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Shouldn't you subtract the KE of natural moon velocity from the KE obtained by adding a single meter per second? I bet it will get much lower than 5-C if you take into account the energy ADDED to the moon rather than its total energy.WeeklyBattles said:@Drag It comes from math
Mass of the moon = 7.34767309 × 1022 kilograms
Speed of the moon = 1023.056 m/s
1 m/s faster would put it at (Round figures) 1024 m/s
KE = 1/2M x V^2 = 3.6738365e+22 x 1048576 = 3.8522968e+28 Joules
As this is literally the absolute lowest end possible and would only need to be slightly faster to be 5-C, 5-C is completely acceptable for moving the moon