speedster352
He/Him- 17,545
- 1,788
So why not?
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Let me guess outlier? Can’t it at least give Thor likely far higher for durability?Because.
Share scanSo why not?
Bro, he barely survives, but I am neutral, I am more interested in why it is an outlier.
The 50K kelvin temperature wields Low 7-B, and we don't take heat like that to accumulate over time to large numbers, it'd just be endurance. Also the Low 7-B value is taken in one second, which we all know Thor was not remotely harmed by, it took minutes to bring him near death.
No clue, I don't watch mcu. Thought it was funny.Let me guess outlier?
Because a lot of characters can harm himBro, he barely survives, but I am neutral, I am more interested in why it is an outlier.
Here is the featNo clue, I don't watch mcu. Thought it was funny.
As a general reminder, in the future, add a bit more context to the question. Like mention a feat or something. Would make it easier to answer for others.
Can it be used for LS? I mean he took the full force of a star and remained in that position for a while?
Why would staying in front of an energy beam be LS?Can it be used for LS? I mean he took the full force of a star and remained in that position for a while?
The beam is also the full force of a starWhy would staying in front of an energy beam be LS?
And what might be the "full force of a star" then since you believe that it's pushing Thor with a lot of force?The beam is also the full force of a star
Son of a bitch, wasn't it 3 million degrees or something?
Be civil on threadsSon of a bitch, wasn't it 3 million degrees or something?
No, those might be previous assumptions before the 50K thing was found IIRC from a guide book.Son of a bitch, wasn't it 3 million degrees or something?
The 50,000K beam might be lower than Low 7-BSurface: The surface of the sun has a temperature of 5,773.2K.
3470*62*5773.2 = 1.242046248E+9J
That is Building Level.
Core: The core of the sun has a temperature of 15,700,000K.
3470*62*15 700 000 = 3.377698E+12J
That is Multi-City Block Level+.
I have already calculated it and it is 6-CReferences for Common Feats
Throughout fiction and real life, there have been numerous feats demonstrating a certain character's or object's destructive power. This page's purpose is to consolidate calculations for those feats for better convenience in determining an object's or character's Attack Potency or Durability...vsbattles.fandom.com
The 50,000K beam might be lower than Low 7-B
And? Has your calculation been accepted by anyone other than yourself?I have already calculated it and it is 6-C
What would the LS be?I have already calculated it and it is 6-C
Yes that can be used for LSAnd what might be the "full force of a star" then since you believe that it's pushing Thor with a lot of force?
How can you calculate the energy beam's force pushing Thor then?Yes that can be used for LS
Sorry to burst your bubble but that's 0.0000000000000023096 JoulesAhm, 50k kelvin is literally a large star temperature?
Also, I calculated it and I get 6.9032E-19 which is (6-C Island)
Ask a calc group memberHow can you calculate the energy beam's force pushing Thor then?
You ask it since you're the one who keeps insisting it's a LS feat, when no other person has, supporter or otherwise.Ask a calc group member
WAIT, I AM SORRY I DID NOT SEE MINUS…Sorry to burst your bubble but that's 0.0000000000000023096 Joules
6.9032E-(negative) 19
WAIT, I AM SORRY I DID NOT SEE MINUS…
Bruh you wouldn't get anything out of Tier 6 even if you used the average neutron star temperature of 1 million kelvin or something.
Bruh you wouldn't get anything out of Tier 6 even if you used the average neutron star temperature of 1 million kelvin or something.