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Planetary KE calcs

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New calc

Scan
  • New planet Diameter : sqrt(1-(tan(35)(1978/2192))^2/((tan(35)(1978/2192))^2+1))*12742 = 11716.043 km = 11716043 m
  • Planet diameter = 1978 px = 11716043 m
  • Distance the debris crossed = 1260.69 px = 7467289.31 m
Low end:
  • Time = 30 s
  • Speed = 248909.644 m/s
  • KE = 0.5 * 2.77e22 * (248909.644^2) = 8.58090751e32 Joule / 205.09 Zettatons (Planet level)
Mid end
  • Time = 15 s
  • Speed = 497819.287 m/s
  • KE = 0.5 * 2.77e22 * (497819.287^2) = 3.43236299e33 Joule / 820.35 Zettatons (Planet level)
High end
  • Time = 5 s
  • Speed = 1493457.86 m/s
  • KE = 0.5 * 2.77e22 * (1493457.86^2) = 3.08912669e34 Joule / 7.38 Yottatons (Large Planet level)
 
I think you got your panel height wrong.

It's supposed to be the tiny panel where the planet shows, not the full page lol

Inb4 we find out it was me that misapplied the method all along
 
I think you got your panel height wrong.

It's supposed to be the tiny panel where the planet shows, not the full page lol

Inb4 we find out it was me that misapplied the method all along
He didn't use the full page tho, just that one scan with debris floating LOL

Possibly his scan is way more HD than I expected

EDIT: NVM I think I get what you meant
 
The explosion of celestial bodies is fine if we can use cinematic timeframe to get a proper velocity calculation. But still comic book or manga images are a different story.
 
I think you got your panel height wrong.

It's supposed to be the tiny panel where the planet shows, not the full page lol

Inb4 we find out it was me that misapplied the method all along
Panel height must be higher than planet height
 
Scan (Actual panel height that should be used is 317), the small rectangle where we see the floating debris)
  • New planet Diameter : sqrt(1-(tan(35)(1978/317))^2/((tan(35)(1978/317))^2+1))*12742 = 4082.63263751 km = 4082632.63751 m
  • Planet diameter = 1978 px = 4082632.63751 m
  • Distance the debris crossed = 1260.69 px =2602090.06056 m
Low end:
  • Time = 30 s
  • Speed = 86736.33535 m/s
  • KE = 0.5 * 2.77e22 * (86736.33535^2) = 1.04196207398775085771625e+32 Joule / 24.903491252 Zettatons (Small Planet level)
Mid end
  • Time = 15 s
  • Speed = 173472.670704 m/s
  • KE = 0.5 * 2.77e22 * (173472.670704^2) = 4.1678483e+32 Joule / 99.613965 Zettatons (Planet level)
High end
  • Time = 5 s
  • Speed = 520418.012112 m/s
  • KE = 0.5 * 2.77e22 * (520418.012112^2) = 3.751063466529e+33 Joule / 896.52568511687377395 zettatons (Planet level)
 
Last edited:
What do you use in that case, then?
Good old KE.

EDIT: Oh wait, in the MewTwo calculation the Earth isn't exactly blasted off into bits yet is it? It is later presumed that it would eventually encover the entire Earth and then destroy it.
 
Ngl, I was expecting worse.

Meh. Still Zettatons.
Considering how energetic the explosion was, I'd say to go with at least a mid-end.

You guys do know I'm an honorary CGM, right?
 
sqrt(1-(tan(35)(734/144))^2/((tan(35)(734/144))^2+1))*12742 = 4874.55747037

Planet = 734pxl | 4874.55747037
Distance = 272pxl | 1806.37552036

Speed = 1806.37552036/30
Speed = 60.2125173453km/s

Mass = 2.77e+22

KE = (60212.5173453^2*2.77e+22)/2 = 5.0213829e+31j

Small Planet/Low 5-B
 
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If the calc gets below 5-B I should remind that then it should be discarded since in the games is stated to be 5-B, and this calc just specifies more its AP basing on manga's showing.

If the accepted end is below 5-B, then the calc will be discarded and will be assumed just baseline from game continuity
 
Still Low 5-B
Anyway...

15 second end-

Speed = 1806.37552036/15
Speed = 120.42503469067 km/s

Mass = 2.77e+22

KE = 0.5 * 2.77e+22 * 120425.03469067^2 = 2.0085531737645e+32 j

Small Planet/Low 5-B


5 second end

Speed- 1806.37552036/5= 361.275104072 km/s or 361275.104072 m/s

KE- 0.5 * 2.77e+22 * 361275.104072^2 = 1.8076978564e+33 J (Planet level)
 
Anyway, I think I get what Strym meant by the "drawing the line from the center".

Yeah, I think that's the variant we should use instead, as the distance line not drawn from the center but rather from the edge might not be the best way to calculate the debris's traveling distance, since the scan shows the debris from an angle.
 
Anyway...

15 second end-

Speed = 1806.37552036/15
Speed = 120.42503469067 km/s

Mass = 2.77e+22

KE = 0.5 * 2.77e+22 * 120425.03469067^2 = 2.0085531737645e+32 j

Small Planet/Low 5-B


5 second end

Speed- 1806.37552036/5= 361.275104072 km/s or 361275.104072 m/s

KE- 0.5 * 2.77e+22 * 361275.104072^2 = 1.8076978564e+33 J (Planet level)
I doubt that 5 seconds will be accepted
 
I doubt that 5 seconds will be accepted
I doubt that your variant with the shorter travel distance would get accepted either since the scan shows the debris floating at an angle and not side by side and thus the travelling distance can be a lot higher than expected.
 
Ye, but game =/= manga, despite both being canon to each other, so
  • Meteor gets 5-B or higher = used
  • Meteor gets Low 5-B or lower = not used and will be just baseline
If it only says "Planet destroyed" and is shown visually differently, the feat will not be left in 5-B
 
If it only says "Planet destroyed" and is shown visually differently, the feat will not be left in 5-B
Not true, if the planet is visually shown to be unable to piece itself together afterwards, that'll mean its GBE has been exceeded, thus it'd qualify for 5-B.

Simply smashing a planet to pieces ain't enough, you need to overcome its GBE and make sure gravity can't piece everything back together.
 
I just mean that the meteor is 5-B regardless due to the game (primary canon) context.
If the calc accepted gives a 5-B or higher result, it just supports the game source, otherwise, if is below, it'll be discarded and meteor will be baseline
 
Well, if not specified, I think it would not be correct to use Tier 5-B. But I don't know much about the verse, so I don't afirms anything
 
From what I've seen, very few calcs here accurately consider the fact that the entire mass of the said celestial object should've moved at least the said distance considered.

Like man, most of those calcs have the fragments still within the volume where the Planet previously existed and the distance those fragments travelled is measured from centre to the farthest fragments.
 
From what I've seen, very few calcs here accurately consider the fact that the entire mass of the said celestial object should've moved at least the said distance considered.

Like man, most of those calcs have the fragments still within the volume where the Planet previously existed and the distance those fragments travelled is measured from centre to the farthest fragments.
It's mostly an issue with the manga/comic book feats where the dispersion still hasn't finished yet, not in anime where cinematic timeframe can be properly used to accurately gauge how much time it took for all the debris to disappear from the screen or stop moving altogether.
 
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