How powerful is this?

[The_real_cal_howard]

A character directly compares his teleportation to E=mc^2, where m is the mass of the things being teleported, and the total energy is multiplied by the distance travelled in meters. The character is then has to teleport six people, including himself (three 18 yo girls, three 18 yo boys), and the distance is two light years past Pluto.

What is the energy expended in that teleportation?

 

[Reppuzan]

I mean, you're the math guy not me.

What are the masses of the characters here?

 

[The_real_cal_howard]

Girls: 90, 105, 120

Boys: 105, 145, 200

 

[Amelia_Lonelyheart]

Let's see. Average male weight seems to be around 84.0 kg. Apparently the average female is around 45.5 kg

84.0 * 3 = 252 kg

45.5 * 3 = 136.5 kg

So a total of 388.5

Earth-Pluto distance is 7,500,000,000,000 meters

Adding two light years yields 1.89285568 × 10^16 meters

1.89285568 × 10^16 * 388.5 = 7.3537443e+18 kg

7.3537443e+18 * 2.998e+8^2 = 6.6095483e+35 J

157.971 Yottatons

Huh, disappointing.

 

[Reppuzan]

Then wouldn't it just be a matter of adding the values and plugging them into the formula?

90+105+120+105+145+200 = 765 pounds (I'm assuming, you didn't provide units but it looks way too high to be kg).

765 lb = 347 kg.

347 kg * c^2 = 3.11868047 × 10^19 J. = Island level

Why would we count this for AP anyhow?

 

[Amelia_Lonelyheart]

Oh I misread the OP. I thoght it was the mass times that insane value, not the energy. Well, taking Repp's value then, I guess.

10^19 * 1.89285568 × 10^16 = 1.8928557e+35 J

45.2 Yotta

 

[Reppuzan]

This theoretical or for an actual character?

 

[The_real_cal_howard]

Theoretical for a character of mine.