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A mistake in our value for the subatomic destruction of water

7,677
1,373
I was looking at the way our subatomic destruction value was obtained for water, and noticed a mistake. The value is obtained by using this to obtain the energy needed to separate a single water molecule into subatomic particles, then using density and molar mass to convert that to J/cc. However the calc mistook the energy/nucleus value of the mass defect for energy/nucleon (likely because the method he used for other materials gave energy/nucleon), and therefore added an unnecessary step of multiplying by the number of nucleons per molecule, getting the wrong answer.
So, the step “Now multiply that by the nucleon number.
8.975E12*18=1.6155E14j/mol
” shouldn’t be in the calculation.

So, to find the correct value just go through the rest of the calc with 8.975e+12 J/mol:
One mole of water weighs 18.078g

8.975e+12 J/mol/18.078g/mol = 496459785e+11J/g

Since 1g of water is 1cc, that’s 4.96459785e+11J/cc (note that this is the same result as just dividing the current value by 18)

I was unable to find any accepted calcs that are still in use that make use of this, so I don’t this will have an impact on any profiles.
 
Last edited:
I was looking at the way our subatomic destruction value was obtained for water, and noticed a mistake. The value is obtained by using this to obtain the energy needed to separate a single water molecule into subatomic particles, then using density and molar mass to convert that to J/cc. However the calc mistook the energy/nucleus value of the mass defect for energy/nucleon (likely because the method he used for other materials gave energy/nucleon), and therefore added an unnecessary step of multiplying by the number of nucleons per molecule, getting the wrong answer.
So, the step “Now multiply that by the nucleon number.
8.975E12*18=1.6155E14j/mol
” shouldn’t be in the calculation.

So, to find the correct value just go through the rest of the calc with 8.975e+12 J/mol:
One mole of water weighs 18.078g

8.975e+12 J/mol/18.078g/mol = 496459785e+11J/g

Since 1g of water is 1cc, that’s 4.96459785e+11J/cc (note that this is the same result as just dividing the current value by 18)

I was unable to find any accepted calcs that are still in use that make use of this, so I don’t this will have an impact on any profiles.
4.96459785e+11J/cc? Jeez, that’s 118.6567363767 (~119) Tons of TNT/cc!
 
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