I find it very difficult to use vs battles to tell whose more powerful than who since so many characters are 1A. This site is making it out to be that Adam Kadmon is one of the most powerful second to only the Axiom. But… isn’t he defeated by the end of P5 royal? Adding on to this, where do P2 characters fit in all of this? Is Tatsuya > Makoto > Ren a valid assertion?
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Does Ren scale higher than Adam Kadmon?
- Thread starter Musclestichfan1030
- Start date
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Some people are talking about potentially indexing scaling chains but as of right now idk, I know nothing about persona
TheKingStrategist13
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1. Ren does not scale above Kadmon, he needed assistance to defeat him and used a weak spot to circumvent Kadmon's ludicrously higher Dura
2. P2 Characters from my knowledge have outdated profiles. That being said, (Personal Interpretations aside that make me think Makoto is the strongest), the current chain for the Protag's from what I last recall is Ren>Makoto>Yu>Tatsuya>Naoya
I could have gotten something wrong in the chain, but I vividly remember Tatsuya being weaker than Makoto, and Ren being the Strongest according to the sites current scaling and how they interpret the characters.
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TheKingStrategist13
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Also, this should be in the Questions and Answer's category
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The Phantom Thieves' win against Adam Kadmon was largely conditional and hinged upon them exploiting a specific weakness. The Phantom Thieves are only able to superficially damage and barely withstand attacks from AK beforehand, meaning they're only marginally comparable (if not weaker) than the primordial man physically.
The scaling chain for the protagonists is:
Third Semester Joker > Tatsuya Suou & Maya Amano > Makoto Yuki > Yu Narukami >=(?) Naoya (I'm unsure about his placement, since P1 scaling is scarce.)
TheKingStrategist13
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Hm, Guess I was wrong then. (Though I do wonder what put's the P2 Protags there...)
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Defeating Philemon and Nyarlathotep's full-powered, true forms.
TheKingStrategist13
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Ah. I see... That, does remind me of a not so enjoyable debate I had about that. Regardless, thank you for the further clarification.
