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Yeah.So if they moving more than one star, just add two sun GBE?
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Yeah.So if they moving more than one star, just add two sun GBE?
thank youYeah.
Could you give a scan with more context ? This could mean alot of things.how do you find the Joules of cutting somebody from the inside out
here.Could you give a scan with more context ? This could mean alot of things.
I think this is more power and precision than LS. We wouldn't give a sword user greater LS for cutting through a meteor I believe.Can you get LS from a character doing this with a meteor?
In the sense that the monster just flies past by right through the asteroid and isn't slowed down by it
Yeah I don't know a formula for it, but a method I think could be used is finding the roots size if they're shown adding that to the tree's trunk mass and then just calcing how fast it was pulled to get ke.Is there a method for calculating uprooting trees (or really anything with roots)? One that can be extrapolated to fictional comically large trees? Because uprooting them feels like it should be a very impressive feat, but I haven't seen any formula for it around.
I think that'd still be far inferior to the result of ripping it out by accounting for tensile strength and what-not. Normally that's okay tho, but there's some cases where trees are uprooted off-screen.Yeah I don't know a formula for it, but a method I think could be used is finding the roots size if they're shown adding that to the tree's trunk mass and then just calcing how fast it was pulled to get ke.
No, you need to take into account the distance between the stars and rely on inverse-square law to find the power at the epicenter determined by how much power is left at the far edge.Celestial Body Feats
In fiction, some of the more impressive feats are those involving constellations and celestial bodies in general. Those feats are often hard to quantify due to going beyond the physics. The following is the agreement on how it will be done. If a constellation is created by moving stars...vsbattles.fandom.com
About the via an explosion method on constellations, what does it mean? And how do you calculate/replicate that?
Can't you instead use the energy of one exploding star and just multiply that by how many stars exploded?
Like this right?No, you need to take into account the distance between the stars and rely on inverse-square law to find the power at the epicenter determined by how much power is left at the far edge.
Something somewhere the brackets got screwed up, because that's even lower than 4-A despite having a larger explosive radius.Like this right?
Via using explosion method
0.6 x G(M^2)/R = 0.6 x (6.67 x 10^-11) x (1.9888x10^30)^2/(6.955x10^8) x 10 (10 stars shown destroyed) = 2.2759471^42 joules
Distance between stars = 5 light years (47303653885597800m)
Distance between 10 stars = 47303653885597800 x 10 = 473036540000000000m
473036540000000000/2 = 236518270000000000m
(2.2759471^42) x 4(π) x (2.3651827×10^17)/(6.955x10^8))^2 = 1.8330596e+49 (183305.96 Foe)
I see why I got different results now
radius of the sun right?and Br is the radius of the body blown up at the edge
Do you not need to account the other 10 stars that got destroyed?U= 5.693e+41 joules
Er= (4.73e+17 / 2) = 2.365e+17 meters
Br= 6.957e+8 meters
Energy: 4 * 5.693e+41 * (2.365e+17/6.957e+8)^2 = 2.6315975e+59 J or 2.6316 petaFoe (4-A)
Wait... Petafoe don't even exist in the tiering2.6316 petaFoe (4-A)
Yepradius of the sun right?
Nope. The AoE of the explosion takes care of that. You only need the star that is at the furthest end of this radius.Do you not need to account the other 10 stars that got destroyed?
Now it does.Wait... Petafoe don't even exist in the tiering
.. thank you
BumpHow would one go about calculating the energy required to grow something like a tree very quickly?
Try to find the dimensions of that block if there are any other shots of it and work out the volume by pixel scaling and using a triangular prism as the shape then use the destruction value for melting concrete which is 4814.5 Joules per cm^3How can I calculate this feat?
I calculated the volume, but I didn't quite understand the triangle thing.Try to find the dimensions of that block if there are any other shots of it and work out the volume by pixel scaling and using a triangular prism as the shape then use the destruction value for melting concrete which is 4814.5 Joules per cm^3
The volume of a triangular prism is the area of the triangular face multiplied by the depth of the prism, this would get you roughly the volume of concrete that was melted throughI calculated the volume, but I didn't quite understand the triangle thing.
I couldn't do the calculation. I will create a calculation request for this.The volume of a traisngular prism is the area of the triangular face multiplied by the depth of the prism, this would get you roughly the volume of concrete that was melted through
Bump 2xHow would one go about calculating the energy required to grow something like a tree very quickly?
You would likely use the calories calculator for that, don’t know about quickly though.Bump 2x
Mob Psycho 100 has a calc of growing a giant broccoli very quickly. I'd look into that maybe?How would one go about calculating the energy required to grow something like a tree very quickly?
Someone had a similar question like this asked on this very thread. Lemme me see if could find their blog post.Bump 2x
Found itSomeone had a similar question like this asked on this very thread. Lemme me see if could find their blog post.