Calcing running pace at incoming projectile?

[CNBA3]

Just like with the thread I made about outrunning a projectile:

https://vsbattles.com/threads/calc-for-outrunning-something.147800/

With how (Distance moved by character x Projectile Velocity) / Distance Moved by Projectile from Muzzle = speed of character

I was wondering, is using the formula for the reverse is true a person running past the source when the projectile reached a distance?


If so, what would the proper formula be for finding the speed of a character if they had to outpace and dodge two projectiles from opposite directions at the same speed and same distance from each other? In this case, shockwaves (lightspeed both).

Here is a little visual below to hopefully give a proper understanding.

(0 meters) A --- --- ---> B (3 meters)
~~~~(1 meter) P>~~~~~~Final destination (3.1 meters)
(0 meters) A<--- --- --- B (3 meters)

 

[CNBA3]

from my attempt to do this, it would be either two ways:

1. First, it would be the same calc as before to outrun a feat but times 2 since he is dodging two shockwaves at both ends.
   1. (2.1 x 299,792,458) / 3 = 209854720.6 * 2 = 419709441.2 m/s = 1.4 c
2. Second would be to apply the added distance the person would need to dodge an incoming shockwave (which would be roughly 3 meters high)
   1. so taking the distance traveled and with the height to find the distance from dodging from above to below an incoming SW triangle style
      1. base 2.1 meters, height 3.1 = the other two sides is roughly 3.27 * 2 = 6.54 meters
   2. then adding that to the usual formula, (6.54 x 299,792,458) / 3 = 653547558.44 = 2.18 c

thoughts?

@KLOL506

 

[CNBA3]

Bump