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Is this Smaug calc usable?

Therefir said:
Okay, I did notice the difference since the beginning and was confused about why that was called the longest root, I thought Hagane was using another root to get their distance, their calc has changed as it was using a different image before.

@Hagane_no_Saiyajin Earthquakes propagate evenly through the surface, so I'm not sure why are you using a formula to get a longer distance, you should be using 9.09 kilometers instead.
Click to expand...
Gotcha. I only mention it again to ask if your opinion has changed with that revelation. I can edit my calc to use your measured length of the actual longest root, though I don't think it will terribly change the final result.
 
Mr._Bambu said:
I can edit my calc to use your measured length of the actual longest root, though I don't think it will terribly change the final result.
Click to expand...
That would be appreciated, even if it doesn't change the result that much.
 
Therefir said:
And various question for Hagane, you used this formula "sqrt(1.75^2+2*(8.80859029787234)^2)" to get a distance of 12.57954792794800 kilometers, I assume this is a formula to obtain the length of inclined objects, but I'm not sure, could you explain that.
Click to expand...
The line of logic I followed was that the mountain was a 3D object, so I had to get the distance from a 3D plane
 
But Smaug was inside the mountain at an unknown altitude when the shake happened, wasn't he? And the tremor waves would reach all corners of the mountain no matter where exactly he was.
 
Therefir said:
But Smaug was inside the mountain at an unknown altitude when the shake happened, wasn't he?
Click to expand...
Hence why I didn't multiple variations of the calc

Edit: It's not anymore than 3.5 km though, that is the canonical height of the mountain
 
Last edited:
Oh, right, totally forgot. I'll do that now, actually.
 
Hagane_no_Saiyajin said:
Might I need to edit the distance for my calc too?
Click to expand...
Therefir said:
But Smaug was inside the mountain at an unknown altitude when the shake happened, wasn't he? And the tremor waves would reach all corners of the mountain no matter where exactly he was.
Click to expand...
Hagane_no_Saiyajin said:
Hence why I didn't multiple variations of the calc

Edit: It's not anymore than 3.5 km though, that is the canonical height of the mountain
Click to expand...
bump
 
It seems like Hagane might still need some help from @Therefir before we close this thread.
 
As I said, the formula only takes the distance in a 2d plane, it's irrelevant where exactly was the epicenter height when it comes to surface earthquakes, as they spread evenly through the surface.

Not to mention mountains aren't perfect slopes, and Hagane hasn't explained where exactly did they got that formula and what it does, it just seems like a way to make the feat 7-C when the distance is simply not enough.
 
Therefir said:
As I said, the formula only takes the distance in a 2d plane, it's irrelevant where exactly was the epicenter height when it comes to surface earthquakes, as they spread evenly through the surface.

Not to mention mountains aren't perfect slopes, and Hagane hasn't explained where exactly did they got that formula and what it does, it just seems like a way to make the feat 7-C when the distance is simply not enough.
Click to expand...
Thank you for helping out.

@Hagane_no_Saiyajin
 
Therefir said:
As I said, the formula only takes the distance in a 2d plane, it's irrelevant where exactly was the epicenter height when it comes to surface earthquakes, as they spread evenly through the surface.
Click to expand...
It isn't really a surface Earthquake were talking about now, if Smaug shook the Lonely Mountain, that simply means he literally shook the entire mass of the Lonely Mountain, not the surface of it
 
Okay then, just hope everyone don't mind keeping this thread open so I can make the calc, because getting the mass of the Lonely Mountain is going to be a pain in the butt because of its shape
 
No problem. I think that we can wait for a while.
 
They are completely different calcs now, I wouldn't call them versions.

But I would say your calc is more accurate to what Smaug was actually doing.
 
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