- 3,751
- 321
So utilizing DontTalk's method of calculating the energy of Plasma usage, I think I have what I need for calculating what I did in my previous threads.
And like in the other thread, the scenario is where the tech transcends conventional science and they have unlimited resources.
Since Fusors are fusion devices with using electricity, I will be using the material for fusion Deuterium,
Number of atoms:
6.022e+23 (Avogadro's Number) * .1967 g/cm^3 (Deuterium Density) * 308 cm^3 (Volume) / 2.014 g/mol (Deuterium Molar Mass) = 1.8114918e+25 number of atoms
----
The degree of Ionization would be likely total in this case so will be 1.8114918e+25 ions
——
1 Atomic Number of Deuterium = 13.6 eV
1.8114918e+25*13.6 = 2.4636288e+26 Watts
Thoughts?
And like in the other thread, the scenario is where the tech transcends conventional science and they have unlimited resources.
Since Fusors are fusion devices with using electricity, I will be using the material for fusion Deuterium,
Number of atoms:
6.022e+23 (Avogadro's Number) * .1967 g/cm^3 (Deuterium Density) * 308 cm^3 (Volume) / 2.014 g/mol (Deuterium Molar Mass) = 1.8114918e+25 number of atoms
----
The degree of Ionization would be likely total in this case so will be 1.8114918e+25 ions
——
1 Atomic Number of Deuterium = 13.6 eV
1.8114918e+25*13.6 = 2.4636288e+26 Watts
Thoughts?
