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Additional revisions for Senran Kagura

Hagane_no_Saiyajin said:
Originally I was going to attempt at calcing the energy needed to melt Kyoto, but I came at a roadblock of sorts, try any pick which building should be used in this image here:
Click to expand...
Why? Just find the most common material and the one with the highest melting point. Can't be a super rare material, but one that is common and is in almost all buildings. The OG calc using the melting point of iron was fine, since iron is abundant in al of these buildings.

Glass, Iron, or whatever works fine.
 
TheRustyOne said:
Why? Just find the most common material and the one with the highest melting point. Can't be a super rare material, but one that is common and is in almost all buildings. The OG calc using the melting point of iron was fine, since iron is abundant in al of these buildings.
Click to expand...
Because for those materials you also require the latent heat of fusion for them to melt, not to mention that materials like glass and concrete have higher Specific Heat Capacities than air

Also, according to here, air has a Specific heat of 1.005 J/(kg*C) at 10 C
 
I don't understand what you're talking about.

Is the calculation not finding the energy required to heat the air/space of Kyoto to the temperature needed to melt iron/glass?
 
Hagane_no_Saiyajin said:
Let's just prioritize the High 8-C+ stuff, I think having some staff on here can help out
Click to expand...
I don't mind that.

But we need staff for that too. Can't change the profiles without staff agreement on it. I already said I agree with it, but my agreement means nothing.
 
DontTalkDT is usually very busy, so I think there's a low chance he'll respond. Though his response would be very appreciated.

Maybe prepare a summary of what is being discussed now or update the OP? Unless you want staff to talk about the spinning speed and High 3-A stuff?
 
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I agree with Rusty I'd just find the most common materials present across the area and find their melting points which would be any buildings present basically and you could try to find an estimate of the amount of buildings present there probably the easiest way would be using the common feat for incinerating/liquifying a building and still multiply that by the amount of buildings present in the region which you could simply find an estimate by looking it up


vsbattles.fandom.com

References for Common Feats

Throughout fiction and real life, there have been numerous feats demonstrating a certain character's or object's destructive power. This page's purpose is to consolidate calculations for those feats for better convenience in determining an object's or character's Attack Potency or Durability...
vsbattles.fandom.com vsbattles.fandom.com

https://vsbattles.fandom.com/wiki/User_blog:Mr._Bambu/General_Calc:_Incineration_of_a_Building
 
Well, I also think that the values I got from the calculator are also just as valid considering that the feat deals with heat and the link from which I got the calculator from literally deals with heat too. Also to ask, why would it just be buildings melting when the screenshot mentions a blast too?

Also, which building here in the image might be the best to be used?

 
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Come to think of it, when it comes to lifting strength, shouldn't Yomi upscale from Daidoji in Lifting Strength? I mean they literally DREW it as such:



(Physical strength ranking shown).
 
Hagane_no_Saiyajin said:
Well, I also think that the values I got from the calculator are also just as valid considering that the feat deals with heat and the link from which I got the calculator from literally deals with heat too. Also to ask, why would it just be buildings melting when the screenshot mentions a blast too?
Click to expand...
Just for a quick update, I had the original quote translated, this is what I got:

 
Giving my own personal knowledge of this series, I think the Glass melting version with latent heat in the calc above is currently the best way of getting the results.

This is still a low ball, but I think is reasonable enough with the information we have right now.

Unless someone can make a better calc.
 
Hagane_no_Saiyajin said:
@DemonGodMitchAubin

After playing about with this calculator, I found the value of Kagura's feat (assuming the Air blast radius to be the radius of Kyoto, ~16.2 km) to be 220-221 Megatons (7-A)



I also did a version assuming ionizing radiation radius and got 5.8-5.9 Gigatons (6-C)



And a version assuming minimum fireball radius: 8.54-8.6 Gigatons (6-C)

Click to expand...

If I were to take my pick from these values, it would be the fireball radius value because that is the radius where everything is vaporized within it which is consistent with "it seems that a astounding amount of heat is released, causing the elimination of the the entire area"
 
8-C+ characters become High 8-C+ via Orochi's calculation. (7.61 Tons of TNT)

High 7-A+ characters become 6-C. (5.36 Gigaton of TNT)

As I said, the glass melting end should be fine to use. Also I've recently learned that the method to find Mirai's reaction speed here isn't usable. However it means little since her bullet speed is able to meet the tank firing at half way, despite shooting after it fired, this means her bullet is equal to or faster than the tank's round.

As such her bullets and whoever scales should just be somewhere from 1530 m/s to 1750 m/s, which is Supersonic+ to Hypersonic. This would scale to their reactions and combat speed, their running/travel speed would be something else. Right now I can say Subsonic (138 m/s) for Hibari running faster than a bullet train.

Though other travel feats may exist.

@Dalesean027

For Kagura's melting feat.

Do you think the glass melting end is fine to use or the fireball radius in the calculator mentioned above?

Currently I've been unable to successfully find a way to calculating melting the majority of the buildings in the area as well.
 
Oops, never mind that. I forgot what the calc was doing. Thought it was something else. Should read again before speaking.

Regardless they'd be faster anyway with the bullet scaling.
 
TheRustyOne said:
For Kagura's melting feat.

Do you think the glass melting end is fine to use or the fireball radius in the calculator mentioned above?

Currently I've been unable to successfully find a way to calculating melting the majority of the buildings in the area as well
Click to expand...
Forgot about this thread what was the feat again?
 
It was this. Basically when Kaguya returns to her Reincarnation Sphere, an immense amount of heat is release that destroys the surrounding area.

The people in universe estimates the blast would wipe Kyoto off the map.

Currently the method being used is latent heat. The 6-C version replaces the Iron Melting temp to Glass Melting.

Though Hagane seems to get another type of results using the calculator above.
 
Hm well I'd say the glass method is fine then since its not an explosion
 
Dalesean027 said:
Hm well I'd say the glass method is fine then since its not an explosion
Click to expand...
Although, I got the calculator from here which, as the title says, deals with heat based feats

And this it the original quote with translation:



The fireball radius is being asked about because that's the radius were as the quote states "it seems that a astounding amount of heat is released, causing the elimination of the the entire area."
 
@TheRustyOne @Dalesean027 I played with the other calculator and got some interesting results (I used the emissivity of concrete):

Using melting of glass temperature



6.68794173162E+14 J/s or 1.59845643681166E+05 Tons of TNT/s (High 7-C)

Using boiling of glass temperature



1.73317516102E+15 J/s or 4.14238805215105E+05 Tons of TNT/s (High 7-C)

Using lightning bolt temperature:



3.57385635054E+19 J/s or 8.54172167911090E+09 Tons of TNT/s (6-C)

Using nuclear fireball temperature (although would like anyone willing to read this for help)



4.41221654155E+33 J/s or 1.05454506251195E+24 Tons of TNT/s (5-B)
 
I'm not familiar with the calculator at all. Not certain if that's usable here, if that's how it works, and if it's better over the latent heat method.

However I don't know why you keep making these different temperature results, such as lightning or nuclear fireball stuff, it's just clutter.

@Dalesean027

Are you familiar with this?
 
TheRustyOne said:
I'm not familiar with the calculator at all. Not certain if that's usable here, if that's how it works, and if it's better over the latent heat method.

However I don't know why you keep making these different temperature results, such as lightning or nuclear fireball stuff, it's just clutter.

@Dalesean027

Are you familiar with this?
Click to expand...
At work still can't answer
 
TheRustyOne said:
I'm not familiar with the calculator at all. Not certain if that's usable here, if that's how it works, and if it's better over the latent heat method.

However I don't know why you keep making these different temperature results, such as lightning or nuclear fireball stuff, it's just clutter.

@Dalesean027

Are you familiar with this?
Click to expand...
No I'm not familiar with that at all and honestly the end we currently have is good enough as is
 
TheRustyOne said:
I'm not familiar with the calculator at all. Not certain if that's usable here, if that's how it works, and if it's better over the latent heat method.
Click to expand...
I'll quote the pages says:

When dealing with a feat that is heat related only, we can still manage to find Destructive capacity, by finding the given temperature of the object in question, estimate or calculate its surface area and emissivity, and apply the values to the following Calculator:

http://www.endmemo.com/physics/radenergy.php
Click to expand...
Of course considering that a translation of the original quotes says "it seems that an astounding amount of heat is released, causing the elimination of the the entire area", there's no reason to believe that Kagura can't reach those temperatures
 
Last hypersonic calc is invalid since the truck rotates across the axis passing though its centel and centrifugal force only describes the stress the truck experiences. In fact even if centrifugal force does push agains the umbrella you only need to push it upwards to counter that force. There's no need to swing the umbrella that fast
 
Asked by Ant to talk here.

If one attack destroys an entire area... can non-nuclear air blast fireball yield calculator be slapped into instead?

Also, is there "no crater behind"? Like ordinary nuclear blasts also claims "leaves no crater behind" but it does.

Hagane_no_Saiyajin said:
Although, I got the calculator from here which, as the title says, deals with heat based feats

And this it the original quote with translation:



The fireball radius is being asked about because that's the radius were as the quote states "it seems that a astounding amount of heat is released, causing the elimination of the the entire area."
Click to expand...

Likely just meaning "Kyoto would be covered by one fireball" if you actually take the context.

Just measure the minimal circle areea required to cover one Kyoto, deduce its radius, and slap the non-nuclear air blast fireball yield and ask me to evaluate.
 
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Jasonsith said:
Likely just meaning "Kyoto would be covered by one fireball" if you actually take the context.

Just measure the minimal circle areea required to cover one Kyoto, deduce its radius, and slap the non-nuclear air blast fireball yield and ask me to evaluate.
Click to expand...
This is what I had gotten

And a version assuming minimum fireball radius: 8.54-8.6 Gigatons (6-C)

Click to expand...

Although what is your stance on melting vs nuclear fireball vs radiation?
 
Since I see the thread is focusing on the calcs, will take a look at the ability additions shortly
 
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