- 2,460
- 921
We know how dimensional space works, but Jonathan Bowers has descripted super dimensions, trimensions (sic!) and etc. Here's the description (find it under Extending Array Notation): "Yet one can keep going into higher spaces, higher than dimensional space - consider the tetrational spaces (which includes super dimensions, trimensions, quadramensions, etc.) - what is this exactly - dimensional spaces can be represented as X^n where X represents a line, X^2 would then be a plane, X^100 would be 100 dimensional. Super dimensions are of this order - X^(X^n), trimensions, quadramensions, etc are as follows: X^(X^(X^n)), X^(X^(X^(X^n))), etc. - these kind of arrays are possible - so array notation can be addapted to these arrays, but the rules get trickier. Using Bird's inline technique we can represent super dimensional space as follows: {# (a,b,c,....,k) #} which represents going to the next a'th dimension of the b'th second level of dimensions of the c'th third level of dimensions .... of the k'th n'th level of dimensions - notice this is only super dimensions, it gets crazier in trimensions on up.
But Arrays can go even further - there are also pentational arrays such as an X^^^6 array which would be an X^^(X^^(X^^(X^^(X^^X)))) array where X^^X alone would be an X^(X^(X^(....^(X^X))....)))) array. Bird has attempted to write rules for extending past dimensional arrays and appears to have captured rules that fit tetration and possibly pentation - but they get quite tedious." and here (find the Higher Superdimensional Group): "Higher Superdimensional Group - includes trimentri, trongulus, quadrongulus, and goplexulus. Trimentri = {3,3 (0,0,0,1) 2} which is a size 3 - x^(x^3) array of 3's - it is also a 1 trimensional array = {3,3 ((0,1)1) 2} - in otherwords a size 3 x^x^x array of 3's, a 3 tetrated to 3 array of 3's - a trimension is a dimension of dimension of dimensions. To help see this, let R represent a line (R for real numbers which is graphed like a line) - R^3 = 3 dimensions, R^R = R^R^1 - is 1 super dimension, R^R^4 = 4 super dimensions. R^R^R = R^R^R^1 = 1 trimension. R^R^R = R tetrated to 3 = {R,3,2}. Even though trimentri is defined with trimensions, it's array is of the higher superdimensional sizes. Trongulus = {10,100 (0,0,0,1) 2}, and quadrongulus = {10,100 (0,0,0,0,1) 2} = size 100 - x^x^4 array of 10's. Goplexulus = {10,100 (0,0,0,.......,0,0,1) 2} - where there are 100 0's - this is a size 100 - x^x^100 array of 10's.".
How we should interpret such spaces in our Tiering System? They can have their tier for sure (ex. 1-B)...
But Arrays can go even further - there are also pentational arrays such as an X^^^6 array which would be an X^^(X^^(X^^(X^^(X^^X)))) array where X^^X alone would be an X^(X^(X^(....^(X^X))....)))) array. Bird has attempted to write rules for extending past dimensional arrays and appears to have captured rules that fit tetration and possibly pentation - but they get quite tedious." and here (find the Higher Superdimensional Group): "Higher Superdimensional Group - includes trimentri, trongulus, quadrongulus, and goplexulus. Trimentri = {3,3 (0,0,0,1) 2} which is a size 3 - x^(x^3) array of 3's - it is also a 1 trimensional array = {3,3 ((0,1)1) 2} - in otherwords a size 3 x^x^x array of 3's, a 3 tetrated to 3 array of 3's - a trimension is a dimension of dimension of dimensions. To help see this, let R represent a line (R for real numbers which is graphed like a line) - R^3 = 3 dimensions, R^R = R^R^1 - is 1 super dimension, R^R^4 = 4 super dimensions. R^R^R = R^R^R^1 = 1 trimension. R^R^R = R tetrated to 3 = {R,3,2}. Even though trimentri is defined with trimensions, it's array is of the higher superdimensional sizes. Trongulus = {10,100 (0,0,0,1) 2}, and quadrongulus = {10,100 (0,0,0,0,1) 2} = size 100 - x^x^4 array of 10's. Goplexulus = {10,100 (0,0,0,.......,0,0,1) 2} - where there are 100 0's - this is a size 100 - x^x^100 array of 10's.".
How we should interpret such spaces in our Tiering System? They can have their tier for sure (ex. 1-B)...