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You can use the equation Kachon gave to find the initial rKE and final rKE, then take the difference in those to find the energy the character applied.how i can calculate change (not stop) in the rotation of earth and saturn?
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You can use the equation Kachon gave to find the initial rKE and final rKE, then take the difference in those to find the energy the character applied.how i can calculate change (not stop) in the rotation of earth and saturn?
OKYou can use the equation Kachon gave to find the initial rKE and final rKE, then take the difference in those to find the energy the character applied.
What do you mean?ALSO, I can calculate the distance from one planet to another using the time it takes for a Normal rocket to arrive?
apparently the distance between earth and mars in a verse is different from ours, since a rocket designed by a NASA expert took 10 years to get from earth to marsWhat do you mean?
Basically follow the instructions on this thread, and post the necessary details on your post so that the calc members will know about it.Hey, just wanted to ask, also I'm sorry if this isn't the right thread, but how do you request a calculation evaluation? I made this calculation blog, and I want someone to evaluate it before it gets used. Could anyone help me?
Find the area of the split in m^2 (A)A character causes the ground to rip open and splits it in two halfs
How do I calc that?
Hey, hey, fanta here. Anybody has any idea on how I can calc this feat?
Question. On what you said to answer Emerald's question, does it apply to my question as well? Or just a slightly different variation of the formula you gave?
Find the radius of the crater (length-wise)
Find the depth (just use the average thickness of a person their age's back)
Since the crater is a half-ellipsoid, use this formula to find the volume of the crater: 2/3*pi*r*r*d = answer in cm^3
Multiply the volume by 655 J/cc (average destruction value of steel) and that is the result in Joules
This is yield strength, not v. frag. The steel panel's linework is also relatively intact, if it was v. fragged something that thin would be torn to tiny metal shards.Find the radius of the crater (length-wise)
Find the depth (just use the average thickness of a person their age's back)
Since the crater is a half-ellipsoid, use this formula to find the volume of the crater: 2/3*pi*r*r*d = answer in cm^3
Multiply the volume by 655 J/cc (average destruction value of steel) and that is the result in Joules
We don't allow that method for splits or cutting feats like this anymore. It was rejected on the Demon Slayer cutting blog.Find the area of the split in m^2 (A)
Multiply A by 60 Mpa (60000000 N/m2)
Multiple that by the value to change tensile to shear force 0.6
Multiply your answer by diameter of the total area displaced (∆x)
The final formula would look like this: (A*60000000*.6)∆x = answer in Joules
I used pulv.This is yield strength, not v. frag. The steel panel's linework is also relatively intact, if it was v. fragged something that thin would be torn to tiny metal shards.
Should've used yield strength instead. Pulv would've turned it to dust and would've left behind no fragments.I used pulv.
Use yield strength. Best for denting metal feats.So what should I do here? Use frag instead or some other method?
Can you send the featdo we calc the reversal of the sides of the earth (Making north into south and south into north) as rotation calc?
Can you send the text? I'm having a hard time understanding what you mean.I got a hypothetical question that needs to be answered. Say you have a feat that has one character destroy something. In text, so no visuals, however, the thing in question that was destroyed was described as something that can be found in real-life and you can use low-ball height and width, but, well... can't find thickness/depth anywhere since there is no standard for it irl.
What can I do? Just assume the thickness of whatever body part was used to break the thing, or is there some other way?
Here you go. If you don't want to follow the link, basically, a character jumped out of a vehicle to slam forehead-first into the side window of a school bus to break through it and get inside said bus. From my own research, bus windows, are made out of tempered glass, so it should be calc it by using the frag values for ballistic glass or smth, according to a convo I had with KLOL a while back.
Yeah that would work.Should I just assume the width and thickness is the same, for simplicity's sake?
The crater is caused by the shockwave of K'Sante's blow sending the creature flying, afaik he doesnt have a canon height yet but maybe average human height could doCan probably do the crater if the creature that made it has a canon height - or if it was standing and/or nearby a character with a canon height in another shot - but don't think the cloud feat can be calced atm due to cloud revisions
He looks quite big so I would go for the size of average strongmenThe crater is caused by the shockwave of K'Sante sending the creature flying, afaik he doesnt have a canon height yet but maybe average human height could do
this (Yeah I already made a thread where it was accepted to use the series, if you ask), Keep in mind that he only gave the thrust, the rest of the planets were moved by the generated thrust and the connection of the planets, so it only scales to the first moments of the movement, the rest I(with help of @DarlingAurora) have already calculated as preparation/chain reactionCan you send the feat
Find the circumference of the Earth, divide that by two, find a timeframe, and then use Kinetic Energy formula.this (Yeah I already made a thread where it was accepted to use the series, if you ask), Keep in mind that he only gave the thrust, the rest of the planets were moved by the generated thrust and the connection of the planets, so it only scales to the first moments of the movement, the rest I(with help of @DarlingAurora) have already calculated as preparation/chain reaction
okFind the circumference of the Earth, divide that by two, find a timeframe, and then use Kinetic Energy formula.
Is it well done or not?Find the circumference of the Earth, divide that by two, find a timeframe, and then use Kinetic Energy formula.
Looks goodIs it well done or not?
the circumference of the Earth is 40,075 km | 40,075,000 m
now divide that by two 40,075,000/2=20,037,500
Timeframe: 08:42:42-08:41:09=1.33/20,037,500=15065789.5m
Earth Mass: 5.972 × 10^24 kg
K.E. = 1/2 m v2
K.E= 1/2*5.97200e24*15065789.5^2=6.77756348e38 J or 161.987655 Ninatos (Nigh 5-A)
ok i'll put it on a blogLooks good
How would I go about trying to calculate something like this? (Feat is from Infinite Leveling: Murim, Chapter 8)