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Calculation based on jellal's new feat. Credit goes to a guy named "Y" on TMF.
The avb one is more elaborate. Pretty much what mine looks like. 159,000m is the distance between gray and the night sky jellal did in the horizon, where as the height of where jellal starts in dispersing the atmosphere should at least be 2km because that's the minimun height of the clouds, and in the scan we can clearly see that the clouds are being dispersed. hence using pythagorean theorem we can get the distance between the nightsky above gray to the nightsky at the horizon(this is lowballed btw, im using a straight line instead of an arc hence it's lower than what it should be) so x = squareroot(159,000-2,000) = 12,000m this will now be our "radius" which we will use to get the volume of the top portion of a sphere or spherical cap, a=12,000m
equation for volume of a portion of a sphere(sphere cap) is v=h(pi)/6 [3a^2+h^2] h = troposhere - height where he started moving the atmosphere= 20,000 - 2,000 = 18,000 m a = horizontal distance = 12,000 which gives us 3.17x10^12 m^3
density of the air is 1.225 kg/m^3, to get the mass we use density formula which is d=m/v, so m=(1.225kg/m^3)(3.17x10^12 m^3) =3.879x10^12 kg
now this the tricky part where we can only do assumptions we don't know how fast jellal turned everything into night, but there is no way it took him a long time considering it has already turned black in the horizon before he even cast his spell specially since he's bloodlusted and wanted to kill neinhart already. i think 5 secs is good time, so 12,000m/5secs = 2400
the energy formula is K=1/2mv^2 =1/2(3.879x10^12)(2400)^2= 1.117x10^19 J
The second one come from a guy named "Jerza Fernandes" from AnimeViceBoards.
http://animevice.boards.net/thread/6272/ft-jellals-atmospheric-dispersio
The avb one is more elaborate. Pretty much what mine looks like. 159,000m is the distance between gray and the night sky jellal did in the horizon, where as the height of where jellal starts in dispersing the atmosphere should at least be 2km because that's the minimun height of the clouds, and in the scan we can clearly see that the clouds are being dispersed. hence using pythagorean theorem we can get the distance between the nightsky above gray to the nightsky at the horizon(this is lowballed btw, im using a straight line instead of an arc hence it's lower than what it should be) so x = squareroot(159,000-2,000) = 12,000m this will now be our "radius" which we will use to get the volume of the top portion of a sphere or spherical cap, a=12,000m
equation for volume of a portion of a sphere(sphere cap) is v=h(pi)/6 [3a^2+h^2] h = troposhere - height where he started moving the atmosphere= 20,000 - 2,000 = 18,000 m a = horizontal distance = 12,000 which gives us 3.17x10^12 m^3
density of the air is 1.225 kg/m^3, to get the mass we use density formula which is d=m/v, so m=(1.225kg/m^3)(3.17x10^12 m^3) =3.879x10^12 kg
now this the tricky part where we can only do assumptions we don't know how fast jellal turned everything into night, but there is no way it took him a long time considering it has already turned black in the horizon before he even cast his spell specially since he's bloodlusted and wanted to kill neinhart already. i think 5 secs is good time, so 12,000m/5secs = 2400
the energy formula is K=1/2mv^2 =1/2(3.879x10^12)(2400)^2= 1.117x10^19 J
The second one come from a guy named "Jerza Fernandes" from AnimeViceBoards.
http://animevice.boards.net/thread/6272/ft-jellals-atmospheric-dispersio
