It's a Calc Stacking?

[The_Causality]

Summary:

• the Characters (A) make a linear beam to destroy his opponent (B)
• The beam destroy the opponent (the beam was supposed to) and travel 10 Kilometers in 1 second
• after some talk, we discover that B avoided the beam when the beam was in a distance of 1 meters of him and B his now at 10 meters of his previous position

Can we calculate the Speed of the beam (Which traveld 10 Kilometers in 1 Second) for found the speed of the characters who have avoided this? or this count as a Calc Stacking?

 

[Firephoenixearl]

It shouldn't be calc stacking. As it's a flat clear cut calc with 10km in a sec. There are no assumptions. So yes the calc can be used and it's not calc stacking.

 

[LordGriffin1000]

No I don't believe this is calc stacking. So long as you don't use the speed of the beam calc to use for the characters speed for another calc.

I could be mistaken tho.

 

[TriforcePower1]

If the beam was stated to be that fast by characters or if the calc is from the same feat, it's not calc stacking.

If the speed is obtained from different showings, then it is.

 

[Andytrenom]

What others said. This isn't the stacking of calc...

 

[AguilaR101]

If the beam being 10 km/s was a result of a calculation then calculating the latter feat would indeed be calc-stacking.

On the other hand, if the beam is outright stated to be that fast by statements then you can use its speed to calculate the speed of the character who dodged it.

 

[Andytrenom]

@Aguila No. If something is calculated at a certain speed in one scene and the character dodges it in that same scene only, then it wouldn't be calc stacking.

 

[The_Causality]

Ok, Thanks guys

 

[AguilaR101]

@Aguila No. If something is calculated at a certain speed in one scene and the character dodges it in that same scene only, then it wouldn't be calc stacking.

I'm not sure if we're on the same page here, but OP is asking if you can use the calculated speed of the beam to extrapolate and figure how fast the character would be by dodging it. In the scenario OP presented the character who dodged the beam would be 10x times faster than the beam itself, if the numbers presented aren't outright confirmed by statements you'll be using the result of one calc, to bump the numbers of another, which is textbook calc-stacking.

 

[Andytrenom]

It would be calc stacking if the character dodged a random instance of the beam being fired and not the one where it's speed was calculated in the first place.

This is similar to how if a person carries something and runs at superspeed, we can use the result of the calc of the person running at a certain speed on "another" calc of them moving the person at that speed.

 

[AguilaR101]

snip

I got confused but you're right, it's not calc stacking if happened during the same instance it was calculated as they both would have moved a distance within the same timeframe.

 

[Andytrenom]

Yes

 

[AKM sama]

What others said.