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Assuming that the entire human population on earth decided to stand together and form a massive group, how much energy would it take to destroy all of them in one move? (Sub-atomic Destruction)
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Energy required to kill off the human population
- Thread starter ArbitraryNumbers
- Start date
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- Tags
- calculations
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High 6-A feat, eh? Aite. *Nods*
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Actually no, scratch that, the values for that are already here https://vsbattles.fandom.com/wiki/Calculations
Which says the actual value for sub-atomic destruction is 1.114e13 per kilogram
Which means the value is (7e9*70*)1.114e13= 5.4586e24 joules or 1.3046367112810707 petatons
a High 6-B feat.
Which says the actual value for sub-atomic destruction is 1.114e13 per kilogram
Which means the value is (7e9*70*)1.114e13= 5.4586e24 joules or 1.3046367112810707 petatons
a High 6-B feat.
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Very high end, eh? Eh, fair enough.
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So, to erradicate the whole human population to the point that no human is around, 1.3 exatons are needed?... wow, that would indeed destroy the planet, not blow it up but make it unable to sustain life
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Hm. How powerful was the impact of the asteroid that wiped out the dinosaurs?
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Well only with Sub-Atomic destruction. Normal destruction would be much lower.
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Does the Chicxulub Impact Event not count? @All
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Oh didn't know we had a profile for that. Cool.
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CrossverseCrisis said:
He asked for sub atomic destruction tho, the actual energy needed to kill a person is considerably much lower than that.
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100 teratons, aka only 0.0001 exatonsLordAizenSama said:
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- Thread starter
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Okay, thanks guys. So the power it would take to kill of the humans would be High 6-B.
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^Yup.
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