What tier would be breaking down a door?

[Arceus0x]

Specifically a front door from the outside

 

[DaMonkeMan]

Wall level (I know literally nothing about AP I'm just guessing)

 

[Arceus0x]

yeah thats 9-B wall

Why

 

[Flashlight237]

Specifically a front door from the outside

Working on that right now. So far, I got 10.1 cm for the door pin and door hinge lengths, and 1 inch for the deadbolt length for my own front door.

 

[Flashlight237]

Specifically a front door from the outside

Okay, so the latch contact area, latch surface area, latch contact volume, hinge thickness, and pin diameter are all the same from this: https://vsbattles.fandom.com/wiki/U...n_Feat:_Pounding_a_Closed_or_Locked_Door_Open

Spoiler: Prerequisites

Unlike the door used in my blog, which is an inside residential door, the front door has a deadbolt. Just from this added factor alone, right of the bat this feat is Street Level.

There is one new item: a deadbolt. That and the pin length and hinge lengths are different, which will lead to different surface area and volume measurements. The hinge length is 10.2 mm and would also translate to the pin length (mind the pop part where there's a ledge; that's the head of the door pin, which isn't included).

The deadbolt has a length of 7/8 of an inch (2.2225 cm). The door's gap is 3.5 mm based on what I can tell, giving the deadbolt's contact area of 1.8725 cm in length. As for the deadbolt? Well... https://prnt.sc/ArW4z-C0SFYE

It had a scale of 1.9 cm=651 px. Using the Histogram feature on GIMP and the Pen Tool (select with path used) gave me a surface area of 311090 square pixels: https://prnt.sc/n2hiNwkRT695

Spoiler: Breaking the Door Open

Under the scale, we got the following...

Area of Deadbolt: 311090 square pixels
Pixel Length: 1.9/651=0.00291858679 cm
Pixel Area: 8.518148848*10^6 cm²
8.518148848*10^6*311090=2.6499109251747 cm²

Add in our previous surface area for the latch and we got... 1.33320845368+2.6499109251747=3.9831193788547 cm²

Now for this next part. We'll need to determine how much force is needed to force the door open without turning the knob, no hinges removed. Brass goes from 205 to 531 MPa in terms of shear strength: https://www.matweb.com/search/datasheet_print.aspx?matguid=d3bd4617903543ada92f4c101c2a20e5

Let's see the force needed.

(3.9831193788547/10000)*205000000=81653.9472665 newtons

(3.9831193788547/10000)*531000000=211503.639017 newtons

Now for the distance. This time, I'll need to use the width of the deadbolt, as this time, the deadbolt is what needs to be broken in order to get the door to slide open freely. I got a width of 562 px for the deadbolt. Let's see how long that is.

562/651*0.019=0.01640245776 meters

Now, let's determine how much energy is needed just to bust the door open.

81653.9472665*0.01640245776=1339.325421 joules

211503.639017*0.01640245776=3469.179504 joules

So 1339.325421 to 3469.179504 joules just to break the door open. Firmly Street Level like I expected. Damn!

Now let's get to the part where we actually bust the door down.

Spoiler: Busting The Door Down

As with the linked blog before, the latch volume remains the same at 0.315 cm³

The door hinges (as well as the door pins that are covered by them) are longer this time, at 10.2 cm. Let's see what the door pin volume is.:

(0.6/2)²*π*10.2=2.883982056 cm³

Now, for the hinges. Same principles as in the blog, only the length is bigger.:

0.002*0.102*2=4.08*10^-4 m³

The tensile strength of brass is 467.7 to 500.6 MPa: https://www.researchgate.net/figure...f-extruded-brass-powder-alloys_tbl1_269453236

As the hinges will be pulled (or in this case pushed) outwards, I'll be using tensile strength for them.

Last comes the deadbolt. The surface area is determined, so now it's a matter of multiplying the height into the value I got (basically from the end of the deadbolt to the part where the door gap starts).:

2.6499109251747*1.8725=4.961958207 cm³

Now, let's get calcin'!

Low End

4.08*10^-4*467700000=190821.6 newtons*0.006=1144.9296 joules*3 hinges=3434.7888 joules (Hinges)

2.883982056*205=591.2163215*3=1773.648964 joules (Door Pins)

0.315*205=64.575 joules (Latch)

4.961958207*205=1017.201433 joules (Deadbolt)

3434.7888+1773.648964+64.575+1017.201433=6290.214197 joules (Total)

High End

4.08*10^-4*500600000=204244.8 newtons*0.006=1225.4688 joules*3 hinges=3676.4064 joules (Hinges)

2.883982056*531=1531.394472*3=4594.183415 joules (Door Pins)

0.315*531=167.265 joules (Latch)

4.961958207*531=2634.799808 joules (Deadbolt)

3676.4064+4594.183415+167.265+2634.799808=11072.65462 joules (Total)

So that's 6290.214197 to 11072.65462 joules, which puts the act of breaking a front door down from Street Level to Street Level+! Damn!

So yeah, depending on the circumstances, the feat can be Street Level, upwards Street Level+.

 

[Arceus0x]

Okay, so the latch contact area, latch surface area, latch contact volume, hinge thickness, and pin diameter are all the same from this: https://vsbattles.fandom.com/wiki/U...n_Feat:_Pounding_a_Closed_or_Locked_Door_Open

Spoiler: Prerequisites

Unlike the door used in my blog, which is an inside residential door, the front door has a deadbolt. Just from this added factor alone, right of the bat this feat is Street Level.

There is one new item: a deadbolt. That and the pin length and hinge lengths are different, which will lead to different surface area and volume measurements. The hinge length is 10.2 mm and would also translate to the pin length (mind the pop part where there's a ledge; that's the head of the door pin, which isn't included).

The deadbolt has a length of 7/8 of an inch (2.2225 cm). The door's gap is 3.5 mm based on what I can tell, giving the deadbolt's contact area of 1.8725 cm in length. As for the deadbolt? Well... https://prnt.sc/ArW4z-C0SFYE

It had a scale of 1.9 cm=651 px. Using the Histogram feature on GIMP and the Pen Tool (select with path used) gave me a surface area of 311090 square pixels: https://prnt.sc/n2hiNwkRT695

Spoiler: Breaking the Door Open

Under the scale, we got the following...

Area of Deadbolt: 311090 square pixels
Pixel Length: 1.9/651=0.00291858679 cm
Pixel Area: 8.518148848*10^6 cm²
8.518148848*10^6*311090=2.6499109251747 cm²

Add in our previous surface area for the latch and we got... 1.33320845368+2.6499109251747=3.9831193788547 cm²

Now for this next part. We'll need to determine how much force is needed to force the door open without turning the knob, no hinges removed. Brass goes from 205 to 531 MPa in terms of shear strength: https://www.matweb.com/search/datasheet_print.aspx?matguid=d3bd4617903543ada92f4c101c2a20e5

Let's see the force needed.

(3.9831193788547/10000)*205000000=81653.9472665 newtons

(3.9831193788547/10000)*531000000=211503.639017 newtons

Now for the distance. This time, I'll need to use the width of the deadbolt, as this time, the deadbolt is what needs to be broken in order to get the door to slide open freely. I got a width of 562 px for the deadbolt. Let's see how long that is.

562/651*0.019=0.01640245776 meters

Now, let's determine how much energy is needed just to bust the door open.

81653.9472665*0.01640245776=1339.325421 joules

211503.639017*0.01640245776=3469.179504 joules

So 1339.325421 to 3469.179504 joules just to break the door open. Firmly Street Level like I expected. Damn!

Now let's get to the part where we actually bust the door down.

Spoiler: Busting The Door Down

As with the linked blog before, the latch volume remains the same at 0.315 cm³

The door hinges (as well as the door pins that are covered by them) are longer this time, at 10.2 cm. Let's see what the door pin volume is.:

(0.6/2)²*π*10.2=2.883982056 cm³

Now, for the hinges. Same principles as in the blog, only the length is bigger.:

0.002*0.102*2=4.08*10^-4 m³

The tensile strength of brass is 467.7 to 500.6 MPa: https://www.researchgate.net/figure...f-extruded-brass-powder-alloys_tbl1_269453236

As the hinges will be pulled (or in this case pushed) outwards, I'll be using tensile strength for them.

Last comes the deadbolt. The surface area is determined, so now it's a matter of multiplying the height into the value I got (basically from the end of the deadbolt to the part where the door gap starts).:

2.6499109251747*1.8725=4.961958207 cm³

Now, let's get calcin'!

Low End

4.08*10^-4*467700000=190821.6 newtons*0.006=1144.9296 joules*3 hinges=3434.7888 joules (Hinges)

2.883982056*205=591.2163215*3=1773.648964 joules (Door Pins)

0.315*205=64.575 joules (Latch)

4.961958207*205=1017.201433 joules (Deadbolt)

3434.7888+1773.648964+64.575+1017.201433=6290.214197 joules (Total)

High End

4.08*10^-4*500600000=204244.8 newtons*0.006=1225.4688 joules*3 hinges=3676.4064 joules (Hinges)

2.883982056*531=1531.394472*3=4594.183415 joules (Door Pins)

0.315*531=167.265 joules (Latch)

4.961958207*531=2634.799808 joules (Deadbolt)

3676.4064+4594.183415+167.265+2634.799808=11072.65462 joules (Total)

So that's 6290.214197 to 11072.65462 joules, which puts the act of breaking a front door down from Street Level to Street Level+! Damn!

So yeah, depending on the circumstances, the feat can be Street Level, upwards Street Level+.

Would you be willing to put that in a blog?

 

[Wikisource]

Well, it depends on many factors like door material, hinge strength,...