern with the propellor, side windows, and a top tower with the antennae.

The only submarines I had in mind was Delfinen, Kronborg, and the U-class. If Delfinen or U-class can't work, I don't have any idea unless we use a submarine outside Denmark?

'Kay so the torpedoes were apparently perfectly fine and they got launched after the sub blew up it seems, in Issue 12. Batman checks them up and watches them launch up close without warning.

Wait, no. The bomb in Batman's submarine feat wasn't a nuke, I was referring to Red Hood.

 

[Transcending]

Batman still seems to be far away from the submarine.

Sorry about not clarifying but I wasn't referring to using Batman to calculate the tower, I was more referring to the Submarine's other properties such as height, length, or width. Unless those are in a bad angle too?

 

[KLOL506]

Is there an average value or something similar we can use?

Prolly just stick with ground-burst for the lack of better means.

The only submarines I had in mind was Delfinen, Kronborg, and the U-class. If Delfinen or U-class can't work, I don't have any idea unless we use a submarine outside Denmark?

The only other ones I can think of are US submarines. Maybe it's the "cavitation" tech's design that has been stolen from Denmark?

Wait, no. The bomb in Batman's submarine feat wasn't a nuke, I was referring to Red Hood.

Whups. My mistake then.

 

[Transcending]

The only other ones I can think of are US submarines. Maybe it's the "cavitation" tech's design that has been stolen from Denmark?

We can use a US submarine then. Would the Ohio work?

 

[Transcending]

Some bombs might exist beyond the walls so we can't see them but I will try to use the farthest bomb we can see.

Ok so from the fourth panel we can figure out the size of the bomb. Lincoln's head=59.14 pixels=0.23 metres. 0.23/59.14= 0.0038890767669935745. Bomb=22.93 pixels. 22.93*0.0038890767669935745= 0.08917653026716266m.

In the last panel, the bomb is 220 pixels high. Panel=309 pixels.

• Distance from point of view to object = 0.08917653026716266*309/[220*2*tan(70deg/2)]=0.08943954713703314

Now for Lincoln. Object(face) size=0.2 metres; Height= 30.02 pixels

• Distance from point of view to object = 0.2*309/[30.02*2*tan(70deg/2)]= 1.470012438651334

Distance between bomb and Lincoln= 1.470012438651334-0.08943954713703314=1.380572891514301m

Now for Bruce. Object size=0.2m; Height= 45.15 pixels

• Distance from point of view to object = 0.2 *309/[45.15*2*tan(70deg/2)]= 0.9774036192317398

Distance between bomb and Bruce= 0.9774036192317398-0.08943954713703314= 0.8879640720947066m

Now we just need to find out how many tons of TNT the bombs had to destroy the top of the tower. This also looks like a great speed feat for Bruce considering he outran the explosion.

 

[Chariot190]

Ok so from the third panel we can figure out the size of the bomb. Lincoln's head=59.14 pixels=0.23 metres. 0.23/59.14= 0.0038890767669935745. Bomb=22.93 pixels. 22.93*0.0038890767669935745= 0.08917653026716266m.

In the last panel, the bomb is 220 pixels high. Panel=309 pixels.

• Distance from point of view to object = 0.08917653026716266*309/[220*2*tan(70deg/2)]=0.08943954713703314

Now for Lincoln. Object(face) size=0.2 metres; Height= 30.02 pixels

• Distance from point of view to object = 0.2*309/[30.02*2*tan(70deg/2)]= 1.470012438651334

Distance between bomb and Lincoln= 1.470012438651334-0.08943954713703314=1.380572891514301m

Now for Bruce. Object size=0.2m; Height= 45.15 pixels

• Distance from point of view to object = 0.2 *309/[45.15*2*tan(70deg/2)]= 0.9774036192317398

Distance between bomb and Bruce= 0.9774036192317398-0.08943954713703314= 0.8879640720947066m

Now we just need to find out how many tons of TNT the bombs had to destroy the top of the tower. This also looks like a great speed feat for Bruce considering he outran the explosion.

Add an extra step, angsize the distance between the bomb and one of the three bombs on the foundation (doesnt matter which), that should, in theory be the furthest possible distance they could have been, that could work as the minimum as there's also bombs closer to them.

 

[Transcending]

Add an extra step, angsize the distance between the bomb and one of the three bombs on the foundation (doesnt matter which), that should, in theory be the furthest possible distance they could have been, that could work as the minimum as there's also bombs closer to them.

They are on different panels though

 

[Chariot190]

This one.
And yeah it might be a different panel, but it's also the same bomb you scaled the distance between Bruce and it already.

So now you just scale the distance from the back bombs to that bomb, and you'd have the distance of Bruce to that bomb by adding it together.

Alternatively you could be absolutely insane and try to get that distance for every bomb, but the furthest would work as the minimum low end (Or maybe you could average them out? Idk maybe KLOL has a solution that wouldn't require jumping through hoops).

 

[Transcending]

This one.
And yeah it might be a different panel, but it's also the same bomb you scaled the distance between Bruce and it already.

So now you just scale the distance from the back bombs to that bomb, and you'd have the distance of Bruce to that bomb by adding it together.

Alternatively you could be absolutely insane and try to get that distance for every bomb, but the furthest would work as the minimum low end (Or maybe you could average them out? Idk maybe KLOL has a solution that wouldn't require jumping through hoops).

Alright.

Object size can be the same as before. Object height= 130 pixels, panel height= 298 pixels.

• Distance from point of view to object = 0.08917653026716266 *298/[130*2*tan(70deg/2)]= 0.14597104083405257

Object height of the farther bomb= 12 pixels.

• Distance from point of view to object = 0.08917653026716266 *298/[12*2*tan(70deg/2)]=1.581352942368903

Distance between them= 1.581352942368903-0.14597104083405257= 1.4353819015348503 metres

 

[KLOL506]

Mainly the current feats we have just need to be evaluated. Other than that, @KLOL506 is currently calcing the tripwire feat and doing ISL part of the boat feat.

Can you link me to the boat calc comment?

 

[Transcending]

Can you link me to the boat calc comment?

Sure

In that case I will do a calc assuming the entire boat is made of steel, and another where I calculate the yield of the explosion.

Calc 1- Steel

First we need the volume of the boat, but it has a weird shape so finding an accurate volume is impossible. However, we could get a rough result. First we need Batman's arm length. Arm length is generally 44% of body height. Bats is 1.88 m, so (1.88 * .44)= 0.8272 m= 82.72 cm.

In the scan Batman's arm is 105.69 pixels long. 82.72/105.69=0.7826662882013435.


Now for the Submarine. Length=570.14 pixels. So 570.14*0.7826662882013435=446.229357555114cm

Width=250.81 pixels; 250.81*0.7826662882013435=196.30053174377898cm

Height=47.17 pixels; 47.17*0.7826662882013435= 36.918368814457374cm

Volume=446.229357555114*196.30053174377898*36.918368814457374= 3233866.7375977174cc

The explosion either fragmented or violently fragmented the boat. I will do both.

Frag- 208*3233866.7375977174= 672644281.4203253 Joules= 0.16076584163966 tons of TNT. 9-A+

V.frag- 568.5*3233866.7375977174= 1838453240.3243024 Joules= 0.43940087005839 tons of TNT. 8-C

Calc might be a bit wacky tho


Calc 2- Yield

Batman's leg is 22.34 pixels long. Legs are generally half of body height. Batman is 188cm so 188/2=94. 94/22.34=4.207699194270367. The explosion has a diameter of 189 pixels, so 189*4.207699194270367=795.2551477170994. Halve that and you get 397.6275738585497 centimetres which is the radius.

Applying the surface burst formula would get you 0.005052600901613905 tons of TNT. Barely into 9-A

Using either calc, considering Batman no-sold this while heavily weakened and in his first year(or second, don't remember), I would say this supports 8-C.

 

[Chariot190]

Alright.

Object size can be the same as before. Object height= 130 pixels, panel height= 298 pixels.

• Distance from point of view to object = 0.08917653026716266 *298/[130*2*tan(70deg/2)]= 0.14597104083405257

Object height of the farther bomb= 12 pixels.

• Distance from point of view to object = 0.08917653026716266 *298/[12*2*tan(70deg/2)]=1.581352942368903

Distance between them= 1.581352942368903-0.14597104083405257= 1.4353819015348503 metres

Ok now we just need to calc the blast, if nobody does it by the time I get back home I will, it should be just a simple case of scaling it off the building itself.

 

[Transcending]

Ok now we just need to calc the blast, if nobody does it by the time I get back home I will, it should be just a simple case of scaling it off the building itself.

Awesome, I will try calcing Batman's submarine feat with Ohio-class submarines

 

[KLOL506]

Sure

Hmmmmmm, given the wonkiness of those dimensions of the boat (Multiple holes on it), I'd just chalk it up to being comparable to car-busting minus the tires (Since it does look weirdly like a car with not enough plastic or wood to go around), and given that the boat has bat-themed body work, I can easily bet 50 bucks it's gonna have armor protection in one way or another. So ye, massively lower with the holes and all, but eh. You could try your luck and swap in the normal steel parts with some type of armor steel that won't sink the boat instantly.

 

[Transcending]

Hmmmmmm, given the wonkiness of those dimensions of the boat (Multiple holes on it), I'd just chalk it up to being comparable to car-busting minus the tires (Since it does look weirdly like a car with not enough plastic or wood to go around), and given that the boat has bat-themed body work, I can easily bet 50 bucks it's gonna have armor protection in one way or another. So ye, massively lower with the holes and all, but eh. You could try your luck and swap in the normal steel parts with some type of armor steel that won't sink the boat instantly.

I think that's too complicated, that's why I also made the second calc calculating the yield

 

[KLOL506]

I think that's too complicated, that's why I also made the second calc calculating the yield

Ah.

You made your blue line too long (It should stop at the heel), and measuring the explosion at its base would be more accurate.

Fortunately, I've already done my side of the work. I got better values for the explosion.

But inverse-square law nukes it to 9-B+.

 

[Transcending]

Ah.

You made your blue line too long (It should stop at the heel), and measuring the explosion at its base would be more accurate.

Fortunately, I've already done my side of the work. I got better values for the explosion.

But inverse-square law nukes it to 9-B+.

Well that sucks. That means the only feats left are:

1: Batman's tower explosion

2: Submarine recalc

3: Red Hood surviving the nuke

4: Deathstroke killing a country

5: Killer Croc survives an underground explosion(?)

6: Batman's tripwire feat

For Red Hood, finding his distance seems to be easy, we just need the explosion's yield. For Deathstroke, we need the distance and the yield.

 

[Antvasima]

Thank you to everybody who are helping out here.

 

[Chariot190]

Got 95.7m on the blast for the Owlman feat (I would've used the height of the tower but I couldn't find a official height for it on the database, it's called Crowne Tower tho), but I'm gonna try like five different methods given there's a few ways we can scale it. Ill toss all the methods and scaling in a sandbox after and we can decide which scale to use.

Edit: Fyi if we go with that that initial scaling, it'd make the feat about 0.70 tons for Owlman.

 

[KLOL506]

Well that sucks.

I spoke too soon.

I fixed up the pixel-scaling a bit on my part. Goes just a tiny bit above baseline 9-A.

 

[Transcending]

I spoke too soon.

I fixed up the pixel-scaling a bit on my part. Goes just a tiny bit above baseline 9-A.

Oh nice! That helps.

 

[KLOL506]

Will upload my two Batman calcs at the earliest tomorrow.

 

[Transcending]

Will upload my two Batman calcs at the earliest tomorrow.

Thank you

 

[Transcending]

Alright, I finished my Ohio calc but I personally don't trust it, since the diameter of the explosion would turn out to be less than half of the Submarine's length, which is demonstrably false.

Submarine's length= 1711 pixels. Ohio Submarines are 170m, so 170/1711=0.09935710111046171. The tower is 65 pixels high(don't worry about the difference in coloring, I accidentally changed the color to green when writing it lol). 0.09935710111046171*65=6.458211572180011m

Now coming to the comic

Tower=221 pixels. 6.458211572180011/221=0.029222676797194622. The explosion has a diameter of 2247.1 pixels, 0.029222676797194622*2247.1=65.66627703097603m. 65.66627703097603/2=32.83313851548802m.

W = 32.83313851548802^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2= 2.844609865147736 tons of TNT.

Now comes ISL. In the feat, Bats seems to be an arm's length away from the explosion. Arm length is generally 44% of body height. Bats is 1.88 m, so (1.88 * .44)= 0.8272 m from epicenter.

• I = (2.844609865147736 ) / (4π((0.8272)^2))=0.3308200297173242 tons of TNT

Last comes CA.
Batman is 210 lbs and 1.88 meters as per the DC Comics Encyclopedia. Dumping the values here, we get a surface area of 2.23 m^2. We need the cross-sectional area. Which is usually 40-50% that of total surface area. But given Batman's bulk, 50% sounds about right.

2.23 * 0.5 = 1.115 m^2

Final Yield taken by Batman= 0.3308200297173242*1.115= 0.3688643331348165 tons of TNT

Still Building Level.

Considering the calc is a lowball and we still got 8-C results, I think this pretty much confirms this feat is 8-C. If this is a major lowball, I recommend calcing the tower with this scan(using the Submarine's length or something, unless it's in a bad angle too) or use the OG calc.

 

[Chariot190]

Just so I don't have to plug the numbers like five times via multiple scaling methods for two different explosions.


Which one do we wanna go with. A or B, B is a longer, I just wasn't sure what we want to qualify as the initial blast or not, basically from which point to point, I feel either could work, though obviously B would give better results, A is also safer.

 

[Hellbeast]

I feel A makes more sense

 

[Transcending]

Just so I don't have to plug the numbers like five times via multiple scaling methods for two different explosions.


Which one do we wanna go with. A or B, B is a longer, I just wasn't sure what we want to qualify as the initial blast or not, basically from which point to point, I feel either could work, though obviously B would give better results, A is also safer.

I feel like B qualifies as the initial blast too but A is also fine.

 

[Hellbeast]

This should work if Bruce tanked the blast

 

[Chariot190]

This should work if Bruce tanked the blast

He didn't, he took a small one and then hauled ass and escaped before the big one went off (Works as a speed feat tho. The sandbox doc doesn't include a page, where Batman gougues Owlman's eyes out to make him loosen his grip and he escapes), wasn't even touched by the large blast.
But Owlman was engulfed completely, and shown as such and curses Batman while everything explodes. Which last I checked, he survived that and shows up later.

So either way.

Anyway I've done like all the pixel scaling and various methods but it's late so I'll sandbox it tomorrow morning.

 

[Transcending]

He didn't, he took a small one and then hauled ass and escaped before the big one went off (Works as a speed feat tho. The sandbox doc doesn't include a page, where Batman gougues Owlman's eyes out to make him loosen his grip and he escapes), wasn't even touched by the large blast.
But Owlman was engulfed completely, and shown as such and curses Batman while everything explodes. Which last I checked, he survived that and shows up later.

So either way.

Anyway I've done like all the pixel scaling and various methods but it's late so I'll sandbox it tomorrow morning.

Can you also post your IF calc?

 

[Spinosaurus75DinosaurFan]

What are the list of calculations for a potential upgrade?

I did calculate a bunch of Tier 8 range feats for DC street tiers a while ago, but a kinda general unspoken rule is that explosions are not very reliable for tiering comic characters.