Question about superman throwing a compressed solar system and about the multiple results.

[Huesito88]

Alright so cal did the superman throwing a compressed solar system calculation his result

5.6548526984352e+46 joules (High end)

Yet in the comment section Dark anine thought, it would be more accurate to use radian then convert it to degree. Here is her calculation

2atan(tan(70/2)*(74/444)) = 0.157611155738 Radians

0.157611155738├ù180┬░/¤Ç = 9.030454028┬░ Degrees

So Distance: 8.8098e+9 Meters

8.8098e+9 Meters / 1 minute = 146,829,999.9998661 m/s

For Relativistic Kinetic Energy, just use this calculator

The result is 2.627E+46 J. 262.7 FOE

With the new values, the high end would be FTL KE, and that's no good.

So lets do the mid end instead.

8.8098e+9 Meters / 30 seconds = 293,660,000 m/s. That's 0.97c. I think theirs a limit to the speed in which Relativistic KE ca go, and I think that's past it, but lets do it just in case.

That result is 6.963E+47 J. 6.9 KiloFoe.

Now here is Matts

Assuming that star was 100 meters in diameter when compressed, and had the same mass of our sun:

GBE = 3GM┬▓/5r

GBE = 3 * 6.67408e-11 * 1.9891e30 kilograms┬▓ / 5 * 50 meters

GBE = 7.9218369e50 / 250

GBE = 3.16873476e48 joules

Is there anything wrong with matts? Would dark calculation be considered more accurate then cals and be better to use. If something is wrong with Matts calculation.

 

[Antvasima]

You can inform Matthew and some calc group members about this thread if you wish.

 

[The_real_cal_howard]

Matt's better when it comes with celestial level calcs than I, though that could be the pessimism talking...wow that sounded much worse than intended.

 

[Matthew_Schroeder]

Cal's calc is way better.

 

[Huesito88]

Alright what about dark anine calculation. he is in the calculation group and his calculation result was only the mid end the high was never stated.

 

[The_real_cal_howard]

I thought we were using Darkanine's.

 

[Huesito88]

No as when ever superman feat is ever brought up in a vs thread. I hear it as 5.6548526984352e+46 joules, which is yours.

 

[Matthew_Schroeder]

I thought we were using Darkanine's.

Or Dark's, ye.

 

[The_real_cal_howard]

Yah, we use Darkanine's, due to the fact that it uses radians first and then gets converted into degrees.

 

[Huesito88]

oh ok then, just like put something to say you are using dark anine and not yours because when you click on the link. People will use your calculation result. While dark's calculation is at the bottom of the comment section

 

[Huesito88]

One more thing Matt why do you consider Cal's calculation better?