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Thanks
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Undead Unluck Discussion Thread
Arkenis
They/Them- 17,083
- 7,874
- Thread starter
- #402
Top Runs Around Earth
vsbattles.fandom.com
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Would it be viable to scale spring and unbreakable to Top's feat?
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I’m still confused on what you mean by spring losing to I change. Do you mean Andy and Billy’s amp attack?
spring got slashed by that attack but top did less damage and broke his leg. He was using i breakable to amp his force.
Arkenis
They/Them- 17,083
- 7,874
- Thread starter
- #406
When he hit spring we don't know if that was Top's max speed like he had against Creed, Top also was greatly assisted with hurting Spring with Rip's blade so its not really his feat or Rip's. And what I mean by unchange beating spring is that Unchange is what hurt Spring. Andy's blade can't actually hurt Spring, only the fact unchange makes things unchange is what allowed them to slice through Spring.
Arkenis
They/Them- 17,083
- 7,874
- Thread starter
- #407
Also noticed this, untouchable is pushing against the staff and Victor is also blasting it with energy yet its not breaking or cracking. So it should scale though since Feng is the one likely applying most of the power here and it seems billy and tella are helping it could apply to all three of them.
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My logic is, tops leg broke. But didn't break from the kick against Creed. I would assume he hit with more force because of it.
Ah I see, so you're saying he bypassed his durability because of unchange?
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Why not just have it listed as a combo attack. Kinda how Alita from battle angel alita assisted in creating a black hole even though she doesn't scale to it on her own?
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It should scale in the profile, that attack can't cut through anything. Otherwise they'd have done it against God.
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Staff? I was referring to Andy slicing him in half.
Arkenis
They/Them- 17,083
- 7,874
- Thread starter
- #415
dude all I’m saying is that unchange is what actually allowed them to cut through spring not that its a combo attack or any other random shit. And I brought up the staff cuz thats what im scaling unchanged above. Starting to think unchange should just be 7-B since its just above the staff
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Unchange is a hax. It would scale with the user.
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All he did was made it so that the blade didn't change, but Andy was the one swinging the blade with his technique. If Andy wasn't strong enough he wouldn't have been able to pull it off.
Arkenis
They/Them- 17,083
- 7,874
- Thread starter
- #419
No, Andy’s blood blade just isn’t strong enough, Andy says this. The thing that made it actually cut through Spring is because of how unchange works, it negates the variation in form thus making it unable to be changed making Unchange that powerful not Andy. Andy scaling to Spring doesn’t work at all.
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Ah I see, I've only read through it once. So without remembering the extra context that makes sense.
Although the way its described it does sound a bit like dura neg.
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Just saw some leaks
looks like sun destroys earth by pushing it into the sun somehow at high speeds. Should be above baseline planet
looks like sun destroys earth by pushing it into the sun somehow at high speeds. Should be above baseline planet
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Re-calc using some of the data from here.These clouds look like wisps, so I'd assume they're cirrus clouds, which have an average height of 1500 meters as per the wiki standards. I'll use the first cloud as an example.
First Cloud Radius = 321.019379845 / 2 = 160.50969 km = 160509.69 meters
Cloud Height = 1500 meters
Cloud Volume = pi * 160509.69^2 * 1500 = 1.21406977e+14 meters^3
Density of Clouds = 1.003 kg/meters^3
Cloud Mass = 1.21406977e+14 * 1.003 = 1.21771198e+14 kg
For the speed, you divide the radius by the time. Judging from the image, this split seemed to happen quickly, so I'll assume a time of 5 seconds.
Speed = 160509.69 / 5 = 32101.938 m/s
The clouds look to have moved directly to the side rather than omnidirectionally, so we can use 0.5 * mass * velocity^2 for KE. However, I'm not 100% sure on this, so I'll also use omnidirectional KE just to be safe, which is (1/12) * mass * velocity^2.
Omnidirectional: (1/12) * 1.21771198e+14 * 32101.938^2 = 1.04574509e+22 Joules or 2.5 teratons; Small Country level (Low 6-B)
Non-Omnidirectional = 0.5 * 1.21771198e+14 * 32101.938^2 = 6.27447054e+22 Joules or 15 teratons; Country level (6-B)
Earth: 12756274m/519 = 24578.6 m/px
- First cloud width: 24578.6*12 = 294943.2
- First cloud length: 24578.6*82 = 2015445.2
- Second cloud width: 24578.6*12 = 294943.2
- Second cloud length: 24578.6*20 = 491572
- Third cloud width: 24578.6*14 = 344100.4
- Third cloud length: 24578.6*37 = 909408.2
- Fourth cloud width: 24578.6*11 = 270364.6
- Fourth cloud length: 24578.6*37 = 909408.2
- Fifth cloud width: 24578.6*12 = 294943.2
- Fifth cloud length: 24578.6*18 = 442414.8
- Sixth cloud width: 24578.6*12 = 294943.2
- Sixth cloud length: 24578.6*68 = 1671344.8
- Seventh cloud width: 24578.6*15 = 368679
- Seventh cloud length: 24578.6*18 = 442414.8
- First cloud volume: 2015445.2*294943.2*1500 = 8.9166279e+14 m3
- Second cloud volume: 491572*294943.2*1500 = 2.1747873e+14 m3
- Third cloud volume: 909408.2*344100.4*1500 = 4.6939159e+14 m3
- Fourth cloud volume: 909408.2*270364.6*1500 = 3.6880768e+14 m3
- Fifth cloud volume: 442414.8*294943.2*1500 = 1.9573086e+14 m3
- Sixth cloud volume: 1671344.8*294943.2*1500 = 7.3942768e+14 m3
- Seventh cloud volume: 442414.8*368679*1500 = 2.4466357e+14 m3
184339.5/5 = 36,867.9 m/s
Now I need the mass of all the clouds put together.
8.9166279e+14 + 2.1747873e+14 + 4.6939159e+14 + 3.6880768e+14 + 1.9573086e+14 + 7.3942768e+14 + 2.4466357e+14 = 3.1271629e+15 m3
Density of clouds: 1.003 kg/m3
3.1271629e+15*1.003 = 3.1365444e+15 kg
KE: 1/2*3.1365444e+15*36867.9^2 = 2.1316615e+24 Joules/509.479 Teratons; Large Country level+ (High 6-B)
Last edited:
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Nice, can you publish this as well?Re-calc using some of the data from here.
Earth: 12756274m/519 = 24578.6 m/px
For the depth, I'll use 1500 meters as used in the calc above. Rectangle volume formula is LxWxH
- First cloud width: 24578.6*12 = 294943.2
- First cloud length: 24578.6*82 = 2015445.2
- Second cloud width: 24578.6*12 = 294943.2
- Second cloud length: 24578.6*20 = 491572
- Third cloud width: 24578.6*14 = 344100.4
- Third cloud length: 24578.6*37 = 909408.2
- Fourth cloud width: 24578.6*11 = 270364.6
- Fourth cloud length: 24578.6*37 = 909408.2
- Fifth cloud width: 24578.6*12 = 294943.2
- Fifth cloud length: 24578.6*18 = 442414.8
- Sixth cloud width: 24578.6*12 = 294943.2
- Sixth cloud length: 24578.6*68 = 1671344.8
- Seventh cloud width: 24578.6*15 = 368679
- Seventh cloud length: 24578.6*18 = 442414.8
To get the speed, I'm going to take the radius of the large cloud split width and assume all of them were split at the same speed. The largest radius of a split we got was 184339.5 meters. Since the feat happened in one panel, and it was assumed in the og calc, I'll assume 5 seconds.
- First cloud volume: 2015445.2*294943.2*1500 = 8.9166279e+14 m3
- Second cloud volume: 491572*294943.2*1500 = 2.1747873e+14 m3
- Third cloud volume: 909408.2*344100.4*1500 = 4.6939159e+14 m3
- Fourth cloud volume: 909408.2*270364.6*1500 = 3.6880768e+14 m3
- Fifth cloud volume: 442414.8*294943.2*1500 = 1.9573086e+14 m3
- Sixth cloud volume: 1671344.8*294943.2*1500 = 7.3942768e+14 m3
- Seventh cloud volume: 442414.8*368679*1500 = 2.4466357e+14 m3
184339.5/5 = 36,867.9 m/s
Now I need the mass of all the clouds put together.
8.9166279e+14 + 2.1747873e+14 + 4.6939159e+14 + 3.6880768e+14 + 1.9573086e+14 + 7.3942768e+14 + 2.4466357e+14 = 3.1271629e+15 m3
Density of clouds: 1.003 kg/m3
3.1271629e+15*1.003 = 3.1365444e+15 kg
KE: 1/2*3.1365444e+15*36867.9^2 = 2.1316615e+24 Joules/509.479 Teratons; Large Country level (High 6-B)
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I was hoping someone else could. It's getting a bit late where I am. Anyone willing to blog it has my permission to copy and paste into a blog. Just be sure to credit me if so (If no one does it by tomorrow, I'll do it myself, but I think someone'll do it before then).
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I would but idk how, I'm a bit of a wiki rookie even though I've been here so long lol
Spinoirr
He/Him- 16,145
- 9,110
I can probably do it in the morning on my laptop
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I believe Arkenis has experience with making blogs. Or was it someone else here? Either way, I think they could prolly manage it if it's trouble for ya'll.
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I'll send it here, and I'll have someone evaluate it.
https://vsbattles.fandom.com/wiki/User_blog:LaserPrecision/Undead_Unluck_cloud_splitting_feat_recalc
https://vsbattles.fandom.com/wiki/User_blog:LaserPrecision/Undead_Unluck_cloud_splitting_feat_recalc
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Actually, realized that since I'm not well versed in the verse, it would be better if someone else put it in calculation evaluation since I wouldn't know the priority or characters really involved in the feat and who it scales to, etc.
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I feel like a lot of the calcs we've done doesn't scale to many people... are we sure almost no one scales to the character who did the feat?
Arkenis
They/Them- 17,083
- 7,874
- Thread starter
- #432
Most the calcs don't scale physically to the characters lol. This calc in particular would literally scale to zero people since no one blocked this and he also never goes that speed again. the priority? its not too important of a calc but it just helps upscale the high tiers ig.
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If it's a character a lot of people scale to, they would scale physically. But ONLY under the condition that when fighting someone he's stated to fight at full strength. The speed part is irrelevant, he doesn't need to always be moving at that speed for other people to scale since his durability should scale to that speed for him to
1. Survive the pressure from running at that speed
2. His feet don't instantly turn into red paste from hitting the ground with that much kinetic energy
For his feet to not literally explode from generating that much KE from running would mean his durability has to scale. Thus characters who can harm him past that point in the series should scale.
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No that's not right, top would scale to the calc since he did the feat.
Spring should scale since top kicked him and then top broke his leg from the kick. So it should have had more force.
Spring should scale since top kicked him and then top broke his leg from the kick. So it should have had more force.
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Was tops armor needed to safely achieve these speeds?
He used unbreakable to amplify his kick against Spring.
Arkenis
They/Them- 17,083
- 7,874
- Thread starter
- #440
Ok please be serious, what do you genuinely think the armor is for? The armor is being used as a means for Top to not be destroyed due to him going near the speed of light. This is why the armor notifies him that he's gonna reach a speed at which the armor's integrity breaks down cause at that speed it can't withstand the energy it's built up. This is also why I do not think when he kicked Spring he was at his max speed.
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