MCU: Spider Man Truck Catch Calc Addition

[KingTempest]

Spidey has a canon lifting strength feat that needs no scaling, catching a 3000 lbs truck at 40 mph.
Although it's not class 100 like his current feat, can it be added to his profile for support?
At least Class 100 (Stopped and held a jetbridge and easily pulled down a crane. Very casually stopped a 3000 pound speeding truck moving at 40 mph)

 

[Dalesean027]

Yeah I agree with this it's simple and sensible

 

[It_is_i_wyatt]

sure

 

[KLOL506]

Spidey has a canon lifting strength feat that needs no scaling, catching a 3000 lbs truck at 40 mph.
Although it's not class 100 like his current feat, can it be added to his profile for support?
At least Class 100 (Stopped and held a jetbridge and easily pulled down a crane. Very casually stopped a 3000 pound speeding truck moving at 40 mph)

I calculated that, it's not a 3000 lb truck, it's a VW Polo IV from 2006, I did the math, doesn't wield much in the face of LS feats.

The car itself shouldn't weigh that much unless it's absolutely loaded, but given Tony's statement and the fact that the average American weighs much heavier than the rest of the world (20 kilos more), and that it's a robbery, chances are these peeps are at least quite heavy, have body armor on, gear and stolen goods which could easily increase the weight to 3000 lbs. Fair's fair. Spidey held up a Hyundai SUV with his webs too (The webs don't amplify his LS, they just act as a tether to hold onto shit, akin to a rope attached to a tyre).

Spidey stops the car within a second. 2.58-3.58 seconds.

Acceleration= (final velocity-initial velocity)/time taken in seconds, velocity being in m/s.

40 mph is 17.8816 m/s

Acceleration= (0-17.8816)/1= -17.8816 m/s^2 deceleration

No negatives allowed, so it's 17.8816 m/s^2.

F= mass * acceleration

3000 lbs is 1360.777 kg.

F= 1360.777 * 17.8816= 24332.8700032 Newtons or 2481.26220506 kgf (Class 5)

 

[Emirp sumitpo]

(Class 5)

Ouch