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The Official Calculation Requests Thread V

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In the fight Sasuke vs. Itachi, Sasuke launches several fire dragons to the sky that soon create currents of air so hot that they create thunderclouds a great feat but that goes unnoticed, to see the blog of ZillaJrKaijuKing on a similar subject I would like to know of which magnitude Is Sasuke's feat would anyone help me calculating that feat? Here is the feat in the manga and the explanation of the jutsu in the databook:

Sasuke Thundercloud feat
Sasuke Thundercloud feat 2
Sasuke Thundercloud feat 3
Sasuke Thundercloud feat 4
Here is the explanation in the manga in english http://www.**********.com/naruto/391/3 and here the events in the anime https://youtu.be/ZQu5x1LKXrI?t=2808 and the explanation of the technique By Zetsu in the anime https://youtu.be/ZQu5x1LKXrI?t=3247 . Even found a topic in a forum of physics talking about something similar (curiously the feat of Zilla Jr)

I think that would be all to consider to take into account the feat. Can anyone calculate it?
 
QuagsireTheLegend said:
Could someone calc possible stats for a combined ant? Not composite, different profile:


Assuming there are 7.2 billion humans on the planet today - if we take everyone over the age of 15, they weigh a combined total of about 332bn kg. If we imagine there are 10,000 trillion ants in the world, weighing an average of 4mg, their total weight comes to just 40bn kg. According to Antweb[2], If we assume that the average weight of: Average weight of an ant = 1.5 mg ( 0.0000033069 lbs.) Average weight of a human being = 150 lbs. Humans on the planet= 7,077,551,385 No. of ants = Combined weight of all human / Weight of a single ant No. of ants = 1061632707750/0.0000033069 There are 321,035,624,829,901,000 ants alive on the planet today. That would be a theoretic average of the amount of ants How many there are exactly, there is no way of knowing


Speed; An ant can run about 2 inches per second in average


Lifting Strength: Worker ants weigh from 1-5 mg and https://www.insidescience.org/news/ants-are-even-stronger-you-imagine


For AP:The trap jaw ant Ondontomachus bauri closes its jaws at a speed of 35-64 m/sec (78-145 mph). But, the speed alone is not what is so amazing. The jaw closure occurs in 0.13 msec with acceleration rates that are 100,000 greater than the the force of gravity. And, these forces are being generated by ants that weigh a mere 12-15 mg. In fact, the force of the jaw snap is so big that the ants can launch themselves into the air with a mere snap of the jaw, achieving heights of close to 40 cm. The equivalent would be a 5' 6" man launching himself 132 feet into the air by closing his jaws


Sources; https://www.quora.com/How-many-ants-are-there-in-the-world http://www.theincredibleant.com/ant-how/how-fast-are-ants https://www.insidescience.org/news/ants-are-even-stronger-you-imagine http://sci.rutgers.edu/forum/showth...the-world-why-it-hurts-to-be-bitten-by-an-ant
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Bumping this
 
That seems simple enough, I will assume he evaporeated enough water for it to form a cloud

http://zidbits.com/2011/01/a-cloud-weighs-more-than-you-might-think/

Assuming he evaporated 4 million kilograms (according to the site)

http://www.engineeringtoolbox.com/water-thermal-properties-d_162.html

The heat capacity of water is 4.178 joules per gram

The latent heat of water is 0.438 joules per gram

The area they are doing it seems relatively craggy and dry, so I will assume the temperature is 30 degrees celsius or so

The heat for vaporization of water is 100 degrees celsius

http://www.endmemo.com/physics/specificheat.php

= 1,169,840,000,000 joules

For latent heat, it is 4 million kilograms * 0.438 joules per gram

= 1,752,000,000 joules

= 1,171,592,000,000 joules or 280.0172 tons of tnt
 
Thank you very much for the prompt response and for the links provided, they have good information. Your way of calculating the feat is very interesting and differs from that used by ZillaJrKaijuKing may be good for calculating the feat although I am not entirely convinced that it is the most concise way to do so. I also pointed out a mistake in your calculations as I have seen water evaporation calculations that yield greater results with less quantity and I think it is because of the data you use since:

Heat Capacity of Water = 4186 J*K^-1*kg^-1

Latent Heat (Evaporation) of Water = 2272000 J*kg^-1

Change of Temperature ~ 85 (of this I am not sure, it can be smaller)

The formula for calculating the energy in this case is Q = m*(c*ΔΤ+L) and substituting the values gives as a result 1.051124e+16 that is 2.51 Megatons which would be Small City Level.

That using your approach and only for a single cumulonimbus. I'm not sure if that way is fine but I appreciate your response, hopefully some other users will be interested in the subject and give us more opinions or another calculation about it.
 
Thanks, I use engineeringtoolbox a lot, and it had the temperature and all
 
I apologize for asking, but, given that the cloud created is shown to create a lightning bolt, has the energy in creating that also been calculated, assuming it's applicable?
 
Imaginym said:
I apologize for asking, but, given that the cloud created is shown to create a lightning bolt, has the energy in creating that also been calculated, assuming it's applicable?
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lightning bolt only peak into the 9-A to low 8-C IIRC. I chose a Cumulonimbus cloud as those are stormclouds.
 
Yes, but if he created the cloud -through the rising air current made by his flames, apparently- that created that lightning bolt, shouldn't its energy be added to the total AP yield for that feat, if only for accuracy's sake, however insignificant an addition it may be?
 
http://www.narutoforums.com/xfa-blog-entry/final-fantasy-ix-feat-garland-moves-gaia-and-terra.26564/

Can someone consider recalcing this feat from Final Fantasy 9?

Someone corrected for me that feat might a little lowballed since it didnt taken into the moons moving with the planets. Since this feat is already high end 5-A to begin with, adding the moons could bring this feat up an entire tier.

Thank you.

Edit: https://elldimensional.wordpress.com/2015/04/04/ffix-terra-and-gaia/

Also, this dungeon in ff9, aka memoria could also be calced since this another view of the two merging.
 
Imaginym said:
I apologize for asking, but, given that the cloud created is shown to create a lightning bolt, has the energy in creating that also been calculated, assuming it's applicable?
Click to expand...

I am not sure, it seems to me that only in this case is the energy necessary to make a change of temperature in the atmosphere so great as to create this storm cloud, I hope soon a user can answer the request and make a more precise calculation on the theme.
 
Hello guys, I have a request. It's an explosion/cloud dispersion calc.

Bumblebee survives an explosion that splits some clouds in the 8th episode of Transformers: Animated.

Go to 20:00 to get the picture. Here

That will scale to: Every single bot, except the humans.
 
I literally typed out the whole calc and forgot about the 20 minute limit and it all got erased.

But to make it short and sweet..


The moon doesn't matter. Moving the planet yields about 48.108 ninatons, and the moo only changes the numbers after the decimal (assuming it's our moon, since the planet he uses has Earth's diameter, but not its mass).

Planet moving AP = 48.108 ninatons, or 48108 yottatons

Moon moving AP = 244 yottatons.

48108.70 + 244.02 = 48352.72 yottatons, or 48.35272 ninatons.

However, I don't know why he only calculated one pair, when there are two pairs. Doubling the result would yield 96 ninatons, making it High 5-A.
 
Forthecalc


417 px = 5 feet (assuming 5 feet of the man is shown)


Panel height = 661 px

2*atan(417/(661/tan(70/2))) = 33.2840581 degrees

http://www.1728.org/angsize.htm = 8.3637 feet distance

Speed of sound is 343 meters per second in the atmosphere

That gives me a timeframe of 7.43223254 milliseconds

Assuming he would have spanned his arm 4 feet to get and fire each arrow, he moved 16 feet

16 feet/7.43223254 milliseconds = 656.16892 m/s or mach 1.92826389

Pretty unorthodox method. I think you could change how far his arm spanned taking the arrow and all, and the height of the man seen, but aside from that, the distance shouldn't be that much different and dabbling with it I should get similar results regardless. This is a solidly Supersonic feet, it can be explained that the 4 sounds being at once was the sonic boom that happens lol.
 
Hello everyone, I hope you all are doing well. If someone would be able to help me with a calculation I would appreciate it.


Han-Jee Han's Four Spirit Destruction

Size of the creature found in the above link. A second reference to its size


If anything else is needed please let me know.
 
FanofRPGs said:
Pretty unorthodox method. I think you could change how far his arm spanned taking the arrow and all, and the height of the man seen, but aside from that, the distance shouldn't be that much different and dabbling with it I should get similar results regardless. This is a solidly Supersonic feet, it can be explained that the 4 sounds being at once was the sonic boom that happens lol.
Click to expand...
Hmmm, idk about this. Given the animation, you can make a case based on the design that he loaded four arrows onto his string and made four fast consecutive shots that sounded like one.

If you look up a guy named Bob Munden, he shot a Colt .45 to two targets 8 feet apart so fast it sounded like one shot. Since you can't change the velocity of the gun, then the answer must lie in how fast you can release the other arrows after the release of the first.

You can watch here as it shows there was virtually no space in between the movements of the two shots, which he's shown to do in under 1/10 of a second.

If he's shooting these arrows from the string, then finding his draw length (which it shows his string at four places, so you can calc that, also it looks as if he finger-plucked them instead of doing a complete draw), average speed of an arrow (300ft/s), weight of the arrow (lets say about 18 grams for an aluminum arrow spine), and the speed of each consecutive shot should be factors.
 
109 was the issue of the Avengers comics that the post referred to.

I'm not familiar with the method needed to find the trajectory of an arrow with the required speed, but using the projectile motion calculator, and object traveling to 68km would need to be going 7525.97m/s, or Mach 21.9
 
I would also appreciate help with calculating the Magi speeds.
 
I see, I wonder how he scaled Champion's body measurements from a normal person though.
 
@BANLK A lot of those images are not available to me. Not sure why other than it being licensed.
 
@BANLK Perhaps you could upload the relevant images to this wiki instead, and then link to them?
 
I'll look at some of them when I get done with work tomorrow night if someone else hasn't beat me to it. Hopefully I can use one (or more) of them to get a calc going.
 
Thank you, but we should stop discussing this issue here. This is not intended to be a discussion thread.
 
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