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Samurai 8 Discussion Thread

*SPOILER*

Yet to be confirmed but:


1. If the light trail is the same of when Ata cut into pieces the asteroid...then that asteroid was larger than a moon, which means he casually performed a moon+ level feat

[[1]]

2. Ata has reached Hachimaru's planet. Confirmed FTL/LS?

3. Ata landing on the moon, creating a massive crater...is a country level feat? Durability and attack potency?
 
AstralKing7 said:
Kishi ain't playing no games ƒÿ▒ƒÿ▒ƒÿ▒
SPOILER:

And this is the first villain. Now i'm curious to know how strong Mujin and Yasha are. If Ata can casually slice planetoids larger than a moon...then "Daruma the Star Buster Dog Samurai" sounds correct.
 
I think the first one is quite a low ball for the meteor's size, you can see ho wmuch bigger it is meant to be but most of it is off screen. which is why I did an avrage size and got island level..not bad though.
 
Rocker1189 said:
I think the first one is quite a low ball for the meteor's size, you can see ho wmuch bigger it is meant to be but most of it is off screen. which is why I did an avrage size and got island level..not bad though.
I didn't want to assume many things so I just did a genreal low ball with pixel scaling.

The speed one is also just based off him leaving the planet wasn't including him reaching what seemed to look like an asteroid belt.
 
The first calc could be completely wrong if the size of Ata's light trail size, when he landed on the moon, is the same when he cut that asteroid.
 
one thing that confuses me is that in the spoiler it looks like the light streak he leaves behind creates a shadow on the moon. Is that possible?
 
yeah, it is actually

could you do a calc based on our moon size for the trail? Then calc his feat from there?
 
I did a quick little calc on the crater assuming that the moon was the same size as our own and got multi-continental levels for pulverisation and vaporization.

But I will fo the full chapter to be released first before creating any calc blogs
 
i just re-read ch. 8 and ata says at beginning of it that hachimaru is in the "ball galactic quadrant" and at the end of it(after cutting the asteroid) he says " i'm still stuck in the cube galactic quadrant"

does anyone knows whats the size of a galatic quadrant knowing that we can get ata flight speed since it only took him 12 hrs to get to hachimaru planet(taking in count that it was daytime when he detect hachimaru and by the time he arrived the moon was in the sky that seems to be the case)
 
redoing the asteroid feat with the trail size calced..it is looking very very big lmfao. might be some moon level maybe even small planet level shit.
 
ok I underestimated it....:

69.35/7.8 = 8.89

using this to get the trail diamter and this for the asteroid size

875.95px =3474200m

25.63px = 101,653m

4.45px = 101,653m

272.94px = 6234925.6847275285709063225736937m

741.52px = 16938968.614857320238508303344491m

using ellipsoid formula: 447244714449275499271.79620674116m^3

pretty damn big asteroid.

guess I would do KE and destruction formula:

calcing KE:

using the same density I got in the last calc of this:

3136kg/m^3 mass = 1402559424512927965716352.9043403kg

speed would be average asteroid speed again = 25000m/s

KE = 4.3829982016028998928636028260634e+32 joules ... 5-B hmmm

calcing using destruction formula:

frag: 3577957715594203994174369653.9293joules or 3.58e27joules = High 6-A

v.frag: 30859885297000009449753938265.14joules or 3.09e28 joules = High 6-A

High 6-A to 5-B.
 
already 5B and MFTL+ 9 chapters in. God bless kishimoto

EDIT: Remember ALL of these feats are casual and aren't even from the real ata
 
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