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The problem with that is you using the weight of a skyscraper as well.
The Empire State Building is outright stated to being 365,000 tons in a fact sheet. Also the one you using is for a average skyscraper so yeah.
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Common Feat - Destroying a Skyscraper
- Thread starter Agnaa
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The Empire State Building is outright stated to being 365,000 tons in a fact sheet. Also the one you using is for a average skyscraper so yeah.
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How much the Empire State Building weighs means nothing, as I'm just finding the mass ratio of materials to use for a 222,500 ton skyscraper.
All the Empire State Building is being used for, is only the RATIO of materials.
I repeat: ONLY.
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Your calculations just used density and volume of a skyscraper in order to get the numbers for those materials though.
Anyway, I assumed the hollowness was also accounted for as well.
Anyway, I assumed the hollowness was also accounted for as well.
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Because I already had the mass.
I just had to reverse operate density from mass to find volume.
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Also IIRC, ain’t skyscrapers technically have mixed composition as well? I do doubt they are just made out of pure steel or pure concrete anyway.
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What do you think the mass ratios are for...?
The composition of materials of the structure.
1/6 steel, 5/6 concrete
Everything else such as glass and cables is ditto.
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I not blind on that fact as I already technically noticed it.
Anyway, as long as the hollowness of the skyscraper is accounted, it should been fine as I didn’t exactly see that in the calc for it.
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The weight of the skyscraper already accounts for the hollowness in advance. If we went off by volume the mass value would be inflated massively.
You'd still need the weight and volume of the "average skyscraper" to use the ESB's material composition ratio on.
The height of the building itself has nothing to do with the ratio.
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Whenever I look up the mass of the "average skyscraper", I always get 222,500 tons.
Which seems pretty reasonable, and it is what is already used.
I already did the calcs, but I used imperial tons instead of metric tons. So I gotta fix that.
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Ah. Didn't see that.
Well, yeah, change it with metric, then put it on a blog and I'll evaluate it, and call up a few boys.
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You got ninja'd man.
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There, I fixed it to metric.
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I'll make a blog for it in a bit
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I was merely pointing out you using the weights as well. Also this does apply to any buildings IIRC.
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It seems I cause a misunderstanding. The reason why we got the weight is because of a formula used in engineering. I also have to double check in advance to ensure that is the case as well.
Edit: This seems to check out too.
Answer to How can I calculate the weight of the skyscraper? by Hessam Kazemzadeh
How can I calculate the weight of the skyscraper?
Hessam Kazemzadeh's answer: Step.1) calculate the volume of the skyscraper. This can be done by using either: i) (Average floor plan area) x (Height of the tower) or ii) using Google Map tools Step.2) Weight = Weight Density x Volume Here you need to know some rule of thumbs regarding Weight ...
https://www.quora.com/How-can-I-cal...&share=c65dc679&srid=Xiz37&target_type=answer
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Agnaa
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I added the calc, after changing some formatting.
Dereck, since you're here, could you replace the direct Wikipedia links with proper ones? And remove the underscores from any other links in the page? I'm about to head to bed.
Dereck, since you're here, could you replace the direct Wikipedia links with proper ones? And remove the underscores from any other links in the page? I'm about to head to bed.
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I'll check in a few minutes as I just wake up.
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Nope, just close this thread, which neither of us can, also now that this revision is finished we should move to this one.
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'Fraid not.
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Okay. I will close this thread then.
Thank you to everybody who helped out here.
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