Shaking The Earth Reloaded

[ByAsura]

This calculation is currently Small Country level, but it assumes the radius of the earthquake is half the circumference of the planet.

That's not how it'd work, though, because earthquakes/quakes (unless stated otherwise) travel radially from a centre point (presumably because that's just how conservation of ******* energy works) as per the inverse-square law, so the energy would be travelling through matter rather than somehow circumnavigating the planet through even more matter. The longest possible distance for the radiated energy, in that case, can only be a maximum of 12,742 km.

I'd show a diagram or something, but idk how to make gifs.

Keep in mind, this is for a quake (or merely just radiated waves) with or without any tectonic movement involved, and it'd technically apply to other calculations with distances surpassing 12,742 km.

(4)+6.399+1.66×log((12,742÷110)×((2×π)÷360)) = 10.9064989901

10^(1.5*(10.9064989901)+4.8) = 1.4446029e+21 J, or 345.26838176 gigatons (Large Island level)

 

[KLOL506]

There's a better way to do this.

Good old KE using Intensity Intensity scale and using that to get velocity via the Mercalli scale. Intensity V (Felt by Nearly Everyone), so the lowest speed is 4.65 cm/s or 0.0465 m/s.

Mass of Earth being 5.972e+24 kg...

KE: 0.5 * 5.972e+24 * 0.0465^2 = 6.4564785e+21 J or 1.54313539675 teratons of TNT (Small Country level)

LOL, actually higher than what we have right now.

This formula works for literally any kind of celestial body, it's how we calc'd shaking the Moon because it has no tectonic plates.

 

[ByAsura]

bruh, how dare you withhold this knowledge until now

 

[KLOL506]

bruh, how dare you withhold this knowledge until now

I only just realized it now brother

 

[Shmeatywerbenmanjenson]

There's a better way to do this.

Good old KE using Intensity Intensity scale and using that to get velocity via the Mercalli scale. Intensity V (Felt by Nearly Everyone), so the lowest speed is 4.65 cm/s or 0.0465 m/s.

Mass of Earth being 5.972e+24 kg...

KE: 0.5 * 5.972e+24 * 0.0465^2 = 6.4564785e+21 J or 1.54313539675 teratons of TNT (Small Country level)

LOL, actually higher than what we have right now.

This formula works for literally any kind of celestial body, it's how we calc'd shaking the Moon because it has no tectonic plates.

I'm all for updating the current calc with this new version

However doesn't this mean that the entire earthquake calculations page needs to be updated using this method as a new base?

 

[KLOL506]

I'm all for updating the current calc with this new version

However doesn't this mean that the entire earthquake calculations page needs to be updated using this method as a new base?

Nah, the only issue here was the distance used.

 

[KLOL506]

There's a better way to do this.

Good old KE using Intensity Intensity scale and using that to get velocity via the Mercalli scale. Intensity V (Felt by Nearly Everyone), so the lowest speed is 4.65 cm/s or 0.0465 m/s.

Mass of Earth being 5.972e+24 kg...

KE: 0.5 * 5.972e+24 * 0.0465^2 = 6.4564785e+21 J or 1.54313539675 teratons of TNT (Small Country level)

LOL, actually higher than what we have right now.

This formula works for literally any kind of celestial body, it's how we calc'd shaking the Moon because it has no tectonic plates.

@Dark-Carioca @AbaddonTheDisappointment @DemonGodMitchAubin @Migue79 @CloverDragon03 @Aguywhodoesthings @Dalesean027 @DMUA @Armorchompy @Therefir @Mr._Bambu @Psychomaster35 @TheRustyOne @DemiiPowa @DontTalkDT @Executor_N0 What do you think of this new version?

 

[Migue79]

I say KLOL's method checks out.

 

[TheUnshakableOne]

@Dark-Carioca @AbaddonTheDisappointment @DemonGodMitchAubin @Migue79 @CloverDragon03 @Aguywhodoesthings @Dalesean027 @DMUA @Armorchompy @Therefir @Mr._Bambu @Psychomaster35 @TheRustyOne @DemiiPowa @DontTalkDT @Executor_N0 What do you think of this new version?

Just to be sure this won't change how shaking a galaxy or universe is calculated will it?

 

[KLOL506]

Just to be sure this won't change how shaking a galaxy or universe is calculated will it?

Nah, they won't be affected, those require vastly different formulae.

 

[TheUnshakableOne]

Nah, they won't be affected, those require vastly different formulae.

I saw DT use DMUA's global earthquake block for calc'ing energy yielding of shaking a galaxy. So, its possible some calcs could be affected?

Shaking the Galaxy (Platinum Wings Accelerator calc)

vsbattles.fandom.com

This is why i asked lol

Also because there is a character that shakes the Galaxy that i need to calc but im too lazy and doing other things for that verse atm

 

[KLOL506]

I saw DT use DMUA's global earthquake block for calc'ing energy yielding of shaking a galaxy. So, its possible some calcs could be affected?

Shaking the Galaxy (Platinum Wings Accelerator calc)

vsbattles.fandom.com

This is why i asked lol

Also because there is a character that shakes the Galaxy that i need to calc but im too lazy and doing other things for that verse atm

Nah, just that the Earth value there gets swapped with the new one, since that one is still using the good-old-fashioned inverse-square law but reversed LMAO

 

[AbaddonTheDisappointment]

KLOL’s seems fine to me

 

[KLOL506]

Bump

@Dark-Carioca @DemonGodMitchAubin @CloverDragon03 @Aguywhodoesthings @Dalesean027 @DMUA @Armorchompy @Therefir @Mr._Bambu @Psychomaster35 @TheRustyOne @DemiiPowa @DontTalkDT @Executor_N0 Would you be able to evaluate this?

There's a better way to do this.

Good old KE using Intensity Intensity scale and using that to get velocity via the Mercalli scale. Intensity V (Felt by Nearly Everyone), so the lowest speed is 4.65 cm/s or 0.0465 m/s.

Mass of Earth being 5.972e+24 kg...

KE: 0.5 * 5.972e+24 * 0.0465^2 = 6.4564785e+21 J or 1.54313539675 teratons of TNT (Small Country level)

LOL, actually higher than what we have right now.

This formula works for literally any kind of celestial body, it's how we calc'd shaking the Moon because it has no tectonic plates.

 

[Dalesean027]

Seems fine to me

 

[Arkenis]

What does this change for the levels of radiated waves? say Magnitude 2?

 

[KLOL506]

What does this change for the levels of radiated waves? say Magnitude 2?

It doesn't.

 

[Dark-Carioca]

KLOL's is fine

 

[KLOL506]

There's a better way to do this.

Good old KE using Intensity Intensity scale and using that to get velocity via the Mercalli scale. Intensity V (Felt by Nearly Everyone), so the lowest speed is 4.65 cm/s or 0.0465 m/s.

Mass of Earth being 5.972e+24 kg...

KE: 0.5 * 5.972e+24 * 0.0465^2 = 6.4564785e+21 J or 1.54313539675 teratons of TNT (Small Country level)

LOL, actually higher than what we have right now.

This formula works for literally any kind of celestial body, it's how we calc'd shaking the Moon because it has no tectonic plates.

@DemonGodMitchAubin @CloverDragon03 @Aguywhodoesthings @Armorchompy @Therefir @Mr._Bambu @Psychomaster35 @TheRustyOne @DemiiPowa @DontTalkDT @Executor_N0 Pls evaluate ;-;

 

[TheRustyOne]

KLOL's calculation seems fine to me as well. At least according to my teeny brain.

 

[KLOL506]

KLOL's calculation seems fine to me as well. At least according to my teeny brain.

Thank you brother. Now we wait for the rest.

 

[Psychomaster35]

KLOL’s calc looks good

 

[Therefir]

There's a better way to do this.

Good old KE using Intensity Intensity scale and using that to get velocity via the Mercalli scale. Intensity V (Felt by Nearly Everyone), so the lowest speed is 4.65 cm/s or 0.0465 m/s.

Mass of Earth being 5.972e+24 kg...

KE: 0.5 * 5.972e+24 * 0.0465^2 = 6.4564785e+21 J or 1.54313539675 teratons of TNT (Small Country level)

LOL, actually higher than what we have right now.

This formula works for literally any kind of celestial body, it's how we calc'd shaking the Moon because it has no tectonic plates.

This should be fine.

 

[CloverDragon03]

@DemonGodMitchAubin @CloverDragon03 @Aguywhodoesthings @Armorchompy @Therefir @Mr._Bambu @Psychomaster35 @TheRustyOne @DemiiPowa @DontTalkDT @Executor_N0 Pls evaluate ;-;

Looks fine to me

 

[DemonGodMitchAubin]

I suppose KLOL's method looks fine for shaking the planet

 

[Mr. Bambu]

@DemonGodMitchAubin @CloverDragon03 @Aguywhodoesthings @Armorchompy @Therefir @Mr._Bambu @Psychomaster35 @TheRustyOne @DemiiPowa @DontTalkDT @Executor_N0 Pls evaluate ;-;

I've always thought this was a better way to do this, but never bothered to pursue it. If this is a genuine proposal for a shift, absolutely in favor of this. Your work looks great.

 

[Armorchompy]

yep

 

[Dark-Carioca]

I'm fine with KLOL's end

 

[KLOL506]

I'm fine with KLOL's end

Bruh you double-evaluated

 

[KLOL506]

@Aguywhodoesthings @TheRustyOne @DemiiPowa @DontTalkDT @Executor_N0 You guys are the only ones left to evaluate and add this.

 

[Dark-Carioca]

Bruh you double-evaluated

lol

Coulda sworn I'd been tagged again, so I thought something had changed

 

[DontTalkDT]

There's a better way to do this.

Good old KE using Intensity Intensity scale and using that to get velocity via the Mercalli scale. Intensity V (Felt by Nearly Everyone), so the lowest speed is 4.65 cm/s or 0.0465 m/s.

Mass of Earth being 5.972e+24 kg...

KE: 0.5 * 5.972e+24 * 0.0465^2 = 6.4564785e+21 J or 1.54313539675 teratons of TNT (Small Country level)

LOL, actually higher than what we have right now.

This formula works for literally any kind of celestial body, it's how we calc'd shaking the Moon because it has no tectonic plates.

Problem is that we use magnitude 4 for shacking the earth feats (or at least, the particular one linked in the references for common feats. We also have the earthquake table). So the speed would be 1.41 cm/s = 0.0141 m/s.

0.0141^2*0.5*5.97219*10^24 = 5.9366554695e20 J which is smaller than our current value.

(Btw. OP is wrong, because the formula actually takes earth curvature into account)

 

[KLOL506]

Problem is that we use magnitude 4 for shacking the earth feats (or at least, the particular one linked in the references for common feats. We also have the earthquake table). So the speed would be 1.41 cm/s = 0.0141 m/s.

0.0141^2*0.5*5.97219*10^24 = 5.9366554695e20 J which is smaller than our current value.

I see.

(Btw. OP is wrong, because the formula actually takes earth curvature into account)

Does it now? What do you propose we do then?

 

[DontTalkDT]

Does it now? What do you propose we do then?

Nothing. The calc is fine as it is.

 

[Armorchompy]

Magnitude 4 is pretty low considering what most of these feats look like. I think we should definitely add KLOL's calc as a high end for more impressive shaking.

 

[DontTalkDT]

Magnitude 4 is pretty low considering what most of these feats look like. I think we should definitely add KLOL's calc as a high end for more impressive shaking.

Standard Calculation for shaking the Earth

vsbattles.fandom.com

We have all magnitudes already

 

[KLOL506]

Magnitude 4 is pretty low considering what most of these feats look like. I think we should definitely add KLOL's calc as a high end for more impressive shaking.

My calc is literally the same value as the current one, maybe half a teraton higher.

Though you can still use the method for other celestial objects that have no tectonic plates.

Nothing. The calc is fine as it is.

Welp. I tried.

 

[Armorchompy]

Standard Calculation for shaking the Earth

vsbattles.fandom.com

We have all magnitudes already

my b

 

[DarkDragonMedeus]

Magnitude 4 from a distance was agreed to be the safe low-end for the Earthquake simply being felt across the globe. But I know some characters such as Yu Yu Hakusho's Shinobu Sensui as well as the Elders from Elder Scrolls who basically, "Shake the entire world so hard it flattens the surface and wipes out all life on the planet". Which I while back some have said that would be at least Magnitude 6 from a distance and get Continent level results, but I recall KLOL mentioning on another thread Magnitude 7 from a distance and getting High 6-A seems more accurate for those types of feats.

 

[KLOL506]

Magnitude 4 from a distance was agreed to be the safe low-end for the Earthquake simply being felt across the globe. But I know some characters such as Yu Yu Hakusho's Shinobu Sensui as well as the Elders from Elder Scrolls who basically, "Shake the entire world so hard it flattens the surface and wipes out all life on the planet". Which I while back some have said that would be at least Magnitude 6 from a distance and get Continent level results, but I recall KLOL mentioning on another thread Magnitude 7 from a distance and getting High 6-A seems more accurate for those types of feats.

Depends really, on the amount of devastation caused, but if it's there, go ham.