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Got a way to calculate the sun eruption feat.
Assuming that the average size of a solar flare is 100000 km and the higher end is 500000 km
With the total surface area of the sun being 6.088 x 10¹² km² or 3.7063744 x 10²⁵ km
Low end= 3.7063744 x 10²⁵ km / 100000 km = the surface area of the sun is 3.7063744 x 10²⁰ times larger than an average solar flare .
3.7063744 x 10²⁰ x 10²⁰ = 3.7063744 x 10⁴⁰ joules (small star level)
High end = 3.7063744 x 10²⁵ km / 500000 km = the surface area of the sun is 7.4127488 x 10¹⁹ times larger than an above average solar flare.
7.4127488 x 10¹⁹ x 10²⁵ = 7.4127488 x 10⁴⁴ joules (large star level)
Assuming that the average size of a solar flare is 100000 km and the higher end is 500000 km
With the total surface area of the sun being 6.088 x 10¹² km² or 3.7063744 x 10²⁵ km
Low end= 3.7063744 x 10²⁵ km / 100000 km = the surface area of the sun is 3.7063744 x 10²⁰ times larger than an average solar flare .
3.7063744 x 10²⁰ x 10²⁰ = 3.7063744 x 10⁴⁰ joules (small star level)
High end = 3.7063744 x 10²⁵ km / 500000 km = the surface area of the sun is 7.4127488 x 10¹⁹ times larger than an above average solar flare.
7.4127488 x 10¹⁹ x 10²⁵ = 7.4127488 x 10⁴⁴ joules (large star level)