If you were to physically strike a star which moved it at FTL speeds, why would it still be Star level and not something like Solar System (given how it goes 4-B once it reaches around 90% SoL from what I saw)? It wouldnt really make sense for something to go baseline if it surpasses the speed of light, even if the values get wacky past that, it would regardless be higher than it was when it was moving at 90% SoL, so we could just assume 99% SoL if it goes at FTL speeds from a physical strike.
Let's follow that reasoning to its logical conclusion.
If we say if it was moving FTL it should be higher than when it was moving with 90% of the speed of light, because of the fact that being faster should be higher, than the same should apply to any other KE value reached if it moves slower than light speed.
If it applies to 90% for that reason, then there is no reason it wouldn't also apply to 99% via the same line of argumentation. In fact, it would also apply to 99.9% of the speed of light given that argumentation. As well as for 99.99%, 99.999%, 99.9999% and so on. As long as it's not faster than light and the FTL body is faster than it, the object should have more KE, right? That's the argument we are making here.
Now the usual KE formula of 0.5*m*v^2 is only a simplification. As we know for more than a hundred years by now, in reality the formula for kinetic energy is
m*c^2 ((1/sqrt(1-(v/c)^2)) - 1)
where v is the velocity of the object, m is the mass and c is the speed of light in vacuum.
What happens if we make v approach c? That's what we are doing if we take percentages ever closer to 100% of the speed of light after all. Well, in that case (v/c) approaches 1. In that case (v/c)^2 also approaches 1. In which case 1-(v/c)^2 approaches 0. In which case sqrt(1-(v/c)^2) approaches 0. In which case (1/sqrt(1-(v/c)^2)) appraoches infinite. In which case m*c^2 ((1/sqrt(1-(v/c)^2)) - 1) also approaches infinite.
What this means is that you can choose some arbitrary amount of energy, say 2.825*10^92 Joule (That's baseline universe level), and you will find some speed value less than the speed of light for which an object of your choice going that fast would have more kinetic energy than that value. E.g. if a 1 kg object moves with sqrt(1-((3*10^92/299792458^2+1)^(-2))*100)% of the speed of light (that percentage is very very close to 100, but not quite) then the object in question would have universe level amounts of energy.
So if you are saying that any FTL object should be considered to have more KE than itself going at any speed less than the speed of light, what you are saying is that all FTL KE should be universe level (or in fact infinite). That we can't realistically make everyone with a FTL KE feat 3-A/High 3-A should be clear, though.
So that argument can't work.
Also, another question: if hitting a star causing it to move at FTL speeds a little distance required many people to move it, would dividing the speed by the number of people work, since it is like them affecting their individual strength? I asked that because of a certain feat I saw where it took 5 people to move it a little at that speed by jumping.
No. You would need to divide the energy by 5, not the speed. Dividing the speed by 5 wouldn't even work for not FTL KE.
