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i am very sorry but this did appear in the trailer for the arc, episode lists also have themOof. Thats a spoiler if I ever did see one....xD
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i am very sorry but this did appear in the trailer for the arc, episode lists also have themOof. Thats a spoiler if I ever did see one....xD
Bump because of this.Hmmm. I haven't been keeping up with the anime, but looking into episode details on Bulbapedia & Wikipedia, it seems like there's some potentially useful stuff.
It may be worth looking into. Do we have a place to freely discuss such spoilerific content?
Source? Your link to the number leads to the Sun energy production. Either way this is 5 times higher than Assaltwaffles amount in his blog, and even he admitted that was a high number. Use the number of stars in the average galaxy (100 million) x 2 trillion instead. That's 2.0e+20 stars. Also, why are you assuming each star is like the Sun when Assalt's blog implies the average star is significantly smaller than that?The average amount of stars in the universe is 10^24***
If what you say is indeed true then wouldn't that make the number of stars significantly less, since a lot of them would have already been dead and gone? Or outside the observable Universe?Since Necrozoma absorbed all the light in the universe, It will have to absorb all the light that has been produced in the universe. The light of the stars that hit the earth are light that takes millions/billions of years to reach our planet, that's years of energy out put that's already out in the universe. Necrozoma by virtue of absorbing all light in the universe would also have to absorb this light. Even after a star dies, all the light it has emitted still exists in the universe. Many of the stars we see now are all ready dead and gone.
https://vsbattles.fandom.com/wiki/User_blog:Assaltwaffle/The_Average_StarOf course, let me know if you think my methods were correct or have any suggestions. Thoughts?
I'm not the OP, but the amount was probably taken from this site. The number of stars in a galaxy assumed in the link seems corroborated by this as well.Source? Your link to the number leads to the Sun energy production. Either way this is 5 times higher than Assaltwaffles amount in his blog, and even he admitted that was a high number. Use the number of stars in the average galaxy (100 million) x 2 trillion instead. That's 2.0e+20 stars.
All of this is banking on the idea that each galaxy is the size of the Milky Way, which is supposed to be large compared to other galaxies. The first link arbitrarily assumed an average based on the larger than normal Milky Way. If it's bigger than average, then it's an outlier. We'd be using a very unjustified high end.
Hey man, I never said I said it was right, js what it was.All of this is banking on the idea that each galaxy is the size of the Milky Way, which is supposed to be large compared to other galaxies. The first link arbitrarily assumed an average based on the larger than normal Milky Way. If it's bigger than average, then it's an outlier. We'd be using a very unjustified high end.
Source? Your link to the number leads to the Sun energy production. Either way this is 5 times higher than Assaltwaffles amount in his blog, and even he admitted that was a high number. Use the number of stars in the average galaxy (100 million) x 2 trillion instead. That's 2.0e+20 stars. Also, why are you assuming each star is like the Sun when Assalt's blog implies the average star is significantly smaller than that?
Source on 100 million/galaxy. You can literally look up "average number of stars in the average galaxy".
If what you say is indeed true then wouldn't that make the number of stars significantly less, since a lot of them would have already been dead and gone? Or outside the observable Universe?
https://vsbattles.fandom.com/wiki/User_blog:Assaltwaffle/The_Average_Star
Look at this, then find the lifespan of the most common star, then find the energy it gives per second, multiply by its lifespan, and redo the calc based on it.
I made an error linking it. If you copy and past the link shown, it would go to the page that I got it from. It has been fixed though.
Anyways if you need a better source, I can provide you an excerpt from a 2015 text book that claims that the universe:
Now, the text book is before the research in 2016 that declared there to be at least 2 trillion galaxies, but it till lists the average galaxy to have 100 billion galaxies and the amount of stars in the universe to be 10^23.
Yeah, but equating the leftover light to the total light energy they'd produce over the course of their lifespan? I kinda doubt that would still be left over by this point. All we're seeing is the last remnants of light from those stars.They are gone but the light they produced still exists and will always exist and should be counted.
Averages that are taken from the mass and radius of several star classifications. Different stars of different sizes and colors won't give off the same amounts of energy as the Sun and won't have the same lifespan.These are all averages for destruction.
76% of all stars are red dwarfs. When I say "average" I mean "most common", since these stars are going to make up a huge bulk of your calculations total energy as a result of their commonness. Say there are 2.0e+23 stars out there. If red dwarfs make up 76% of all stars, then 1.52e+23 of them are going to be red dwarfs. Give or take.There is no such thing as an average star. And you can't get an average light output or lifespan either because that is all dependent on the type of stars and is all proportional.
Where did this come from? I'm not as doubtful as I am the number of stars, but I just want to be certain.Even if I use red dwarfs, the most abundant type of stars in the universe, they have an output that's as low as 1/10,000 of the Sun's Light, with 1000 times the life span. It comes off to 10^66. If you see above, Professor asked to use Sirius and that came up to a 2.5x difference. It doesn't matter what kind of star you use, it will be around each other.
I'm not sure why that is the way it is since the Sun is a class G star, making up 7.5% of stars. The odds of encountering a Sun/Sunlike Star aren't very high in terms of percentage. I just personally feel it is safest to use the most common star classifications since they are the ones you are going to be seeing the most of.Now, the reason I use the Sun as the standard is because across the vs battling world, the sun is used as the standard for all star calcs.
I would take a text book that's written to teach people astronomy as a better source than websites. Even the one you linked just quotes the professor and doesn't give us his methodology or the research he's quoting from. Of course if there is some scientific journal or research to go by we should use those.Normally I wouldn't question this stuff, but the textbook would have to provide a source on the average galaxy housing that many stars for a few reasons I find contradictory to their claims. Such as the Milky Way being the second-largest galaxy in the Local Group. Heck, most websites I've been to tell me the Milky Way is bigger than average anyways, not the largest by any means, but certainly not the average or most common type in terms of star count.
Yeah, but equating the leftover light to the total light energy they'd produce over the course of their lifespan? I kinda doubt that would still be left over by this point. All we're seeing is the last remnants of light from those stars.
Wikipedia page for Red Dwarfs which then links to this article.Where did this come from? I'm not as doubtful as I am the number of stars, but I just want to be certain.
I'm not sure why that is the way it is since the Sun is a class G star, making up 7.5% of stars. The odds of encountering a Sun/Sunlike Star aren't very high in terms of percentage. I just personally feel it is safest to use the most common star classifications since they are the ones you are going to be seeing the most of.
Averages that are taken from the mass and radius of several star classifications. Different stars of different sizes and colors won't give off the same amounts of energy as the Sun and won't have the same lifespan.
76% of all stars are red dwarfs. When I say "average" I mean "most common", since these stars are going to make up a huge bulk of your calculations total energy as a result of their commonness. Say there are 2.0e+23 stars out there. If red dwarfs make up 76% of all stars, then 1.52e+23 of them are going to be red dwarfs. Give or take.
It was already reported on the Rule Violations Thread.yall who th just changed UN to 4-A? Not only was it the worst edit ive seen but it is 4-A and not the 3-C that we calced
Yeah I reported that, and DDM fixed it.It was already reported on the Rule Violations Thread.
I'm kinda surprised Cal hasn't seen this yet.Speaking of which, how many more supporters do we need for this to get accepted?
it was just some dude with 0 edits or replies. Must've seen our thread or tried to use a headcanon. They literally changed all of the tiers listed to 4-A and in the description there they only changed one stating that at full power it attacks with MSS level attacks. Newbies man!Funny thing is I saw from a glance that UN was edited, but I never thought it would be a whole tier edit.
seems legitNo idea. You’d have to prove stars go on and on and on rather than just stop at some point followed by empty space.
And does the textbook provide a source for where it gets these numbers? I have good reason to suspect why it might be faulty: That it's basing the number of stars in the average galaxy off the Milky Way, which; ya know, isn't average size. While you may be right that the textbook was made before 2 trillion galaxies, it seems as the number of stars changed because of the number of galaxies changed. Being designed to teach people astronomy doesn't make it wrong where it is, and if it makes an assumption like that, it needs to be pointed out.I would take a text book that's written to teach people astronomy as a better source than websites. Even the one you linked just quotes the professor and doesn't give us his methodology or the research he's quoting from. Of course if there is some scientific journal or research to go by we should use those.
Fair enough, you might have actually given me an idea for something else myself.The leftover light is the total light energy. Remember that light is travelling through the universe from the moment of birth to the star's death. All of it being emitted and will keep traveling after the stars death.
Hmm, so it sounds like 9.5 trillion years (2.99790797e20 seconds) and 3.846e22 joules per second which comes out to 1.15299541e43 joules of light total for a single red dwarf. That comes out to (2.0e20 x 0.76) x 1.15299541e43 = 1.75255302e63 joules (Using my average for galaxies that is). Mind you, this doesn't take into account other stars, but still. You get similar results if you take into account the number of Suns there are and how much energy they give off.Wikipedia page for Red Dwarfs which then links to this article.
That doesn't make it right nor accurate to do so, which I'm trying to ensure this is.That's just how it is. I think it has to do with the sun being people's reference for stars in fiction and most stars in fiction are shown to be like the sun.
Honestly, it depends on the Star and how many there really are.Like I said, it really doesn't matter what type of star you use, it all is around the same ball park give or take a few exponents.
I just realized that you should probably put tags on this so the Staff will Notice it better so it can be Accepted or Rejected.
If it was, I wasn't around for that. I'm a relatively recent addition to VSB. Only been here for about a year now.Wasn't this already calculated,applied, downgraded, then put back because it's indeed a universe
Well what about TIA’s video on the subject? It seems more accurate then the one we use.Well now that I actually look
I dunno about the logic of absorbing all the light that was ever produced thus ramping it all the way up to 3-C
Like, basic entropy says you could still just do the inverse of the 4-B feat and get mostly the same result, even if there is still some light lurking in other places
you should have followed this up with a linkWell what about TIA’s video on the subject? It seems more accurate then the one we use.
Sorry, here it isyou should have followed this up with a link
Well, there are fundamental differences between the equations used. We used meters, and divided by the distance the the sun, while they used parsecs and divided by 10.