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Planetary KE calcs

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It's mostly an issue with the manga/comic book feats where the dispersion still hasn't finished yet, not in anime where cinematic timeframe can be properly used to accurately gauge how much time it took for all the debris to disappear from the screen or stop moving altogether.
At least we have an idea of what can be a timeframe, since the fragments in the scans we've used seem like that they've stopped from the previous panel
 
Can somebody experienced summarise the conclusions so far here please?
 
Can somebody experienced summarise the conclusions so far here please?
From what I can gather, KE can still be used, but the curvature shot is not reliable to use.

The results will still get results in the Zettatons at least, which is anywhere between Small Planet & Planet level.

And according to Strym, if the calculation gets Small Planet, then the meteor feat just gets pegged at Baseline Planet level, whiiiich I'll let others decide on that.
 
Basically these 2
New calc

Scan
  • New planet Diameter : sqrt(1-(tan(35)(1978/2192))^2/((tan(35)(1978/2192))^2+1))*12742 = 11716.043 km = 11716043 m
  • Planet diameter = 1978 px = 11716043 m
  • Distance the debris crossed = 1260.69 px = 7467289.31 m
Low end:
  • Time = 30 s
  • Speed = 248909.644 m/s
  • KE = 0.5 * 2.77e22 * (248909.644^2) = 8.58090751e32 Joule / 205.09 Zettatons (Planet level)
Mid end
  • Time = 15 s
  • Speed = 497819.287 m/s
  • KE = 0.5 * 2.77e22 * (497819.287^2) = 3.43236299e33 Joule / 820.35 Zettatons (Planet level)
High end
  • Time = 5 s
  • Speed = 1493457.86 m/s
  • KE = 0.5 * 2.77e22 * (1493457.86^2) = 3.08912669e34 Joule / 7.38 Yottatons (Large Planet level)
Anyway...

15 second end-

Speed = 1806.37552036/15
Speed = 120.42503469067 km/s

Mass = 2.77e+22

KE = 0.5 * 2.77e+22 * 120425.03469067^2 = 2.0085531737645e+32 j

Small Planet/Low 5-B


5 second end

Speed- 1806.37552036/5= 361.275104072 km/s or 361275.104072 m/s

KE- 0.5 * 2.77e+22 * 361275.104072^2 = 1.8076978564e+33 J (Planet level)
 
Scan (Actual panel height that should be used is 317), the small rectangle where we see the floating debris)
  • New planet Diameter : sqrt(1-(tan(35)(1978/317))^2/((tan(35)(1978/317))^2+1))*12742 = 4082.63263751 km = 4082632.63751 m
  • Planet diameter = 1978 px = 4082632.63751 m
  • Distance the debris crossed = 1260.69 px =2602090.06056 m
Low end:
  • Time = 30 s
  • Speed = 86736.33535 m/s
  • KE = 0.5 * 2.77e22 * (86736.33535^2) = 1.04196207398775085771625e+32 Joule / 24.903491252 Zettatons (Small Planet level)
Mid end
  • Time = 15 s
  • Speed = 173472.670704 m/s
  • KE = 0.5 * 2.77e22 * (173472.670704^2) = 4.1678483e+32 Joule / 99.613965 Zettatons (Planet level)
High end
  • Time = 5 s
  • Speed = 520418.012112 m/s
  • KE = 0.5 * 2.77e22 * (520418.012112^2) = 3.751063466529e+33 Joule / 896.52568511687377395 zettatons (Planet level)
Nah, this one.
 
Distance and Mass

The main issue with this, is because we don't know if all the mass moved the same distance in X timeframe. It's more accurate to know that if we have an audio-visual midia of the manga/comic in question, and it should be used to calculate the feat if possible. I am not suggesting that only audiovisual media are allowed to be calculated using this method, there are artists who can do something similar to a video to represent such feat, it is just not common. It must be something case by case analysis.

A clear way to calculate this feats is, see if all the mass moved away from the panel in X timeframe. You can also calculate the mass of the chunks moved, their speed and then KE, but that's more complicated.

Destruction Vs. KE

In my opinion, that's the main issue about these feats. We should not always assume that the mass of the planet moved at X speed, it can be destroyed by other methods, such as fragmentation and only overcome the GBE of the planet, without moving the chunks at X speed.

Examples: The destruction of the Death Star in Star Wars, and the manga feat of Frieza destroying planet Vegeta.

In general, to calculate feats with KE, we should pay more attention:

If all the mass moved the same distance in X timeframe
The mass moved, not got destroyed.
 
Examples: The destruction of the Death Star in Star Wars, and the manga feat of Frieza destroying planet Vegeta.
Ugh, this again?

Like I already cannot stress enough, there is no scan of Planet Vegeta being blown up in the manga, just Frieza talking about it. The actual destruction is only ever shown in the DBZ anime, DBZ Kai, DB Super and DBS Broly.
 
Dude, stop. You know that, I know that, we all know that. The feat does not qualify for KE feats.
 
Dude, stop. You know that, I know that, we all know that. The feat does not qualify for KE feats.
How many times do I have to tell you that we don't even use the manga for Frieza's destruction of Planet Vegeta at all?

EDIT: YOU COULD AT LEAST TELL ME YOU WERE ACTUALLY TALKING ABOUT DEOXYS AND NOT ABOUT FRIEZA
 
So the feat will then probably be at the Tier High 6-A

But exist the meteor creating a big wave on the planet, can probably use KE in this feat
**** it, just assume average surface wiping.

However, since this surface wiping happened on the ground, don't assume the airburst formula, assume the ground-based explosion formula.
 
Ground based explosion formula

W= R^3*((27136*P+8649)^(1/2)/13568-93/13568)^2

W be the yield in tons of TNT, R is the radius in meters, P is the pressure, usually 1.37895 bars

Circumference of Earth is 40,075 km or 40,075,000 meters. Half that is the radius, 20037.5 km or 20037500 meters.

20037500^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2= 6.4657085e+17 tons of TNT / 646.57085 petatons of TNT or 2.7052524364e+27 J (Multi-Continent level)
 
It's mostly an issue with the manga/comic book feats where the dispersion still hasn't finished yet, not in anime where cinematic timeframe can be properly used to accurately gauge how much time it took for all the debris to disappear from the screen or stop moving altogether.
The dispersion not being finished yet at that point still gives an estimate of the speed. It doesn't have to stop/finish to get an estimate. (time-frame issue isn't something exclusive to this)
It isn't the problem, the problem is the distance being considered whether it is mid-projection of the fragments or after the fragments have come to a rest state.

It is alright to consider distance between center and farthest end of panel if the manga/anime shows the panel being empty like you said.

But in the case where it isn't and fragments are dispersed throughout the panel (or a dynamic panel where they are mid-travel), one can't just consider distance between center and farthest part of fragments (or farther fragments that are in travel) like a ton of calcs here do. All those fragments aren't being projected from the center and there are a significant amount of them within the distance that is being considered.
 
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The dispersion not being finished yet at that point still gives an estimate of the speed. It doesn't have to stop/finish to get an estimate. (time-frame problem isn't something exclusive to this)
It isn't the problem, the problem is the distance being considered whether it is mid-projection of the fragments or after the fragments have come to a rest state.

It is alright to consider distance between center and farthest fragments if the manga/anime shows the panel being empty like you said.

But in the case where it isn't and fragments are dispersed throughout the panel (or a dynamic panel where they are mid-travel), one can't just consider distance between center and farthest part of fragments (or farther fragments that are in travel) like a ton of calcs here do. Those fragments aren't being projected from the center and there are a significant amount of them within the distance that is being considered.
This. This is exactly what I mean.

In any case, I think we're just gonna opt to normal surface-wiping for this but using the ground-based explosion formula instead since the destruction doesn't start in mid-air, but on the ground.
 
Volume = pi*20000000^2*3688
Volume = 4.6344775e+24
Energy = 4.6344775e+24*8
Energy = 3.707582e+25J (High 6-A)

Mh... This is probably wrong
 
Ground based explosion formula

W= R^3*((27136*P+8649)^(1/2)/13568-93/13568)^2

W be the yield in tons of TNT, R is the radius in meters, P is the pressure, usually 1.37895 bars

Circumference of Earth is 40,075 km or 40,075,000 meters. Half that is the radius, 20037.5 km or 20037500 meters.

20037500^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2= 6.4657085e+17 tons of TNT / 646.57085 petatons of TNT or 2.7052524364e+27 J (Multi-Continent level)
Is it really correct to use this method? The explosion was circulate
 
Is it really correct to use this method? The explosion was circulate
The explosion being circulate really doesn't matter, as this formula just assumes the explosion covering the entire surface area of the Earth at ground level while destroying everyhing else in its path so if anything this is a low-ball since it doesn't even assume the entire crust being destroyed, just the surface. Plus, the explosion still originates from the ground, which is why this is the formula you should use when blowing up shit on ground level.

For explosions happening in mid-air, use this
 
Well this destruction seems to be far above near total fatality which is considered for that nuke formula tbh (20psi over-pressure/wiping out of concrete structures above ground)

From what Strym is saying, the game apparently portrayed this as Planet Buster meteor.
 
Well this destruction seems to be far above near total fatality which is considered for that nuke formula tbh (20psi over-pressure/wiping out of concrete structures above ground)

From what Strym is saying, the game apparently portrayed this as Planet Buster meteor.
Well the near total fatality is airburst, not ground-based so there's that.

It's still a low-ball so to speak.
 
And it looks like manga tried portraying it that way too (seeing the panel of destruction itself), it is just that one panel with a spherical body remaining which contradicts this isn't it?

It seems highly unlikely the fragments exclusively on surface will be blown away omni-directionally considering the meteor collided from one direction) with the earth retaining it's spherical nature.
 
Well the near total fatality is airburst, not ground-based so there's that.

It's still a low-ball so to speak.
The "ground based formula" also considers near total fatality and air burst with 20psi overpressure. It just considers that something exploded on ground instead of mid-air that's all.
 
"You do realize that this is the least hope we have of saving this planet?"

I think that doesn’t cancel the result High 6-A.
 
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