Formula for kinetic energy under water?

[TheJ-ManRequiem]

Example, the character in question throws something with enough force to reach a speed of 300m/s and hit 5,000,000,000,000joules.

The character then does the same thing underwater, the object hits 300m/s and the object weighs the same, but it cant be 5,000,000,000,000joules, water is far denser and thicker than air.

So what would ya mutiply the original result by for the new result? What do ya factor in for the fact it happened under water. ?

 

[Golden_Void]

"Perhaps this is related to viscosity by any chance?

Viscosity of water = 8.90e-4 Pa*S or kg/(m*s)


Viscosity of air = 1.81e-5 kg/(m*s)


This means that water provides 49.17 times more resistance to air, thus to move in the same speed in water compared to air, you would need about (49.17^2) times more kinetic energy to do so.

This would also explain why bullets slow down immensely when fired underwater compared to being fired in the atmosphere. Someone needs to check however."

 

[TheJ-ManRequiem]

So can i do the calc normally then simply multiply the result by 49.17?

 

[Golden_Void]

I'm unsure, I'm checking it out.

Also, 49.17^2