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How fast is this thought-process feat?

309
110
Some context:

It involves a short story in a particular verse where the main character(Bert) was being helped by another character(Jack) to find missing numbers in the number line. Jack developed a device which speeds up the thought process when asleep. Bert was able to count to 12,345,893 which took the Buddhist Monk who’s the current holder of the Unaided Counting Holder about 2 years to reach.

Jack hooked Bert’s device up to a quantum computer and by the time he woke up in the morning. Starting from his current count of 12,345,893. Now he’s at 12, 345, 678, 901, 234, 567, 890, 123, 456, 789, 012, 345, 678, 901, 234, 567, 890, 123, 456, 789, 012, 345, 678, 901, 234, 567, 890, 123, 456, 789, 012, 345, 678, 901. (12 duotrigintillion or 12 x 10^99) . I’ll give a high estimate that he was asleep for 24 hours even though the process doesn’t hinder his sleep. If it was a normal sleep then it would be 8 hours.

A character with a help of a device was able to count from 12 million to 12 x 10^99 in a matter of hours(8 hours - min, 12 hours - mid, 24 hours - maximum). How fast would it be?


Source of the story: “2 + 2 = 5” by Rudy Rucker with Terry Bisson

https://imgur.com/gallery/5g13OoJ
 
Some context:

It involves a short story in a particular verse where the main character(Bert) was being helped by another character(Jack) to find missing numbers in the number line. Jack developed a device which speeds up the thought process when asleep. Bert was able to count to 12,345,893 which took the Buddhist Monk who’s the current holder of the Unaided Counting Holder about 2 years to reach.

Jack hooked Bert’s device up to a quantum computer and by the time he woke up in the morning. Starting from his current count of 12,345,893. Now he’s at 12, 345, 678, 901, 234, 567, 890, 123, 456, 789, 012, 345, 678, 901, 234, 567, 890, 123, 456, 789, 012, 345, 678, 901, 234, 567, 890, 123, 456, 789, 012, 345, 678, 901. (12 duotrigintillion or 12 x 10^99) . I’ll give a high estimate that he was asleep for 24 hours even though the process doesn’t hinder his sleep. If it was a normal sleep then it would be 8 hours.

A character with a help of a device was able to count from 12 million to 12 x 10^99 in a matter of hours(8 hours - min, 12 hours - mid, 24 hours - maximum). How fast would it be?


Source of the story: “2 + 2 = 5” by Rudy Rucker with Terry Bisson

https://imgur.com/gallery/5g13OoJ
Considering a liberal temporal constraint of 24 hours (Maximum estimate), a parameter established in excess of conventional circadian rhythms, the convolution of Bert's mental operations beckons nuanced mathematical evaluation. The task involves quantifying the numerical differential between the inaugural and terminal counts, denoted as (12×1099)−12,345,893(12×1099)−12,345,893. This differential reflects the expansive numeric domain spanned during the stipulated temporal interval.

Counting rate=(12×1099)−12,345,89324 hoursCounting rate=24 hours(12×1099)−12,345,893

The calculated difference amounts to 1.2×10991.2×1099, an extraordinary numeric amplitude. Substituting this result into the counting rate expression yields:

Counting rate≈1.2×109924 hours Counting rate≈24 hours1.2×1099

Upon division, the ascertained counting rate approximates 5×10 (To the 97th Power) counts per hour.
 
Considering a liberal temporal constraint of 24 hours (Maximum estimate), a parameter established in excess of conventional circadian rhythms, the convolution of Bert's mental operations beckons nuanced mathematical evaluation. The task involves quantifying the numerical differential between the inaugural and terminal counts, denoted as (12×1099)−12,345,893(12×1099)−12,345,893. This differential reflects the expansive numeric domain spanned during the stipulated temporal interval.

Counting rate=(12×1099)−12,345,89324 hoursCounting rate=24 hours(12×1099)−12,345,893

The calculated difference amounts to 1.2×10991.2×1099, an extraordinary numeric amplitude. Substituting this result into the counting rate expression yields:

Counting rate≈1.2×109924 hours Counting rate≈24 hours1.2×1099

Upon division, the ascertained counting rate approximates 5×10 (To the 97th Power) counts per hour.
Is the rate applicable in the speed tiering?
 
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