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Calculation Requests II

The atmosphere ends at 100 KM, the moon is 384,400 KM away, meaning it travelled 384,300 KM

divided by 50 minutes, and then dividing that by 60 seconds is 1281 KM per second, 1281000 meters per second, Mach 3734.69387755, Massively Hypersonic+
 
I expected a higher result, but I want to try and calc a speed feat

Just that it took 6 seconds to travl that far

So how do i do that?

Like this?

384,300 ├À 0.6
 
If it's 6 seconds dividing by 6 will get you per second
 
High (when I am using the minimum distance to our Moon) - 349900 km ├À 6 = 58316.666 ├À 6 = 9719.444444444444 km per second

Now whats that?

Low (when i use the normal distance from the moon) - 384,300 km ├À 6 = 64.05 ├À 6 = 10.675 km per second
 
... huh

It's 384,300 km ├À 6 equals 64050 KM per second, which is 64050000 meters per second, 0.21364955468c
 
When you make a explosion that destroys the planet you are on and the moon, is it impressive if it reachs the moon or the fact it blew up the Moon and planet?
 
It blowing up the moon gets high with Inverse Square Law
 
So the explosion reachs all the way to the moon and destroys the planet and moon is Large planet level and blowing up the moon and the planet (same size as earth) is just planet level?
 
ughh

Surface area is 4*¤Ç*radius^2, which we need to see to the energy distribution

Moon is 384,400,000 meters away

4*¤Ç*384,400,000^2 is 1.8568491e+18 meters

To see how much of the total energy the moon is taking, we find it's surface area. It's radius is 1737100, so, 4*¤Ç*1737100^2 is 3.791923e+13.

1.8568491e+18 divided by 3.791923e+13 means the explosion would be 48968.5339075 times more powerful at the epicenter

The Moon's GBE is 1.24x10^29, so times 48968.5339075 is....

6.0720982e+33 Joules, 1.45126630127 Yottatons, Planet level+
 
Dose this also take in affect the planet sized as earth also getting blown up at the epicenter? Also did you count the area of the explosion because I don't see that
 
What tier is making a planet spin around like a beyblade by brute strength,if any speed is needed on how fast it spins here,spinning at FTL speeds
 
You can't use FTL KE

once you go faster then light, the mass actually decreases, and generally cannot be calculated
 
Alright

Considering that earth's circumference is 40075000 meters, sending it spinning at 440,000 meters per second would be 0.50599747474 Degrees per second, which is 0.008831321940967932 Rads

Now, we need to find Earth's moment of inertia, which is (1/3) * mass * length in meters^2. In this case, Earth's Mass is 5.972e+24 kilograms, and it's diameter, and thereby length, is 12,742,000 meters.

(1/3) times 5.972e+24 times 12,742,000^2 is 3.2320178e+38

RKE is Moment of Inertia times .5 times rads per second^2, so, 3.2320178e+38 * 0.5 * 0.008831321940967932^2 is....

1.2603617e+34 Joules, 3.01233665503 Yottatons, Large Planet level
 
(Following, now. I can potentially run some calcs here in the future.)

@Spinoirr Admittedly, calculating the second one would be slightly easier if I knew how wide that wave of ice spikes was. Can I assume it's traveling outwards in a cone from the point of origin? Or is that first picture meant to demonstrate how wide the attack is?
 
First image is how wide the spikes are and you are Right, they make the first ice spikes and then make that giant ice attack
 
Now, another question. Are these spikes just being created from nothing, and pulled up from under the earth? Or is the attacker in this instance actually freezing water in the air or something of the sort?
 
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