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One Punch Man - Low 5-B downgrades

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To summarize:
  • I'm saying that the sphere Orochi pulled was energy. So the Low 5-B calc is invalid as it relies on the assumption that the sphere has mass
  • Truelight is saying it does have mass, so the previous calc is still valid
I'm neutral then

However a Low 5-B attack passing through the entire planet and only causing earthquakes instead of like, tearing apart half the crust is suspicious, and KE feats are ignored if the results shown contradict the AP.
 
deformation of the outer core would give similar results

I do not understand why it should be excused when following that logic practically all the weapons of class s heroes should disintegrate every time they are used for the astronomical quantities of energy to which they are subjected
then the palace built by metal knight was built with super resistant materials and these materials logically should have been obtained from the earth
 
I do not understand why it should be excused when following that logic practically all the weapons of class s heroes should disintegrate every time they are used for the astronomical quantities of energy to which they are subjected
then the palace built by metal knight was built with super resistant materials and these materials logically should have been obtained from the earth
Are you arguing the entirety of OPM earth is more durable than normal Earth? That's dumb and would require much more proof.
 
eCjOeFL.png

  • Distance = 5155 km = 516.2 px
5155 / 516.2 = 9.98643936459 m/px
  • Diameter = 47.5 px = 474.35 km (radius 237.175 km)
  • Height = 54.6 px = 545.25 km
Sizing:
  • Volume = 3.2119007e+16 m³
  • Density = 4500 kg/m³
  • Mass = 1.4453553e+20 kg
Considering 10 seconds (hahahahah)= 23717.5 m/s
  • KE = (0.5) * (1.4453553e+20) * (23717.5²) = 4.0652049e+28 J or 9.7 Exatons (Multi-Continent level)
 
eCjOeFL.png

  • Distance = 5155 km = 516.2 px
5155 / 516.2 = 9.98643936459 m/px
  • Diameter = 47.5 px = 474.35 km (radius 237.175 km)
  • Height = 54.6 px = 545.25 km
Sizing:
  • Volume = 3.2119007e+16 m³
  • Density = 4500 kg/m³
  • Mass = 1.4453553e+20 kg
Considering 10 seconds (hahahahah)= 23717.5 m/s
  • KE = (0.5) * (1.4453553e+20) * (23717.5²) = 4.0652049e+28 J or 9.7 Exatons (Multi-Continent level)
Put that in a blog.
 
eCjOeFL.png

  • Distance = 5155 km = 516.2 px
5155 / 516.2 = 9.98643936459 m/px
  • Diameter = 47.5 px = 474.35 km (radius 237.175 km)
  • Height = 54.6 px = 545.25 km
Sizing:
  • Volume = 3.2119007e+16 m³
  • Density = 4500 kg/m³
  • Mass = 1.4453553e+20 kg
Considering 10 seconds (hahahahah)= 23717.5 m/s
  • KE = (0.5) * (1.4453553e+20) * (23717.5²) = 4.0652049e+28 J or 9.7 Exatons (Multi-Continent level)
did not consider the lower parts that were moved
 
Well if accepted then the changes are as follows
  • All of the Class Z ratings are removed
  • All of the Low 5-B ratings are changed to High 6-A
Now for the second point here
  • Are we scaling Orochi to the 166 Teratons feat or the 9.7 Exaton feat. What I mean by this is are we saying Orochi's base is High 6-B or High 6-A
 
Well if accepted then the changes are as follows
  • All of the Class Z ratings are removed
  • All of the Low 5-B ratings are changed to High 6-A
Now for the second point here
  • Are we scaling Orochi to the 166 Teratons feat or the 9.7 Exaton feat. What I mean by this is are we saying Orochi's base is High 6-B or High 6-A
Why high 6-A?
 
Well if accepted then the changes are as follows
  • All of the Class Z ratings are removed
  • All of the Low 5-B ratings are changed to High 6-A
Now for the second point here
  • Are we scaling Orochi to the 166 Teratons feat or the 9.7 Exaton feat. What I mean by this is are we saying Orochi's base is High 6-B or High 6-A
He has no other forms other than true form. Either way, he'll be High 6-A.
 
Accepted the mid-end. Though I would feel comfortable if yous got input from another CGM. Maybe @Armorchompy should check it out.
 
If we're upscaling Boros to Orochi then yes, his second key would be like his old version that scaled to the moon jump of "High 6-A, Higher with the CSRC"
 
  • Serious Punch: High 6-A
  • CSRC: High 6-A
  • Plate Lift: High 6-A
  • Magma Pull: High 6-A

I was asking are we making him "High 6-A, higher with the Gaia Cannon" or "High 6-B. High 6-A with the Gaia Cannon"
Ah I see so the new calculation takes into account the movement of the mantle due to the movement of the blob of energy right? I see well orochi would indeed scale to that since it's himself causing the kinetic energy.
 
Ah I see so the new calculation takes into account the movement of the mantle due to the movement of the blob of energy right? I see well orochi would indeed scale to that since it's himself causing the kinetic energy.
Agreed.
Not only to mention that the Core itself got distorted which shouldn't happen if only the heat/energy was being pulled :


Why are people ignoring this?
 
I do think that it is clear the mantle moved tbh. So I support using the mantle movement calc.
 
New ranking system would be
  • Serious Punch's Original Power: 3.52 Exatons
  • Serious Punch Left Over Power: 2.51 Exatons
  • Core Pull: 2.42 Exatons
  • CSRC: 1.01 Exatons
  • Plate Lift: 254 Petatons
Why are people ignoring this?
Because its more likely that he yanked out Thermal Energy than 3.5% of the Moon's total mass that he then somehow stored into his body
 
outer core is therefore liquid
I try to make an approximate and simplified calculation of the work required to malform the outer core:

1) shape drag
Sphere: 90%
cone:> 10%
(this is a downward approximation to avoid too complex calculations)

I find the viscous friction force for the moving sphere and then multiply by 0.1 since the friction of a cone is at best 90% lower

using the measurements provided by USklaverei

radius: 237 000 m (r)
distance: 545 000 m (d)
time: 20s (t)
speed: 545 000/20 m / s (v)
density = (de)
viscosity = (vs)

Re = (2r * v * de) / vs if Re <1 we can use this formula:
F (friction) = - 6pi * r * vs * v (v = d / t)


viscosity outer core = 10e + 16 pa * s


density outer core = 12.6 g / m3 or 12600 kg / m ^ 3

Re = (2 * 237000 * (545000/20) * 12600) / 10e + 16 = 0.016 (Re <1)
F = - 6pi * r * vs * v (v = d / t) * 0.1 (because it is a cone)

work = F * d
but since it starts from a standstill and accelerates (the friction increases with increasing speed) I have to do the integral
integral from d1 = 0m to d2 = 545000 m (distance) of -6pi * r * vs * d / t * 0.1 in ds
using
result = -
331560096750000000000000000000000 joules
 
How does pulling thermal energy warp the landscape of the planet? It's literally heat energy / heat radiation. It doesn't have measurable mass. We see a piece of the core get sectioned off.
 
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