- 1,315
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Okay, thanks
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Official Calculations Discussion Thread
- Thread starter Antvasima
- Start date
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- Tags
- vs battles wiki
- 2,341
- 2,140
They don't, really. Take Z Vegeta for example. A lot of his keys have him at hypersonic flight speed with FTL or MFTL combat (and thus reaction) speed. Unless they're shown to scale (i.e dodging things while moving at MFTL+ speeds would give you MFTL+ reactions/combat speed), they're taken as separate.
Arkenis
They/Them- 17,083
- 7,873
Not what I'm asking. I'm asking how the values correlate to one another, how Transonic speeds relate to Transonic reaction values.
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It appears to just be 1/speed. Baseline supersonic speed is 377.3m/s, 1/that is 0.00265s, just as it is in the reactions page.
Arkenis
They/Them- 17,083
- 7,873
Can just use a calc converter
- 6,900
- 1,321
- 18,784
- 13,800
What do we use as an average of the number of stars a constellation has?
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What feat are you trying to calculate? I think info/context is needed, especially when dealing with star stuff.
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Let's maybe use Ursa Major or Orion as an example
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I think it still needs more info. Did someone blow up the constellation? Did someone use TK to move the entire thing? If so, how fast did they move it? etc.
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It'd probably be at LEAST baseline 4-C because it explicitly says he encapulates stars, meaning ones that already exist from the sky.They shoot stars... And... I'll just give the text
I guess to make a constellation you could do it like this calc where he used the nearest constellation to Earth, found the center, found the edge then used inverse-square law for an explosion.
- 18,784
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Well can't I just use average amount of stars a constellation has and then with that just kinda combine everything to one result?
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Can't I just use our star/sun for the constellation? Says here it's about an average star
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Nope. If that guy is from Earth, you could honestly just use that calculation and change nothing.Well can't I just use average amount of stars a constellation has and then with that just kinda combine everything to one result?
That Calc has to many numbers/equations for me...
- 18,784
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Well he's not really from earth... The monsters can come from anywhere, different galaxy, from hell, from heaven and stuff
There's one monster tho who carries earth
We don't know where he's from I think.. Just that he's an intergalactic pyrotechnician
That's why I think just using average star size and average amount of stars in a constellation is good enough I think
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But that's just not how the math works, lol. If you create or destroy something on a celestial scale (i.e planets and stars etc.) you have to do it properly, with inverse-square law and everything. I'd use that calc as it's a safe lowball, using the closest constellation to Earth and the stars in that.
damn... So I have to learn/be able to understand that to do it? 
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Appears to be about the GBE of Uranus. I calculated it myself and got approx. 2.84 yottatons so I'd imagine it's a matter of using more accurate values. That really should be listed on the page, though.
Arkenis
They/Them- 17,083
- 7,873
Think it's the only tier that doesnt have a standard value once u get to tier 5. Could u do a calc for me though?
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Depends what it is, but sure.
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Ok... So, someone has the strength of a thousand seas... , use average sea size then find it's mass then times 999?
, use average sea size then find it's mass then times 999?
Oliver_de_jesus
He/Him- 24,724
- 17,761
Why not 1000?Ok... So, someone has the strength of a thousand seas...
Like 999*1=999
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No... Since its a thousand seas... I use 1 average sea's size and then mass... Which will count for 1 out of 1000 seas... So then I just times that by 999x?
That's not how you do it?
As in the result of an average sea's mass gets times 999
azontr
He/Him- 40,580
- 50,192
Its not. You multiply it by 1000.That's not how you do it?
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... Really? But aren't you already accounting 1 sea when finding the result of it's mass?
azontr
He/Him- 40,580
- 50,192
That's... not how multiplication works. You're thinking your adding 999 to 1, you're not, you're multiplying 1 by 1000.
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You really sure? How doesn't finding the result of an average sea not already make/add it within the one thousand seas?
It's not like he achieved 1000x more seas or strength... He is the 1000 seas
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If I have 1 bottle of water and I get 4 more, I went from 1 to 5. That is a 5x increase.You really sure? How doesn't finding the result of an average sea not already make/add it within the one thousand seas?
It's not like he achieved 1000x more seas or strength... He is the 1000 seas
If I have 1 bottle and get 999 more, I went from 1 to 1000. That is a 1000x increase.
azontr
He/Him- 40,580
- 50,192
You really sure? How doesn't finding the result of an average sea not already make/add it within the one thousand seas?
It's not like he achieved 1000x more seas or strength... He is the 1000 seas
^
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... And what if you took one bottle of water from the 1000 of water bottles to taste one of it... You liked it and now you want 999 more
Why doesn't that make sense? Wait I think I'm understanding what you mean... 1 = 54636 x 1000 = 54636000
oh so the 1 is already accounted for in the equation with the 1000x
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So I use this
en.wikipedia.org
Find the average and then find the mass and then times that by 1000?
6,950,002,000kg?
List of seas on Earth - Wikipedia
Find the average and then find the mass and then times that by 1000?
6,950,002,000kg?
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That is a list of seas by area, not their mass. Ideally you'd want a list of seas by volume, but I can't find that.So I use this
List of seas on Earth - Wikipedia
Find the average and then find the mass and then times that by 1000?
6,950,002,000kg?
Average ocean depth is 3688m or 3.688km. I'd be conservative and lowball by taking the smallest sea listed there, the Adriatic Sea at 138,000 km^2.
Multiply that by average depth to get a volume of 508944km^3.
Convert to m^3, 5.08944e14 m^3.
Multiply THAT by 1000 (because water has a density of 1000kg/m^3) to get your mass, 5.08944e17 kg or Class P.
Oh, and for the record, most sources I found said tsunamis had an energy of AROUND 3 * 10^15 J (another source, see the log diagrams) or within an order of magnitude, which is about 750 Kilotons, High 7-C+.
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Mmm ...
...
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@SeijiSetto I personally would like to know the basis of all the values up to High 6-A
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No clue. Try re-arranging the ground based explosion formula to make the radius the subject, then comparing the area of a circle with said radius to the thing being destroyed.
