Lilltotto diverting from the radius of Candicce
Candicce Head: 21cm - 74px
Screen: 522px
2atan (tan (70/2) * (74/522)) = 7.68547179 degrees
This gives us 1.56 m
Lil Head: 19cm - 94px
2atan (tan (70/2) * (94/522)) = 9.75366755 degrees
This gives us 1.11 m
Now let's find the distance between Lill and Candice
1.56 - 1.11 = 0.45 m
Liltotto was 0,45m from Candicce
Time = (0.45 / 440,000)
Time = 1.0227272727272727272727272727272727273e-6
Movement
Candice: 1.6 m - 32 pixels
Screen: 562 pixels
2atan (tan (70/2) * (32/562)) = 3.09079005 degrees
This gives us 29.65m
Lilltotto: 1.45 m - 90 px
I considered that Lilltotto was 1.45m, since she is much smaller in relation to the other 3
2atan (tan (70/2) * (90/562)) = 8.67832616 degree
This gives 9.55m
29.65 - 9.55 = 20m
Lilltotto moved 20m
Speed = (20 / 1.0227272727272727272727272727273e-6)
Speed = 19,555,555.55 m / s or Mach 57,516
Sub-Relativist +