Vaporization value of Iron

[Amelia_Lonelyheart]

It's been known for a long time that our vaporization of Iron is either inaccurate or misleading, most likely the ladder. As such, due to the lack of instruction, many people, including me, have mistaken it as the actual value and thus have highly inflated results for calcs in the past.

To help out Medeus in this blog, I attempted to make a calc of it myself following Alakabamm's method of vaporization of Titanium calc.

Here's the calc in full.

Source

Source 2

Iron characteristics

• Density: 7.874 g/cm^3
• Boiling point: 2862 ┬░C
• Heat of fusion: 13,810 J/mol
• Heat of vaporization: 340,000 J/mol
• Molar Heat Capacity 25.10 J/(mol*K)
• Molar Mass: 55.8450 g/mol

Room Temperature: 20 ┬░C (average)

Conversions:

• 55.8450 g/mol > 0.055845 kg/m^3

so:

• Heat of Fusion: 247 j/g
• Heat of Vaporization: 6,088 j/g
• Molar Heat Capacity: 0.4494 J/g*C

(7.874)(0.4494)(6088-20) = 21,472 J

(247)(7.874) + (6,088)(7.874) = 49,881.79 J

49,881.79 + 21,472 = 71,353.79 J

That should be the rough j/cm^3 value for vaporizing Iron.

Any feedback is welcomed.

 

[Js250476]

Seems alright to me

 

[Antoniofer]

Let me check: Using the same process than Alakab, and using this source and this one, I got:

• Iron UMA = 55.845 g/mol
• Iron Boiling Point = 2861 C
• Iron Heat of Fusion = 13.8 kJ/mol = 247.1 J J/g
• Iron Heat of Vaporization = 347 kJ/mol = 6.2136 kJ/g
• Iron Heat Capacity = 449 J/(kg*C)

• Q1 = 7.874*0.449*(2861 ― 20) = 10044.145 J/cc

• Q2 = (247.1 + 6213.6)*7.874 = 50871.5518 J/cc

• Qt = 60915.7 J/cc

 

[Amelia_Lonelyheart]

Well I personally trust you more with this kind of stuff then myself so I'll take your word.

 

[Antoniofer]

You can check if there's any type or missplacing of values, I used the same structure than Alakab's. I not often the heat calcs neither, so mistakes are possible.

 

[Amelia_Lonelyheart]

I'll do a more thorough look over when I get back. Thanks.