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TheRustyOne

TheRustyOne

VS Battles Calculation Group
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  • Don't DM me for calc evaluations, you can just leave a message here if the Evaluation Thread isn't working for you.
    Godsatoshi23
    View previous comments…
    TheRustyOne
    TheRustyOne
    You shouldn't be using an assumed sized.

    Just fine the size of one of the buildings and use that to find the explosion's size.

    You're going to tell me that at no point does anyone standard near a building so you can measure it?
    BreezeHM
    BreezeHM
    I didn't find anything at first, which is why I went with the Kingdom. I went back to look at the episode and found something plausible. I've updated the calculation
    TheRustyOne
    TheRustyOne
    Left a comment.
    Viott
    TheRustyOne
    TheRustyOne
    I don't feel like that's a good way to get the volume of all the buildings in the area.

    Also, the Gun Devil was only in Japan for 26 seconds. Meaning what you measured couldn't have taken place in 26 seconds since the Gun Devil would've still been in Japan.

    It'd would have to be an unknown amount less than 26 seconds. Considering how fast the devil is shown to be, highly doubt it stood in one area like this for long, nor do I think dividing the destruction by timeframe is an accurate measure of how powerful it is. Did it fly through and shoot like crazy at the same time? Can't be use in that case.

    That's also ignoring how the destruction clearly goes off screen for who knows how long. There weren't a straight line of buildings in that area either, there would've been sidewalks, streets, and alleyways. Personally, I think this destruction is uncalculatable.
    Viott
    can you check this?
    vsbattles.com

    The boxer ap upgrade

    Old Calc : Viktor plays minecraft : 54343825 Joules or 0.012988485899 tons of tnt (9-A) Recalc : The boxer : viktor ap (Recalc) : 90892970,6799 Joules or 0,0217239414 Tons of TNT (9-A) Pulverization should be used instead of V.frag
    vsbattles.com vsbattles.com
    Apex_Predator_GX
    Hi bud. I hope you're safe and happy. I want to thank you for evaluating my Dino Crisis calculation. I really appreciate your help. :)
    NikHelton
    View previous comments…
    NikHelton
    NikHelton
    The character on the left literally slides down this crater, which is written on the page itself (I dropped it in the comments).
    I just found the volume of the crater and applied the fragmentation value to it


    Regarding the second feat, this is what I came up with together with Ugarik and this method is used as an alternative to the earthquake method in cases when it does not fit the criteria of such
    TheRustyOne
    TheRustyOne
    I don't see him sliding down the crater, he just tripped from the ground shaking. I kind of don't see what you see there.

    Look, it's best if you just ask another calc group member about this.

    For the second calc, I'm not okay with evaluating a method I don't fully understand myself. I don't know when I'll look into that method, but not right now.
    NikHelton
    NikHelton
    Shouldn't the "slide" label be enough?

    Thanks for the help anyway

    tWmzMThD24Y.jpg
    LaserPrecision
    I know this is random, but I noticed a small error regarding your calculation here.

    For the radius of the explosion, you divided the width of the screen. However, the explosion reached the PoV from where it originated. To get an accurate radius of the explosion, you'd have to angsize the distance the explosion is from the screen. Fortunately most of the values you already have. So I took the liberty of doing the math here to see what you think. Px scaling is here.

    5493.889•1083/[1103•2•tan(70deg/2)] = 3851.91m radius

    3851.91^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2 = 4593184.695 Tons | 4.593 Megatons

    Not a huge difference obviously. Though it does increase the result a few times.
    LaserPrecision
    LaserPrecision
    I also noticed that the size of the cave is px-scaled incorrectly. Think they mixed up the numbers.

    MHABE.png


    5493.889•1083/[1013•2•tan(70deg/2)] = 4194.13m radius

    4194.13^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2 = 5929405.85728 Tons | 5.93 Megatons
    TheRustyOne
    TheRustyOne
    Px scaling is usually preferred over angular size, which considered to be less reliable.

    The explosion does spread out off screen no matter which way you measure. I don't believe using px scaling is wrong in this case.

    Also, why are you using the explosion for the angular size and not the cave? The px size of the explosion is 1920 and not 1013, making your results much lower.

    5493.889•1080/[1920•2•tan(70deg/2)] = 2206.71186 m

    However, I didn't realize I put down 1103 instead of 1013. That is a mistake and I thank you for informing me of it.
    LaserPrecision
    LaserPrecision
    I get that, but ang sizing measures a completely different axis. The width of the screen is the X-axis, and the camera is the Z-axis. There's a less visible X-axis than there is a Y-axis.

    I used the cave because the explosion started there and propagated towards the screen.

    Either way, glad I could help in some way.
    Emerald
    Hey Rusty, sorry for bothering you
    Do you mind explaining to me why this feat done by Iida is considered an LS feat even though it's a kick?
    vsbattles.fandom.com

    MHA Movies: Lifting Strength

    vsbattles.fandom.com vsbattles.fandom.com
    TheRustyOne
    TheRustyOne
    It does not scale to his LS, I said so on the blog itself.

    I calculated the force because I could, it would at best scale to his engine's thrust power. But that isn't lifting strength at all.
    Emerald
    Emerald
    Aight thanks for answering
    SeijiSetto
    hihi hello
    would you mind taking a look at (1) (2) feats? they basically piggyback off existing ones and just serve to get new values for feats.
    God243
    bro i have a question,if a dude survive to a nuke how does it scale if the nuke is 7B(he is very close to the explosion)?low7C or 7B?
    TheRustyOne
    TheRustyOne
    Based on the information you've given me, there is no way to tell.

    You need to give an exact distance for me to give any detailed answer. Even being 1 m away from the center of the explosive can drastically lower the results.
    Damage3245
    Sorry for the delay Rusty. I've been out pretty much all day, so I won't be able to make my response post till tomorrow morning. Will try to get it up as soon as possible.
    Hagane_no_Saiyajin
    I have a couple of issues with this calc:
    • It a little unclear what's happening exactly happening for the feat, or if the calculation really matches up with what's happening
    • The feat was performed over a time frame of 3 seconds
    • What's to say the centinels were digging through dirt instead of rock? They did kick up a lot of dust from their digging
    • Looking at how close the towers are to the edge, the centinels probably wouldn't have needed to dig that much to make the shield towers fall down
    • This feat happens with Team RWBY is in Atlas, so technically it should only apply to characters' Atlas keys, not Post-Haven keys
    • What's to say that the Centinels instead dig out a torus shape or triagular prism shape or pyramid shape?
    TheRustyOne
    TheRustyOne
    My interest in RWBY on this wiki varies depending on my mood, and I have zero interest right now.

    I have no idea when I'll be interested again.

    Ask someone else.
    Hagane_no_Saiyajin
    Hagane_no_Saiyajin
    Well, it's your calc, your responsibility, I've also posted these issues on the Calc Discussion Thread, and I might as well post them on the Ruby discussion thread too
    TheRustyOne
    TheRustyOne
    Not it isn't, stop trying to force me to do what you want. You don't need my opinion or thoughts if you want remove/change my calculation.

    I have zero interest in RWBY as of now. You just need another calc group member's opinion, maybe even the one who evaluated it.

    I will not be responding to this again, I'm respectfully asking you not to bother me on this topic again.
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