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Fist Of The North Star Revision Part 2 (Scaling and Multipliers)

I think doing a proper calc of the nuke's cloud split taking reduced air density into account would probably still be a good idea
 
Then I don't really see much problem with the multi-cont end of the feat since the cloud split objectively happens and these are fictional nukes that cause explosions much bigger than any explosion that would be feasible irl
 
Then I don't really see much problem with the multi-cont end of the feat since the cloud split objectively happens and these are fictional nukes that cause explosions much bigger than any explosion that would be feasible irl
If someone threw an object that has a KE of 10 Kilotons that hits a concrete wall and fails to destroy it, the KE end would be rejected.

Multiple High 6-A explosions would do far more damage to the planet, in fact it's not even comparable. The entire planet should've been flatten, and leave no structures or mountains on the surface standing. Yet in the video linked, I see lots of things still around but just destroyed. The destruction is clearly not High 6-A.

The energy of a single explosion would be enough to pulverize all of the rock on the Earth's crust.
 
If someone threw an object that has a KE of 10 Kilotons that hits a concrete wall and fails to destroy it, the KE end would be rejected.

Multiple High 6-A explosions would do far more damage to the planet, in fact it's not even comparable. The entire planet should've been flatten, and leave no structures or mountains on the surface standing. Yet in the video linked, I see lots of things still around but just destroyed. The destruction is clearly not High 6-A.

The energy of a single explosion would be enough to pulverize all of the rock on the Earth's crust.
The war literally shifted the planet's tectonic plates and possibly split it in 2. You gotta account for the fact that most of the nukes would have had to land on the ocean and that most of the energy was contained within the shockwave. We are also never shown anything outside of Japan and a very small portion of China, so for all we know the rest of the planet could very well be completely flattened
 
The war literally shifted the planet's tectonic plates and possibly split it in 2. You gotta account for the fact that most of the nukes would have had to land on the ocean and that most of the energy was contained within the shockwave. We are also never shown anything outside of Japan and a very small portion of China, so for all we know the rest of the planet could very well be completely flattened
Yeah honestly the war only being high 6-A by itself is a lowball considering the irreparable damage it caused to the planet
 
May want to ask the two other calc group members that've commented here.

I've know nothing about this verse until this thread, so I cannot be the judge. Assuming they're more familiar about this stuff.

I can't say more beyond what I've already said. Personally, I don't care either way.
 
I did a quick calc on how many bombs could have been used during the nuclear destruction, it comes out to being 38, which seems reasonable as I only counted 8 explosions in the scan, and we don’t see the other side of the planet
 
Might be best to ask a calc group member familiar with the verse.

I'm feeling far too lost here about how anything works.
 
Looks like it's chapter 11, although since this isn't from the main manga nor written by the original authors, is there anything to verify that it's canon?
 
What are the calculation results that have been accepted here, which characters scale to the results, and which calculation blogs currently still need to be evaluated?

Provide links please. 🙏
 
Well its had been a month and nothing has change...

What are the calculation results that have been accepted here, which characters scale to the results, and which calculation blogs currently still need to be evaluated?


Like i say before, Jasonsith's version of Jagi feat its the only calc which had be trully been officialy accepted by a calc member, but i does lack the Air Dispersion Yield.

While Shmeaty (which calc had been corrected like KLOL506 wanted), its still in a state of limbo.
 
Well if nothing else, if no other calc members will borther evaluate any other calcs, we may as well go with the accepted end and Jasonsith's version of the nuke.

3.88098e23*0.02 = 7.76196e21 J or 1.855 Teratons (Small Country level)

I know for some people its a bit of a downplay since we are not even counting that Jasonsith's version lack the Air Dispersion Yield, but its still better than nothing.
 
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