Serious Punch Squared Revision CRT ~~December Edition~~

[Naeem0304]

I have a high-end CRT suggestion for Serious Punch Squared:
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• The average star weighs between 0.5 and 8 solar masses.
• The average star is about half the size of the sun. This would be 432,690 / 2 = 216,345 miles for an average star's radius.

The midpoint would be 4.25, so let's use 0.5, 4.25, and 8 for now:

Gravitational Binding Energy (0.5): 1.138×10^41 joules (Star Level+)
Gravitational Binding Energy (4.25): 8.218×10^42 joules (Large Star Level)
Gravitational Binding Energy (8): 2.911×10^43 joules (Large Star Level)

First Cosmic Velocity (The speed needed to escape gravitational attraction from a celestial object.)
Escape Velocity (Minimum speed needed for a celestial object to escape gravitational attraction.)

(0.5):

• Cosmic velocity (0.5)= (Mach 1271/Massively Hypersonic+)

(4.25):

• Cosmic velocity (4.25) = (Mach 3711/Massively Hypersonic+)

(8):

• Cosmic velocity (8) = (Mach 7197.7587/Massively Hypersonic+)

The cosmic/escape velocity is relevant because we can gauge the level of force needed to break apart the Star. (Gravitational Binding Energy is 0.6 times the kinetic energy of that object moving through it's escape velocity.) This is because of U=(3/5) x G x (M^2 / R)

U: Newtonian Gravity -- G: Gravitational Constant. -- M: Mass of the sphere -- R: Radius. --

Therefore, the cosmic/escape velocity would remain somewhat relative to overpowering the Gravitational Binding Energy.

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Calculation Format
The original calculation used a 4,000 light year value (3.7843e+19 meters) for range. (credits to @Qawsedf234)

• 4,000 lightyears = 3.7843e+19 Meters
• Using the AngSize calculator = 3.1350e+19 is the size
• 3.1350e+19 / 2 = 1.5675e+19 meters is the radius
• Sector Area: 9.6488373e+37 meters^2
• 5.693e+41 Joules = Accepted GBE of the Sun
• Surface Area of the Sun according to NASA = 6.087799e+12 kilometers^2 or 6.087799e+18 meters^2 These are the values created by @Qawsedf234 in the official post

• For this, we'll simply convert the explosion's mass in joules to PSI, convert the PSI to force, then find the Kinetic Energy by using the cosmic velocity's speed:

(Cosmic Velocity for 0.5) 0.5 Solar Masses: 3.6073388e+60 joules is equal to 3.7386253782100767e+22 Pascal, which is equal to 8.94657e+59 Metric Tons

Kinetic Energy Format

Which is equal to 2.031e64 Tons of TNT (Multi-Galaxy Level), divided by two for Saitama/Garou equals 1.0155e+64 Tons of TNT

(Cosmic Velocity) 4.25 Solar Masses: 2.6050185e+62 joules is equal to 26998263303703960000 Bars, which is equal to 6.4555e+61 Metric Tons

Kinetic Energy Format

1.250e+67 Tons of TNT (Multi-Galaxy Level), divided by two for Saitama/Garou equals 5.0775e+63 Tons of TNT (Multi-Galaxy Level)
(Cosmic Velocity) 8 Solar Masses: 9.22756e+62 joules is equal to 95633906066588980000 Bars, which is equal to 6.450908e+61 Metric Tons

Kinetic Energy Format

2.0166e+67 Tons of TNT (Multi-Galaxy Level), divided by two for Saitama/Garou equals 1.0083e+67 Tons of TNT (Multi-Galaxy Level)


Multi-Galaxy seems supported in-manga from galaxies clearly being visible even from IO's surface (in sharp contrast to the void being shown from outside of Earth's atmosphere)

 

[Robo432343]

No.

 

[Wankbreaker]

neutral

 

[Berento_Magnifico]

People be saying no without explaining why lol

 

[Diamentus]

No.

 

[EnderLord8]

following, You should have first posted it on a blog and attached it to the calculation evaluation group and waited for it to be approved, before doing a CTR...

But let's see what happens now

 

[MasqueTLDF]

Disagree FRB

 

[Hellformer]

Disagree, stop wanking
Agree, great job buddy

 

[DavidTPPM]

Could you please explain wtf are you actually doing in the calc? Idk if I'm just dumb or blind but I can't piece it together.
Why are pascals/PSI even being mentioned they're a measure of pressure?
What's the point of calculating GBE of stars when we have an accepted value for that which is already used in the SP² calc?
Why are you calculating cosmic velocity?

This post feels like it very much lacks important explanations

 

[Naeem0304]

Could you please explain wtf are you actually doing in the calc? Idk if I'm just dumb or blind but I can't piece it together.
Why are pascals/PSI even being mentioned they're a measure of pressure?

This post feels like it very much lacks important explanations

I was trying to calculate the weight of the explosion, although I likely could've just done it in this fashion...

The ton of TNT is a unit of energy defined by convention to be 4.184 gigajoules (1 gigacalorie),[1] which is the approximate energy released in the detonation of a metric ton (1,000 kilograms) of TNT.

1 Ton of TNT is relative to the energy released from 1 metric ton:

• 5.693e+41 Joules = Accepted GBE of the Sun
• Surface Area of the Sun according to NASA = 6.087799e+12 kilometers^2 or 6.087799e+18 meters^2
• 5.693e+41 * (9.6488373e+37 / (6.087799e+18 / 2)) = X
• 5.693e+41 * (9.6488373e+37 / 3.0438995e+18) = 1.8046204e+61 Joules (4-A)

1.8046204e+61 Joules = 4.31e+51 Tons, which would equal to the force of 4.326e+48 KG. That would land 4.15e+62 Joules or 22x higher than the original.

What's the point of calculating GBE of stars when we have an accepted value for that which is already used in the SP² calc?

1. Only for the sun; I was calculating GBE's for the average stars.

Why are you calculating cosmic velocity?

1. If you destroy a planet/star with the exact force of it's Gravitational Binding Energy than that means they will move relative to their escape velocity. I'm using the cosmic velocity as a low-end, however, I briefly explained up top that overpowering the GBE is somewhat relative to the escape velocity that the remains of the celestial object.

 

[DavidTPPM]

I was trying to calculate the weight of the explosion, although I likely could've just done it in this fashion...

For KE? The explosion is moving at MFTL+ speeds it's not viable for KE calcs.

1 Ton of TNT is relative to the energy released from 1 metric ton:

1. Only for the sun; I was calculating GBE's for the average stars.

We use sun as the standard size for a star.

1. If you destroy a planet/star with the exact force of it's Gravitational Binding Energy than that means they will move relative to their escape velocity. I'm using the cosmic velocity as a low-end, however, I briefly explained up top that overpowering the GBE is somewhat relative to the escape velocity that the remains of the celestial object.

Not really…? Why would you assume destroying a star means it's "moving at speed relative to the escape velocity"? And what would that even be helpful for?

This whole calc is silly.

For this, we'll simply convert the explosion's mass in joules to PSI, convert the PSI to force, then find the Kinetic Energy by using the cosmic velocity's speed

For one, joules don't measure mass but energy.
But more importantly you can't just convert pressure/force to mass. Just because an explosion is outputting certain amount of pressure or force doesn't mean the explosion has mass equal to that force.

 

[DavidTPPM]

This is literally just a calc for basic star destruction and you're getting multi galaxy level results. That alone should have been a giant red flag indicating the calc is wrong

 

[Naeem0304]

For KE? The explosion is moving at MFTL+ speeds it's not viable for KE calcs.

1. Lol sorry about that, although I do wonder why Saitama and Garou didn't get a MFTL+ rating for their attack speed?

Not really…? Why would you assume destroying a star means it's "moving at speed relative to the escape velocity"? And what would that even be helpful for?

1. For instance, if you bust the Earth at it's exact GBE, it's fragments would move at 11 km/s. Shouldn't the escape velocity remain relative, or no? It probably isn't helpful either way.

This whole calc is silly.

1. Thank you for the honesty

For one, joules don't measure mass but energy.
But more importantly you can't just convert pressure/force to mass. Just because an explosion is outputting certain amount of pressure or force doesn't mean the explosion has mass equal to that force.

1. Just a question, but couldn't F=MA apply?

 

[MrTayman616]

1. Lol sorry about that, although I do wonder why Saitama and Garou didn't get a MFTL+ rating for their attack speed?

Because the attack was compressed, the speed of it should be faster than what it would be if it was omni-directional. It was accepted being released as 45 degree angle cone. I wonder if the difference in speed (between compressed and omni directional) can be found. It could be used that way

 

[DavidTPPM]

1. Lol sorry about that, although I do wonder why Saitama and Garou didn't get a MFTL+ rating for their attack speed?

Like Tayman said, the attack was compressed. Imagine holding a water hose and squeezing the tip. The water will become much faster.

1. For instance, if you bust the Earth at it's exact GBE, it's fragments would move at 11 km/s. Shouldn't the escape velocity remain relative, or no? It probably isn't helpful either way.

Not necessarily I think? The if the planet is gone you don't need to overcome it's escape velocity anymore because, well, there is no planet lol

1. Just a question, but couldn't F=MA apply?

Not really. We can't really calculate the mass of the explosion because we don't have the energy density and type.

If you want mass from energy alone you can probably use Einstein’s e=mc². That would mean mass = Energy/speed of light².
To calculate this
m= 3.6e66/(speed of light)²
m= 4e49 kilograms
Or just about 22250000000x less than what you got. And I'm using the galaxy level high end here, not just standard star GBE values.

Then if we assume you somehow cooked up an argument for why this explosion is moving at the highest possible speed for KE of 0.91c, you would only get 5e66 Joules which is less than 2x the currently accepted result and you would still have to jump through a ton of hoops.

 

[DavidTPPM]

Just for reference, using your highest values (8x solar mass star GBE for energy and it's escape velocity for speed) with the E=mc² formula you would get
m = 3e43/(speed of light)²
m = 3.33e26kg
KE = 4e32 Joules
Or in other words, 4-C star level

 

[King_Gorilla4002-8922]

Because the attack was compressed, the speed of it should be faster than what it would be if it was omni-directional. It was accepted being released as 45 degree angle cone. I wonder if the difference in speed (between compressed and omni directional) can be found. It could be used that way

This makes no sense at all, especially since the explosion was "compressed" by vector manipulation hax, not by physical pressure.

 

[Minos_the_Judge]

Bump

 

[Shadowslaya!]

I agree, let's get our goat upgraded!

 

[DavidTPPM]

I agree, let's get our goat upgraded!

Crazy ngl