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Tensei Shitara Slime Datta Ken Discussion Thread 20

MrTim said:
The formula for calculating the gravitational force:

F = G * (M * m) / r^2


Sun:

  • F is the force of gravity (Newtons)
  • G is the gravitational constant (6.674 * 10^-11 Nm^2/kg^2)
  • m1 is the mass of object 1 (kg) (mass of the Sun: 1.989 * 10^30 kg)
  • m2 - object weight 2 (kg) (object weight: 70 kg) (human)
  • r is the distance between the centers of mass of objects (meters) (1 meter)

Calculation:

F = 6.674 * 10^-11 * (1.989 * 10^30 * 70) / 1^2

F ≈ 9.28 * 10^21 N

Therefore, the gravitational force of the Sun on an object weighing 70 kg at a distance of 1 meter from it will be approximately 9.28 * 10^21 Newtons.


Massive Star like Betelgeuse :

  • Betelgeuse mass (M): Approximately 11.6 solar masses, which is about 2.31 x 10^31 kg.
  • Gravitational constant (G): 6.674 x 10^-11 N(m/kg)^2
  • Object weight (m): 70 kg (human)
  • Distance from the center of Betelgeuse to the object (r): 1 meter

Calculation:

F = 6.674 x 10^-11 * (2.31 x 10^31 * 70) / 1^2

F ≈ 1.08 x 10^24 N

The gravitational force of Betelgeuse on an object weighing 70 kg at a distance of 1 meter from the star will be approximately 1.08 x 10^24 Newtons.
Click to expand...
So pre stellar?
 
Mizuki67 said:
one calc supporter joxay is banned
Click to expand...
Can you stop mention nonsense about Jozay, he doesn't have any accepted calculations and I haven't seen he try it, it really disrespects the efforts of those who make the calculations.
 
CodeCCLL said:
Can you stop mention nonsense about Jozay, he doesn't have any accepted calculations and I haven't seen he try it, it really disrespects the efforts of those who make the calculations.
Click to expand...
I said that "i have seen"
He did a very good calc on rimuru absorption speed but it was denied base on there wasn't any time frame
I haven't seen any other calc from this verse except from @Catpija so far have i, also how is this even offensive?
Franz said:
This would tie in well with characters like Carrera, Ultima, and Testarossa during the invasion of the empire before being able to use their power to hurt Velgrynd
Click to expand...
Carrera gravity collapse need calculations too lol
Porbably be around star level, perhaps?
Idk, but her own is an accurate black hole so...
 
Mizuki67 said:
Carrera gravity collapse need calculations too lol
Porbably be around star level, perhaps?
Idk, but her own is an accurate black hole so...
Click to expand...
In general they will all need to be recalculated considering the x100 more solid in the Cardinal world. Carrera's Gravity Collapse would indeed be star level. The character like Hinata would surely be planet level or large planet
 
Franz said:
In general they will all need to be recalculated considering the x100 more solid in the Cardinal world. Carrera's Gravity Collapse would indeed be star level. The character like Hinata would surely be planet level or large planet
Click to expand...
Moon level actually
Anyways, carrera is already 2-C, the star level bit isnt necessary
We did the calcs @MrTim helped out
And they seem to be small planet/large moon level (we can just say planet level ngl)
With LS of class Z
True dragons LS should then be stellar or multi-stellar with this scan
gyazo.com

Gyazo

gyazo.com gyazo.com
 
MrTim said:
The formula for calculating the gravitational force:

F = G * (M * m) / r^2


Sun:

  • F is the force of gravity (Newtons)
  • G is the gravitational constant (6.674 * 10^-11 Nm^2/kg^2)
  • m1 is the mass of object 1 (kg) (mass of the Sun: 1.989 * 10^30 kg)
  • m2 - object weight 2 (kg) (object weight: 70 kg) (human)
  • r is the distance between the centers of mass of objects (meters) (1 meter)

Calculation:

F = 6.674 * 10^-11 * (1.989 * 10^30 * 70) / 1^2

F ≈ 9.28 * 10^21 N

Therefore, the gravitational force of the Sun on an object weighing 70 kg at a distance of 1 meter from it will be approximately 9.28 * 10^21 Newtons.


Massive Star like Betelgeuse :

  • Betelgeuse mass (M): Approximately 11.6 solar masses, which is about 2.31 x 10^31 kg.
  • Gravitational constant (G): 6.674 x 10^-11 N(m/kg)^2
  • Object weight (m): 70 kg (human)
  • Distance from the center of Betelgeuse to the object (r): 1 meter

Calculation:

F = 6.674 x 10^-11 * (2.31 x 10^31 * 70) / 1^2

F ≈ 1.08 x 10^24 N

The gravitational force of Betelgeuse on an object weighing 70 kg at a distance of 1 meter from the star will be approximately 1.08 x 10^24 Newtons.
Click to expand...
This is good, less complicated than my idea

But why Betelgeuse? The minimum mass for a star to be considered massive is plus or minus 8 solar masses, Betelgeuse has around 20, it would be better to consider a low and a high ball for the calculation, Be can serve as a medium ball I guess.

I propose this:

Low ball: 8 solar masses

Medium ball: 20

High ball 30, which is about the amount of mass needed to start forming black holes.

Although this may change at the discretion of some staff.
 
Meli_Tempest said:
This is good, less complicated than my idea

But why Betelgeuse? The minimum mass for a star to be considered massive is plus or minus 8 solar masses, Betelgeuse has around 20, it would be better to consider a low and a high ball for the calculation, Be can serve as a medium ball I guess.

I propose this:

Low ball: 8 solar masses

Medium ball: 20

High ball 30, which is about the amount of mass needed to start forming black holes.

Although this may change at the discretion of some staff.
Click to expand...

Can you put all of this into a blog?
Lets get the calc observed
 
As for Carrera's feat, to calculate black holes we need data that the novel does not provide, so we may have to wait until the appearance of the feat in the anime or manga.
 
Meli_Tempest said:
As for Carrera's feat, to calculate black holes we need data that the novel does not provide, so we may have to wait until the appearance of the feat in the anime or manga.
Click to expand...
Forget about that one
I'll handle it
You can add the minitz issue first
Then we can get LS feat evaluated
 
Mizuki67 said:
I was wondering if you could all your calcs in a blog btw
This is the scan

The scan that it is legitimate since it is better than kumara gravity manip
Click to expand...

Im not good at editing content or creating blogs, so... sorry
 
It seems I made a mistake in calculating Betelgeuse ehe~
btw rating will remain the same, within Class Z

The formula for calculating the gravitational force:

F = G * (M * m) / r^2
Low Ball: Spica is about 10 times more massive than the Sun.

The weight of the Spica = 10 * 1.989 * 10 ^30 kg = 1.989 * 10^31 kg
Click to expand...
  • F is the force of gravity (in Newtons)
  • G is the gravitational constant (6.674 * 10^-11 N * m^2/kg^2)
  • m1 is the mass of the Spica (1.989 * 10^31 kg)
  • m2 - object weight (70 kg) (human)
  • r is the distance between the centers of mass (1 meter)

F = 6.674 * 10^-11 * (1.989 * 10^31 * 70) / 1^2

F ≈ 9.29 * 10^22 N

Thus, the gravitational force acting on an object weighing 70 kg at a distance of 1 meter from the center of the Spica would be approximately 9.29 * 10^22 Newtons.
Click to expand...
Mid ball: Deneb is about 20 times more massive than the Sun.

The mass of the Deneb = 20 * 1.989 * 10 ^30 kg = 3.978 * 10^31 kg
Click to expand...
  • F is the force of gravity (in Newtons)
  • G is the gravitational constant (6.674 * 10^-11 N * m^2/kg^2)
  • m1 is the mass of Deneb (3.978 * 10^31 kg)
  • m2 - object weight (70 kg) (human)
  • r is the distance between the centers of mass (1 meter)

F = 6.674 * 10^-11 * (3.978 * 10^31 * 70) / 1^2

F ≈ 1.858 * 10^23 N

Thus, the gravitational force acting on an object weighing 70 kg at a distance of 1 meter from the center of Deneb would be approximately 1.858 * 10^23 Newtons
Click to expand...
High ball: Random unknown star is about 30 times more massive than the Sun.

The mass of Random unknown star = 30 * 1.989 * 10^30 kg = 5.967 * 10^31 kg
Click to expand...
  • F is the force of gravity (in Newtons)
  • G is the gravitational constant (6.674 * 10^-11 N * m^2/kg^2)
  • m1 is the mass of the star (5.967 * 10^31 kg)
  • m2 - object weight (70 kg) (human)
  • r is the distance between the centers of mass (1 meter)

F = 6.674 * 10^-11 * (5.967 * 10^31 * 70) / 1^2

F ≈ 2.787 * 10^23 N

Thus, the gravitational force acting on an object weighing 70 kg at a distance of 1 meter from the center of a star would be approximately 2.787 * 10^23 Newtons.
Click to expand...
 
Last edited:
MrTim said:
It seems I made a mistake in calculating Betelgeuse ehe~
btw rating will remain the same, within Class Z

The formula for calculating the gravitational force:

F = G * (M * m) / r^2
Click to expand...
How about kumara who's gravity can interfere with planets?
That should make the lifting strength planet level at the least right?
 
Mizuki67 said:
How about kumara who's gravity can interfere with planets?
That should make the lifting strength planet level at the least right?
Click to expand...

As far as I understand it should be at least Class E, since it can manipulate planets despite the gravitational force of local star
(I take into account a star comparable to sun)

pushing a planet or a star is not the same as destroying it, space-time itself is taken into account here as the fabric on which these stars are located.
Well, that's how physics works.
 
Last edited:
Mizuki67 said:
How about kumara who's gravity can interfere with planets?
That should make the lifting strength planet level at the least right?
Click to expand...

vsbattles.fandom.com

Planet Level Slime?

vsbattles.fandom.com vsbattles.fandom.com

I made the blog, although it doesn't really look anything impressive, I think I didn't get anything wrong, but you can take a look at it, I must sleep.

Pd: remembering I decided to change the mid and highball thanks to a friend's reminder that the maximum possible mass is 150 solar masses.
.
 
MrTim said:
As far as I understand it should be at least Class E, since it can manipulate planets despite the gravitational force of local star
(I take into account a star comparable to sun)

pushing a planet or a star is not the same as destroying it, space-time itself is taken into account here as the fabric on which these stars are located.
Well, that's how physics works.
Click to expand...
Alright, thanks a bjcb
Meli_Tempest said:
vsbattles.fandom.com

Planet Level Slime?

vsbattles.fandom.com vsbattles.fandom.com

I made the blog, although it doesn't really look anything impressive, I think I didn't get anything wrong, but you can take a look at it, I must sleep.

Pd: remembering I decided to change the mid and highball thanks to a friend's reminder that the maximum possible mass is 150 solar masses.
.
Click to expand...
This will help
 
Well screw it ig
vsbattles.com

Stellar level lifting strength (Revision of Tensura)

well, we haven't gotten any answer from any calc mod on the AP ratings, but LS seems straightforward, okay here we go The Force exerted The force exerted is the GF (gravitational force, tensile force, Crushing force), was on par with a massive star That was Oppressor, his unique skill, and it...
vsbattles.com vsbattles.com
 
Eikichi_Sensei said:
vsbattles.com

My first Slime CRT (Tensura): Adding things and questions.

Good morning/afternoon/night. This is my first CRT of adding things to Rimuru's profile. I would like Slime Rimuru to have Low Godly for the following reasons: https://imgur.com/gallery/x8lgODc https://imgur.com/gallery/8qV9gpK I was also wondering if anyone would be kind enough to answer...
vsbattles.com vsbattles.com
Click to expand...
Ohh christ
Of course everyone wants to open a CRT
😂
Meli_Tempest said:
vsbattles.fandom.com

Planet Level Slime?

vsbattles.fandom.com vsbattles.fandom.com


I fixed all the little details and I think it works smoothly now.
Click to expand...
Let me take a look
 
Hey everyone, @CodeCCLL sorry to say but we have decided to yank our CM1 for SPL and magic back to type 2
It feels and sounds stupid, there's also numerous wanks on it, if someone was serious, downgrading that thing would take less than no time at all
 
Eikichi_Sensei said:
So only True Dragon will keep CM 1? 🤔
Click to expand...
Safe to say, yes
Reasons:
  1. It is consistent with the storyline
  2. It have backups and better wordings to it
That's why i have decided to remove CM1 from magic, also ultimate skills can probably keep theirs as well
I have my reasons for that too
 
if anyone with brain cells read that CM1 for SPL thread you should know how silly it sounded, lol, so its better to be safe than sorry
 
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