• This forum is strictly intended to be used by members of the VS Battles wiki. Please only register if you have an autoconfirmed account there, as otherwise your registration will be rejected. If you have already registered once, do not do so again, and contact Antvasima if you encounter any problems.

    For instructions regarding the exact procedure to sign up to this forum, please click here.
  • We need Patreon donations for this forum to have all of its running costs financially secured.

    Community members who help us out will receive badges that give them several different benefits, including the removal of all advertisements in this forum, but donations from non-members are also extremely appreciated.

    Please click here for further information, or here to directly visit our Patreon donations page.
  • Please click here for information about a large petition to help children in need.

2-A's "Above Baseline" standard

Status
Not open for further replies.
Really? No one is arguing. Andy and Kukui both agree with Pritti, who hasn't posted back since her last point over an hour ago.
 
So if there's a general agreement, is there anything else left to do?
 
Pritti agrees with Multiple Multiverse busting being higher than baseline iirc

Kukui says it's not

Not sure about Andy
 
Should 2x2 infinite multiverses be treated as being above baseline? Probably not.

No she doesn't.
 
Overlord775 said:
Pritti agrees with Multiple Multiverse busting being higher than baseline iirc
No. Pritti's main argument is that it depends on how the feat is performed (casually or after a lot of struggle), not by the quantity destroyed.
 
Dragonmasterxyz said:
So basically, the judge for 2-A feats is quality over quantity.
Yep. How casual you perform a 2-A feat and scaling chains above someone who is 2-A should be the only methods used to determine whats above baseline 2-A.

At least thats what me, Sera, AKM and Pritti agree with.
 
If a verse actually establishes multiple sets of multiverses to be harder to destroy than a single one, such as by making one 2-A character incapable of destroying more than one set, then scaling through number of multiverses is fine as well

Apart from that I agree with Kukui
 
I agree with Kukri and the others.

The only other way I'd see scaling 2-As possible is if busting a specific structure "larger/more complex than the multiverse" is treated as a feat as superior to baseline In-Verse, granted, this would still be unquantifiably above it.
 
I haven't had time to actually argue this, but what's the stance on an infinity of infinities type thing? Like a quote I have that says an infinite multiverse Is just an infinitely small part of a much larger and more powerful whole? Is the argument still about this sort of thing as well, or only about non infinite times baseline 2-A?
 
@Woki

If you're talking about a construct that holds infinite^infinite universes (aleph one), it would be High 2-A.
 
Overlord775 said:
Multiverse Simplified
Assuming that each of the spheres is an infinite multiverse, why would destroying only 1 be as good as a feat as destroying all 6 of them ?
Because they are all infinite. Simple as that.

And you are comparing objects of finite sizes within their dimensional plane to infinite ones.
 
Well I have a quote that was ambiguously so, to the point where the char is straight up "at least 2-A, possibly High 2-A" off of it. What would become of the low end?
 
DMB 1 said:
Because they are all infinite. Simple as that.

And you are comparing objects of finite sizes within their dimensional plane to infinite ones.
This would seem to imply 2-B being equivalent to Low 2-C because 123873 infinite universes is the same as 1 via them all being infinity, which does not seem to be the standard currently used.
 
Overlord775 said:
@AKM
No, that's just Infinity^2
My bad. I meant to say infinite^infinite would be High 2-A. I'm pretty sure I didn't word that right in my last comment.
 
AKM sama said:
@Woki
If you're talking about infinite number of multiverses that contain infinite universes each, it would fall under uncountably infinite number of universes (aleph one), which is High 2-A.
I actually asked this question like a year ago and the responses I got from people said it would most likely be just really high into 2-A rather than High 2-A ....iirc.
 
1 High 3-A space vs 300000 ones would be the same, yes.

Low 2-C and 2-B wouldn't because they are both finite in a 4D scale.
 
They don't have to be finite in a 4D scale though. Take timeline feats where time's equated to a dimension in a way that lets individual ones scale to Low 2-C. We don't instantly be like "oh looks like this one timeline is 2-A because that axis is also infinite".
 
Overlord775 said:
Multiverse Simplified
Assuming that each of the spheres is an infinite multiverse, why would destroying only 1 be as good as a feat as destroying all 6 of them ?
Because 6 times aleph null is still aleph null. Even if you raise infinity to any power that is not infinite, it will still be the same.
 
AKM sama said:
Overlord775 said:
Multiverse Simplified
Assuming that each of the spheres is an infinite multiverse, why would destroying only 1 be as good as a feat as destroying all 6 of them ?
Because 6 times aleph null is still aleph null. Even if you raise infinity to any power that is not infinite, it will still be the same.
You do realize that you are saying that 1=6, right ?
 
Yes, aleph null or infinity doesn't follow the rules of finite numbers.

If you denote countably infinite number as Y:

Y + 1 = Y

Y x 500 = Y

Y ^ (any finite number) = Y
 
AKM sama said:
Yes, aleph null or infinity doesn't follow the rules of finite numbers.
Than Aleph Null shouldn't be used

as it clearly defies logic and physic

Saying 1=6 is madness, as it's going against any basic princible of things
 
So I guess by this logic 0.3... going on forever is the same as 0.3... going on forever followed by 4... going on forever because both are infinite even though one set encompasses the other, right?
 
Status
Not open for further replies.
Back
Top