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Is a multiverse with uncountably infinite universes Low 1-C
- Thread starter Arceus0x
- Start date
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I asked for explanations, not profiles that could be just as easily outdated. I'm trying to clear out some things here.
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No that's just 2-A.
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This video should do the trick. TLDR, its a higher infinity that cant be reached by conventional infinity (in this case 2-A)
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No it is Low 1-C, as per Oryx and SCP profiles who are up to date with the new tiering system. And because of how infinity works.
Rikimarox2
He/Him- 7,679
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I recall a thread about this.
Iirc, there's a difference between uncountable Infinite universes, and uncountably infinite universes.
The former was Low 1C, while the latter is 2A.
I'll try to find a thread for that later, but I'm 100% sure it exists, I think maybe in a transformers thread.
Iirc, there's a difference between uncountable Infinite universes, and uncountably infinite universes.
The former was Low 1C, while the latter is 2A.
I'll try to find a thread for that later, but I'm 100% sure it exists, I think maybe in a transformers thread.
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That's different than what's being explained in the OP
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It's not though? Oryx is scaling to uncountable infinite universes, and so is Yesod. The OP is asking exactly that, uncountable infinite universes.
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Yes it does exist, that's literally what DT said, but there is another (kinda recent) thread that's made to upgrade Transformer to tier 1 and people agreed that both are same thing
No, it is same
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The entire tiering system can be said to be based around layers or uncountable infinities. For example, if you read the tiering system page closely, High 1-B is infinite dimensions while Low 1-A is uncountable infinite dimensions. Even a 1-D line has uncountably infinitely many 0-D points, and so on.
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2-A Universes are countable infinity on a 5-D scale, Low 1-C multiverses are uncountable infinity on a 5-D scale. 2-A has an Infinite number of space-time continuums. Which while theoretically makes the 1st 3 dimensions add to infinity individually as well as the timeframe of each universe, the distance between each universe aka the 5th dimension would also need to be infinite to separate all of them. But in order to truly reach Low 1-C, the Uncountable number of universes is one way, but individual dimensions might also need uncountable details. Having a higher plane of existence within the multiverse that's bigger than the infinite universes combined might get the impression there's some limited 6-Dimensional value.
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It can be concluded if I am right :
Countless Universe = 2B
Infinite Universe = Base = 2A
Uncountably Inf Universe = L1C
( Infinite ^ Infinite )
Trancend Inf ^ Inf Universe = 1C
Trancend Inf ^ Inf ( × 6 ) Universe = H1C
Trancend Inf ^ Inf ( × 8 ) / Countless - ( D ) = 1B
Infinite - (D) = H1B
*Noted = (× 1) = Powered as many as 1 time
Countless Universe = 2B
Infinite Universe = Base = 2A
Uncountably Inf Universe = L1C
( Infinite ^ Infinite )
Trancend Inf ^ Inf Universe = 1C
Trancend Inf ^ Inf ( × 6 ) Universe = H1C
Trancend Inf ^ Inf ( × 8 ) / Countless - ( D ) = 1B
Infinite - (D) = H1B
*Noted = (× 1) = Powered as many as 1 time
Last edited:
Vietthai96
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Yes, Uncountable Infinite Universe/Universal Spacetime Continuum/Timeline is Low 1-C
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No, adding uncountable or uncountably number of 2D squares can't make a 3D object. Same applies here. It has to be an inacessible difference
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I don't think you understand any of what you're talking about here. An uncountably infinite number of squares stacked together will very much lead to a significant sized 3-dimensional cube.
Inaccesibility doesn't even factor here.
Vietthai96
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Inaccessible can mean anything, something inaccesible doesn't automatically make it have higher dimension or more dimension
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Proof?
Anything can mean anything, I didn't say inacessible is automatically higher dimension
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Uncountable infinite universes I remember stated via ultima grants low 1-C.
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Noooo Ultima isn't knowledgeable, he is like 15 and uses psuedo mathematics
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Excuse me?
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what is the point here?
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He is using csap standards and trying to impose them here without CRTs. Just ignore him I guess
Darksmash
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"Standards" is kinda polite for blatant ignorance and misinformation tbh.
Vietthai96
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well different "standard" doesn't mean misinformation though, each people have different belief when it come to these thing. But ignorance is definitely right on the point
PrinceofPein
Username Only- 8,896
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You tend to act extremely rudely and make rash comments when people don’t agree with you, fix that messed up attitude
Darksmash
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Using wrong maths is a standard?
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I don't think any staff members disagree that uncountably infinite universes is Low 1-C. That thing with Confluctor looked more like a miscommunication to me.
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i mean, why not ask the question now so it doesn't come up later?
TheGreatJedi13
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it is being discussed and cleared up already in staff discussion afaik the FAQ at least.
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Vietthai96
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is CSAP use math at all in their tiering system?
Darksmash
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If they are using higher dimensions then by extension they are using maths. Especially when talking about how higher dimensions relate with Infinity.
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i mean if we speak very strictly then the entire tiering system is based on cardinals and alephs
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Answer to the your question is "Yes."
You could start by looking at a line, or really any interval in 1-dimensional space, considering those are just the union of uncountably-many 0-D points, and the total amount of these points is 2^aleph-0. Same thing generalizes to any other space, as the definition of a cartesian product can tell you.
The "needs to be an inaccessible difference" bit is pretty context-dependent. You could make some model where 2^aleph-0 is weakly inaccessible, yeah, but if you mean a strongly inaccessible cardinal, then that's out of the picture, since by definition those can't be power sets of smaller sets, pretty much. And the Tiering System assumes 2^aleph_0 equals aleph-1 anyway, so, moot point.
(I'm 17, by the by)
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Ayyyy me tooAnswer to the your question is "Yes."
You could start by looking at a line, or really any interval in 1-dimensional space, considering those are just the union of uncountably-many 0-D points, and the total amount of these points is 2^aleph-0. Same thing generalizes to any other space, as the definition of a cartesian product can tell you.
The "needs to be an inaccessible difference" bit is pretty context-dependent. You could make some model where 2^aleph-0 is weakly inaccessible, yeah, but if you mean a strongly inaccessible cardinal, then that's out of the picture, since by definition those can't be power sets of smaller sets, pretty much. And the Tiering System assumes 2^aleph_0 equals aleph-1 anyway, so, moot point.
(I'm 17, by the by)
Rikimarox2
He/Him- 7,679
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Would've been ******* godly if you just came here, posted that gif, and left without a single word.Answer to the your question is "Yes."
You could start by looking at a line, or really any interval in 1-dimensional space, considering those are just the union of uncountably-many 0-D points, and the total amount of these points is 2^aleph-0. Same thing generalizes to any other space, as the definition of a cartesian product can tell you.
The "needs to be an inaccessible difference" bit is pretty context-dependent. You could make some model where 2^aleph-0 is weakly inaccessible, yeah, but if you mean a strongly inaccessible cardinal, then that's out of the picture, since by definition those can't be power sets of smaller sets, pretty much. And the Tiering System assumes 2^aleph_0 equals aleph-1 anyway, so, moot point.
(I'm 17, by the by)
