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The atmosphere ends at 100 KM, the moon is 384,400 KM away, meaning it travelled 384,300 KM
divided by 50 minutes, and then dividing that by 60 seconds is 1281 KM per second, 1281000 meters per second, Mach 3734.69387755, Massively Hypersonic+
When you make a explosion that destroys the planet you are on and the moon, is it impressive if it reachs the moon or the fact it blew up the Moon and planet?
So the explosion reachs all the way to the moon and destroys the planet and moon is Large planet level and blowing up the moon and the planet (same size as earth) is just planet level?
Dose this also take in affect the planet sized as earth also getting blown up at the epicenter? Also did you count the area of the explosion because I don't see that
Considering that earth's circumference is 40075000 meters, sending it spinning at 440,000 meters per second would be 0.50599747474 Degrees per second, which is 0.008831321940967932 Rads
Now, we need to find Earth's moment of inertia, which is (1/3) * mass * length in meters^2. In this case, Earth's Mass is 5.972e+24 kilograms, and it's diameter, and thereby length, is 12,742,000 meters.
(1/3) times 5.972e+24 times 12,742,000^2 is 3.2320178e+38
RKE is Moment of Inertia times .5 times rads per second^2, so, 3.2320178e+38 * 0.5 * 0.008831321940967932^2 is....
1.2603617e+34 Joules, 3.01233665503 Yottatons, Large Planet level
(Following, now. I can potentially run some calcs here in the future.)
@Spinoirr Admittedly, calculating the second one would be slightly easier if I knew how wide that wave of ice spikes was. Can I assume it's traveling outwards in a cone from the point of origin? Or is that first picture meant to demonstrate how wide the attack is?
Now, another question. Are these spikes just being created from nothing, and pulled up from under the earth? Or is the attacker in this instance actually freezing water in the air or something of the sort?