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Dragon Ball Super Discussion Thread 100

Jaakor48 said:
It was always considered immeasurable but outlier, same as the last time it was brought up. If (a very big an unlikely IF) another immeasurable speed feat comes up, that one will most likely be also used as supporting
Click to expand...
That's if Wiki allows it, if not try to change the rules again.
 
uhh...
高い重力に縛られて生活をしているから、自然と体がきたえられる。
Because we live our lives bound by high gravity, our bodies are naturally toughened.
Click to expand...
i mean-
 
RedReaper said:
I didn't find the raws, but I found it translated to page 64.
Click to expand...
My problem is, I can't reliably apply any of the translated material without the raw text and images to verify.

I'd love to use Nam's Cross Arm Dive doubling in strength when used at high altitudes (allegedly), or the Four Witches Technique multiplying the strength of Tien's blows by "several times" (allegedly), but Japanese is a tricky language, and without solid evidence to back up said claims, the information is next to worthless.
 
Nullflowerblush said:
My problem is, I can't reliably apply any of the translated material without the raw text and images to verify.

I'd love to use Nam's Cross Arm Dive doubling in strength when used at high altitudes (allegedly), or the Four Witches Technique multiplying the strength of Tien's blows by "several times" (allegedly), but Japanese is a tricky language, and without solid evidence to back up said claims, the information is next to worthless.
Click to expand...
Fair. I couldn't find the SEG either, which is surprising, considering-As you said-It's so well utilized on the internet that you'd think everyone has an easy to verify source.
 
Nullflowerblush said:
My problem is, I can't reliably apply any of the translated material without the raw text and images to verify.

I'd love to use Nam's Cross Arm Dive doubling in strength when used at high altitudes (allegedly), or the Four Witches Technique multiplying the strength of Tien's blows by "several times" (allegedly), but Japanese is a tricky language, and without solid evidence to back up said claims, the information is next to worthless.
Click to expand...
Phsccarvalho said:
There are some scans in Japanese with good quality on the wiki page I linked, in the gallery part.

It's not everything, but take a look.
Click to expand...
Examples
 
So goku can predict a. 1 attack in the future?
What calculator yall use for calc?
 
TiltedFN said:
https://www.stardestroyer.net/Empire/Science/Nuke.html how do i find the yield of an explosion using this site?
Click to expand...
That calculator only determines the effects of an explosion, given its yield is already known.

((x/0.28)^3) is the formula for the explosive yield of an airblast (in kilotons), using the radius of the explosion in kilometers (x).
For non-nuclear explosions, the yield is halved.

R^3*((27136*P+8649)^(1/2)/13568-93/13568)^2 is the formula for the explosive yield of a ground explosion (in tons), using the radius of the explosion in meters (R) and the overpressure of the shockwave (in bars); the standard is 20 psi or 1.37895 bars.
 
Nullflowerblush said:
That calculator only determines the effects of an explosion, given its yield is already known.

((x/0.28)^3) is the formula for the explosive yield of an airblast (in kilotons), using the radius of the explosion in kilometers (x).
For non-nuclear explosions, the yield is halved.

R^3*((27136*P+8649)^(1/2)/13568-93/13568)^2 is the formula for the explosive yield of a ground explosion (in tons), using the radius of the explosion in meters (R) and the overpressure of the shockwave (in bars); the standard is 20 psi or 1.37895 bars.
Click to expand...
oh okay I see, thank you
 
Nullflowerblush said:
That calculator only determines the effects of an explosion, given its yield is already known.

((x/0.28)^3) is the formula for the explosive yield of an airblast (in kilotons), using the radius of the explosion in kilometers (x).
For non-nuclear explosions, the yield is halved.

R^3*((27136*P+8649)^(1/2)/13568-93/13568)^2 is the formula for the explosive yield of a ground explosion (in tons), using the radius of the explosion in meters (R) and the overpressure of the shockwave (in bars); the standard is 20 psi or 1.37895 bars.
Click to expand...
9.401678449525E17 tons of tnt do you mind giving me the tier for this? And energy value.
 
Hasty12345 said:
would Beerus and Champa get 5D if the Neutral zone got an extra temporal dimension?
Click to expand...
No, because affecting two space-time doesn’t imply affecting the additional dimension that makes them exist in parallel, which in this case is the neutral zone that encompasses the 12 universes. In other words, destroying 2 universes is insignificant for the neutral zone since it will continue to exist.
 
Nullflowerblush said:
High 6-A (940.167844952 Petatons of TNT).
What exactly are you calculating?
Click to expand...
Sorry, I forgot to convert to meters. Here's the new value if you dont mind. 9.401678449525E26 tons of tnt. Seems to be like large planet level which still seems laughably low. Not sure what i'm doing wrong.
 
Last edited:
I'm looking forward to the New Namek CRT. Got my arguments lined up for it.
 
TiltedFN said:
I dont see how this makes them 5D tbh
Click to expand...
i think what Hasty is saying that if the Neutral zone is accepted to have its own temporal dimension and it is an insignificant 5D realm that should kinda make it a full fledged low 1-C realm unless you can explain how a 4D temporal axis can service a 5D realm.
 
Ryzen7900X said:
i think what Hasty is saying that if the Neutral zone is accepted to have its own temporal dimension and it is an insignificant 5D realm that should kinda make it a full fledged low 1-C realm unless you can explain how a 4D temporal axis can service a 5D realm.
Click to expand...
It is already accepted that the neutral zone is 5D insignificant, it was just missing evidence, but now that it is there it is smooth.
 
mYgo6di.jpeg
 
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