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My Hero Academia General Discussion Thread #18

Bigger question—Wasn’t the weather in America still the Todoroki Storm/Typhoon? Doesn’t that mean Deku straightforwardly scales above it entirely, now?
 
So, what happe-

chris-pratt-andy-dwyer.gif
 
So getting to the power scaling part, how do we calc the the storm destruction. We don't how big it was but we do know it big enough to affect weather in USA. Plus the winds still being affected days after the punch.
 
Gitagon said:
I do wonder how long Horikoshi intends the epilogue to be since he specifically mentioned it.
Click to expand...
Similar to what Shimura said above, I think we probably have 2 - 5 chapters left. There’s probably like, 2 chapters worth of wrap-up at most for any characters that were unaccounted for, then the rest might be a short timeskip that may or may not lead into a sequel Year 2 or Year 3 series.
 
GoldExPoints said:
Similar to what Shimura said above, I think we probably have 2 - 5 chapters left. There’s probably like, 2 chapters worth of wrap-up at most for any characters that were unaccounted for, then the rest might be a short timeskip that may or may not lead into a sequel Year 2 or Year 3 series.
Click to expand...
I don't think so. Shonen jump would have given us several warning before mha end given its also a big series. Theirs also the fact that horikoshi has also recently comment about this series ending.

Horikoshi's comment in this week's Jump:
Writing conventions say that the conclusion of a story should be short, but this is not the type of manga that can immediately end after the fighting is done, so I'll keep going for a little while. We're going back to the title.

This statement has also been confirmed by one of mha best news reporter. So from the looks of things we still have a mini arc that will likely focus on the side effects of the war and the todoroki's drama.

I would say we still have atleast 10+ or 8 chapters to go.
 
Dreymannn said:
MHA part 2, introducing androids and possibly aliens. This is where we also discover Deku is actually half alien and his father is no where to be found because he's in space somewhere.
Click to expand...
Didn't they say that if Quirks didn't happen, humans would be taking Vacations on Mars ? Lets go to space.
 
It’s interesting that Hori is seeming to fully double down on Deku being Quirkless (Outside of the dying Embers). Edit: Especially because this implies the way to “Complete the Quirk” and “Make it his” is through obliterating it as if it never existed. The only “Correct” way for it to exist (“use it as it was intended”/“Make it as it should be”) is to never have existed at all/kill it.
 
57Dev said:
So Mash vs Deku and Asta vs Deku is a possibility now.
Click to expand...
Nah, Mash vs Deku is an impossibility now, because pre training Mash is 6-A (Need to update it), and post training Mash is among the highest of High 6-A's and gets to 5-C through Weakness mode. And then there's his purgatory training...
 
Time to make a crazy unpolished high-balled calc, I will just be focusing on the winds.
So as stated on the chapter, the power of Deku's final punch caused winds so strong that they could reach all the way to America even days after the event.

The shortest distance between Japan and Washington, where the reporter is located, is 7,835 km, that will be our radius.

The bulk of the atmosphere is located close to Earth’s surface—up to a distance of around 8 to 15 kilometers, so we will be using 11.5 kilometers for our height.

Having these two values, we can use this calculator to find the mass of air Deku's punch had to push to reach all they way to America. The average elevation of Japan is 438 meters above sea level, the air pushed has a thickness of at least 11,500 meters, and an area of 192853655084263.69 (pi*7835000^2).

Mass = 1.50*10^18 Kilograms of Air

Now we just need to find the speed of the winds, which were stated to be "strong". The wind reached America a few days after the battle, let's say 2 days, or 172800 seconds:

Speed = 7835000/172800 = 45.34 m/s

Strong stuff indeed, probably too strong, but let's continue.

Finally we can the kinetic energy of this feat.

Energy = 1/12*2920000000000000000*45.34^2 = 500224129333333333333.33 Joules

Giving us a grand total of... 119.55 Gigatons.
I don't know what I cooked but it got burned some way through.
 
Last edited:
Therefir said:
Time to make a crazy unpolished high-balled calc, I will just be focusing on the winds that reached America.

So as stated on the chapter, the power of Deku's final punch caused winds so strong that they could reach all the way to America even days after the event.

The shortest distance between Japan and Washington, where the reporter is located, is 10,906 kilometers, that will be our radius.

The bulk of the atmosphere is located close to Earth’s surface—up to a distance of around 8 to 15 kilometers, so we will be using 11.5 kilometers for our height.

Having these two values, we can use this calculator to find the mass of air Deku's punch had to push to reach all they way to America. The average elevation of Japan is 438 meters above sea level, the air pushed has a thickness of at least 11,500 meters, and an area of 373663656589428.40 square meters (pi*10906000^2).

Mass = 2.92*10^18 Kilograms of Air

Now we just need to find the speed of the winds, which were stated to be "strong". The wind reached America a few days after the battle, let's say 2 days, or 172800 seconds:

Speed = 9723620/172800 = 56.27 m/s

Strong stuff indeed, probably too strong, but let's continue.

Finally we can the kinetic energy of this feat.

Energy = 1/12*2920000000000000000*56.27^2 = 770469472333333333333.33 Joules

Giving us a grand total of... 184.14 Gigatons.
I don't know what I cooked but it got burned some way through.
Click to expand...
Isn’t “few” typically used for 3-4? Not 2?
 
It's being high-balled on purpose, but the calc isn't finished, I forgot to apply the Inverse Square Law.

I will be using TheRustyOne's formula shown here, which I don't even fully understand.

Air Radius = 7835000 m

Air Area = (pi*7835000^2) = 192853655084263.69 m^2

Shockwave Radius = 7835000 m (Should at least be the same as the air dispersion itself)

I'm assuming the clap produced a shockwave omni-directionally.

Shockwave Area = 4*pi*7835000^2 = 771414620337054.78 m^2

Air Dispersion Energy = 770469472333333333333.33 Joules

Inverse Square Law = area of the explosion/area of the object*the initial value

Final Punch Energy = 771414620337054.78/192853655084263.69*500224129333333333333.33 = 2000896517333333385209.35 Joules or 478.22 Gigatons of TNT (Large Island level)

I expected more to be honest.
 
Last edited:
Therefir said:
Time to make a crazy unpolished high-balled calc, I will just be focusing on the winds.

So as stated on the chapter, the power of Deku's final punch caused winds so strong that they could reach all the way to America even days after the event.

The shortest distance between Japan and Washington, where the reporter is located, is 10,906 kilometers, that will be our radius.

The bulk of the atmosphere is located close to Earth’s surface—up to a distance of around 8 to 15 kilometers, so we will be using 11.5 kilometers for our height.

Having these two values, we can use this calculator to find the mass of air Deku's punch had to push to reach all they way to America. The average elevation of Japan is 438 meters above sea level, the air pushed has a thickness of at least 11,500 meters, and an area of 373663656589428.40 square meters (pi*10906000^2).

Mass = 2.92*10^18 Kilograms of Air

Now we just need to find the speed of the winds, which were stated to be "strong". The wind reached America a few days after the battle, let's say 2 days, or 172800 seconds:

Speed = 9723620/172800 = 56.27 m/s

Strong stuff indeed, probably too strong, but let's continue.

Finally we can the kinetic energy of this feat.

Energy = 1/12*2920000000000000000*56.27^2 = 770469472333333333333.33 Joules

Giving us a grand total of... 184.14 Gigatons.
I don't know what I cooked but it got burned some way through.
Click to expand...
you did your best man
See what you need to do is do a 1 second time frame of a cloud split from Japan to America THEN WE'RE TALKING
 
Therefir said:
It's being high-balled on purpose, but the calc isn't finished, I forgot to apply the Inverse Square Law.

I will be using TheRustyOne's formula shown here, which I don't even fully understand.

Air Radius = 10906000 m

Air Area = (pi*10906000^2) = 373663656589428.40 m^2

Shockwave Radius = 10906000 m (Should at least be the same as the air dispersion itself)

I'm assuming the clap produced a shockwave omni-directionally.

Shockwave Area = 4*pi*10906000^2 = 1494654626357713.63 m^2

Air Dispersion Energy = 770469472333333333333.33 Joules

Inverse Square Law = area of the explosion/area of the object*the initial value

Final Punch Energy = 1494654626357713.63/373663656589428.40*770469472333333333333.33 = 3081877889333333395191.31 Joules or 736.58 Gigatons of TNT (Large Island level+)

I expected more to be honest.
Click to expand...
Now what if it went across the whole earth

How much would it even be then? Would it even be high 6-A?
 
Therefir said:
Time to make a crazy unpolished high-balled calc, I will just be focusing on the winds.

So as stated on the chapter, the power of Deku's final punch caused winds so strong that they could reach all the way to America even days after the event.

The shortest distance between Japan and Washington, where the reporter is located, is 10,906 kilometers, that will be our radius.

The bulk of the atmosphere is located close to Earth’s surface—up to a distance of around 8 to 15 kilometers, so we will be using 11.5 kilometers for our height.

Having these two values, we can use this calculator to find the mass of air Deku's punch had to push to reach all they way to America. The average elevation of Japan is 438 meters above sea level, the air pushed has a thickness of at least 11,500 meters, and an area of 373663656589428.40 square meters (pi*10906000^2).

Mass = 2.92*10^18 Kilograms of Air

Now we just need to find the speed of the winds, which were stated to be "strong". The wind reached America a few days after the battle, let's say 2 days, or 172800 seconds:

Speed = 9723620/172800 = 56.27 m/s

Strong stuff indeed, probably too strong, but let's continue.

Finally we can the kinetic energy of this feat.

Energy = 1/12*2920000000000000000*56.27^2 = 770469472333333333333.33 Joules

Giving us a grand total of... 184.14 Gigatons.
I don't know what I cooked but it got burned some way through.
Click to expand...
Damn… still consistently in the large island ranges… 😭
 
Therefir said:
Time to make a crazy unpolished high-balled calc, I will just be focusing on the winds.

So as stated on the chapter, the power of Deku's final punch caused winds so strong that they could reach all the way to America even days after the event.

The shortest distance between Japan and Washington, where the reporter is located, is 10,906 kilometers, that will be our radius.

The bulk of the atmosphere is located close to Earth’s surface—up to a distance of around 8 to 15 kilometers, so we will be using 11.5 kilometers for our height.

Having these two values, we can use this calculator to find the mass of air Deku's punch had to push to reach all they way to America. The average elevation of Japan is 438 meters above sea level, the air pushed has a thickness of at least 11,500 meters, and an area of 373663656589428.40 square meters (pi*10906000^2).

Mass = 2.92*10^18 Kilograms of Air

Now we just need to find the speed of the winds, which were stated to be "strong". The wind reached America a few days after the battle, let's say 2 days, or 172800 seconds:

Speed = 9723620/172800 = 56.27 m/s

Strong stuff indeed, probably too strong, but let's continue.

Finally we can the kinetic energy of this feat.

Energy = 1/12*2920000000000000000*56.27^2 = 770469472333333333333.33 Joules

Giving us a grand total of... 184.14 Gigatons.
I don't know what I cooked but it got burned some way through.
Click to expand...
The spoiler that I saw said Washington State, not Washington DC. So it'd be 7,835 km, not 10,906 km.
 
Therefir said:
Time to make a crazy unpolished high-balled calc, I will just be focusing on the winds.

So as stated on the chapter, the power of Deku's final punch caused winds so strong that they could reach all the way to America even days after the event.

The shortest distance between Japan and Washington, where the reporter is located, is 10,906 kilometers, that will be our radius.

The bulk of the atmosphere is located close to Earth’s surface—up to a distance of around 8 to 15 kilometers, so we will be using 11.5 kilometers for our height.

Having these two values, we can use this calculator to find the mass of air Deku's punch had to push to reach all they way to America. The average elevation of Japan is 438 meters above sea level, the air pushed has a thickness of at least 11,500 meters, and an area of 373663656589428.40 square meters (pi*10906000^2).

Mass = 2.92*10^18 Kilograms of Air

Now we just need to find the speed of the winds, which were stated to be "strong". The wind reached America a few days after the battle, let's say 2 days, or 172800 seconds:

Speed = 9723620/172800 = 56.27 m/s

Strong stuff indeed, probably too strong, but let's continue.

Finally we can the kinetic energy of this feat.

Energy = 1/12*2920000000000000000*56.27^2 = 770469472333333333333.33 Joules

Giving us a grand total of... 184.14 Gigatons.
I don't know what I cooked but it got burned some way through.
Click to expand...
I'll wait until translations come out. I'm sure we can get it higher
 
Therefir said:
Time to make a crazy unpolished high-balled calc, I will just be focusing on the winds.

So as stated on the chapter, the power of Deku's final punch caused winds so strong that they could reach all the way to America even days after the event.

The shortest distance between Japan and Washington, where the reporter is located, is 10,906 kilometers, that will be our radius.

The bulk of the atmosphere is located close to Earth’s surface—up to a distance of around 8 to 15 kilometers, so we will be using 11.5 kilometers for our height.

Having these two values, we can use this calculator to find the mass of air Deku's punch had to push to reach all they way to America. The average elevation of Japan is 438 meters above sea level, the air pushed has a thickness of at least 11,500 meters, and an area of 373663656589428.40 square meters (pi*10906000^2).

Mass = 2.92*10^18 Kilograms of Air

Now we just need to find the speed of the winds, which were stated to be "strong". The wind reached America a few days after the battle, let's say 2 days, or 172800 seconds:

Speed = 9723620/172800 = 56.27 m/s

Strong stuff indeed, probably too strong, but let's continue.

Finally we can the kinetic energy of this feat.

Energy = 1/12*2920000000000000000*56.27^2 = 770469472333333333333.33 Joules

Giving us a grand total of... 184.14 Gigatons.
I don't know what I cooked but it got burned some way through.
Click to expand...
In the leaks reports says that the winds are "Still strong"
Implying that the wind have been there for a while now.
 
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