Fragging Sokovia
The calc assumes that whole rock is a hemisphere (half a circle) for simplicity, and we can get the volume of a hemisphere with the radius from equation: 2/3* ¤Ç*R^3. Now you mention it, there is something wrong with the calc since it used the diameter instead of radius. So the actual results should be:
Fragmentation: 4.3735654e+13
[7-C Town Level]
Violent Fragmentation: 3.4988523e+14
[7-C Town Level]
7-B Statement
General Ross statement comparing Thor and Hulk to 30 Megaton nukes is evidence for 7-B.
Thor getting knocked out by the Novi Grad Explosio
Anyways, that's a surface area of
2280.5575054645 meters2
...An energy release spread over all of that isn't giving much for the surface area of a human.
2.61e+18/2280.5575054645*1.14=1.30468098e15 (
High 7-C)
Thor's Wakanda Storm Feat
00:37, Thor creates a storm in the timespan of a jump.
Stretches all towards the horizon and covers the sky. It took 0.76 seconds for Thor to land from that height.
0.5*g*t^2
0.5*9.81*0.76^2 = 2.833128 m
Adding 1.9 m to account Thor's height, so 4.733128 m. Then deduct 10 cm to account for the distance between Thor's head and his eyes. 4.723128 m, so horizon is
7.8 km.
Clouds appear to be cumulonimbus.
Using C.A.P.E.
Assuming strong instability.
Low End
pi*7800^2*8000*1.003 = 1.5336632e+12 kg
1.5336632e+12*4000=6.1346528e+15 joules or 1466182.0192 Tons of TNT (
Small City level)
High End
pi*7800^2*11800*3*1.003 = 6.7864597e+12 kg
6.7864597e+12*4000=2.7145839e+16 joules or 6487855.521 Tons of TNT (
City level)
